/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 A well-designed and safe workpla... [FREE SOLUTION] | 91Ó°ÊÓ

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A well-designed and safe workplace can contribute greatly to increasing productivity. It is especially important that workers not be asked to perform tasks, such as lifting, that exceed their capabilities. The following data on maximum weight of lift (MWOL, in kilograms) for a frequency of 4 lifts per minute were reported in the article "The Effects of Speed, Frequency, and Load on Measured Hand Forces for a Floor-to-Knuckle Lifting Task" (Ergonomics \([1992]: 833-843):\) \(\begin{array}{lllll}25.8 & 36.6 & 26.3 & 21.8 & 27.2\end{array}\) Suppose that it is reasonable to regard the sample as a random sample from the population of healthy males, age \(18-30\). Do the data suggest that the population mean MWOL exceeds 25 ? Carry out a test of the relevant hypotheses using a \(.05\) significance level.

Short Answer

Expert verified
From the hypothesis test, if the calculated t-value is higher than the critical t-value, it would suggest that the population mean MWOL exceeds 25 kg. However, the actual result is dependent on the calculation of the t-value.

Step by step solution

01

Calculate sample mean

First, calculate the sample mean (average) of the five given observations: \( (25.8 + 36.6 + 26.3 + 21.8 + 27.2) / 5 \)
02

Calculate the sample standard deviation

Calculate the sample standard deviation using the formula: \( \sqrt{ \frac{1}{N-1} \sum{(x_i - \bar{x})^2}} \), where \( x_i \) are the data points, \( \bar{x} \) is the sample mean, and N is the number of data points (5 in this case).
03

Set up the hypotheses

The null hypothesis is that the population mean is 25 kg. The alternative hypothesis is that the population mean exceeds 25 kg. So we have: \( H_0: \mu = 25 \) vs \( H_1: \mu > 25 \).
04

Calculate t-value

Calculate the t-value using the formula: \( t = \frac{\bar{x} - \mu_0} {s / \sqrt{N}} \), where \( \bar{x} \) is the sample mean, \( \mu_0 \) is the population mean under the null hypothesis (which is 25 in this case), s is the sample standard deviation, and N is the number of data points.
05

Find the critical t-value

Now we need to find the critical t-value from t-distribution table with \( N-1 \) degrees of freedom (i.e., 4 in this case) corresponding to a right-tailed test at 0.05 significance level.
06

Make the decision

If the calculated t-value is higher than the critical t-value, then we reject the null hypothesis. Otherwise, we do not reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean Calculation
The sample mean, often represented as \( \bar{x} \), is the average value of a sample and is a vital statistic in hypothesis testing. It's calculated by adding together all observations in a sample and dividing by the total number of observations. In this case, if we add the given MWOL values (25.8, 36.6, 26.3, 21.8, 27.2) and divide by the number of observations (5), we get the sample mean. This forms the basis for comparison against the population mean when conducting hypothesis tests.
Sample Standard Deviation
The sample standard deviation (denoted as \( s \)) is a measure of how spread out numbers in a data set are around the mean. After calculating the sample mean, we use the formula \( s = \sqrt{\frac{1}{N-1} \sum{(x_i - \bar{x})^2}} \), where \( x_i \) represents each data point, \( \bar{x} \) is the sample mean, and \( N \) is the number of observations, to find the sample standard deviation. This step is crucial because it quantifies the variability or dispersion of the data set, an important component in the t-value calculation.
Population Mean
The population mean \( (\mu) \) is the average of all measurements in a population. In hypothesis testing, we don't usually know the population mean and attempt to estimate or make inferences about it using our sample statistics. The null hypothesis often involves an assumption or claim about the population mean, which is then tested against the sample evidence.
T-Value
The t-value, or t-score, is the result of a calculation that measures how far away a sample mean is from the hypothesized population mean in units of standard error. It's given by \( t = \frac{\bar{x} - \mu_0}{s / \sqrt{N}} \), where \( \bar{x} \) is the sample mean, \( \mu_0 \) is the population mean under the null hypothesis, \( s \) is the sample standard deviation, and \( N \) is the number of observations. A higher absolute t-value indicates a greater difference between the sample mean and the population mean, relative to the variability in the sample data.
Null Hypothesis
The null hypothesis \( (H_0) \) proposes that there is no effect or difference in the context of the test, often stating that any observed differences are due to chance. In the provided example, the null hypothesis posits that the true population mean MWOL is 25 kg, indicated as \( H_0: \mu = 25 \). It represents the status quo that we aim to challenge with sample data.
Alternative Hypothesis
The alternative hypothesis \( (H_1) \), in contrast to the null hypothesis, suggests that there is an effect or a difference. It represents the outcome that the test is designed to support. In this instance, the alternative hypothesis claims the population mean MWOL is greater than 25 kg, which is mathematically represented as \( H_1: \mu > 25 \). It's what we hope to find evidence for in the sample data.
Significance Level
The significance level, denoted as alpha \( (\alpha) \), is a threshold used to determine when to reject the null hypothesis. Commonly set at 0.05, it represents a 5% risk of concluding that a difference exists when there is no actual difference. When a p-value is less than \( \alpha \), or a test statistic exceeds the critical value at this level, we reject the null hypothesis in favor of the alternative. It's a key aspect in determining the robustness of our hypothesis test.
Degrees of Freedom
Degrees of freedom (df) is a concept related to the amount of independent information in a sample. In t-tests, degrees of freedom equal the number of observations minus one (\( N-1 \)). They are used to determine the critical value of t from the t-distribution that corresponds with the significance level for the test. With 5 data points in our example, we have 4 degrees of freedom, which helps us determine the critical t-value needed to assess the validity of our null hypothesis.

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Most popular questions from this chapter

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