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The article "Poll Finds Most Oppose Return to Draft, Wouldn't Encourage Children to Enlist" (Associated Press, December 18,2005 ) reports that in a random sample of 1000 American adults, 700 indicated that they oppose the reinstatement of a military draft. Is there convincing evidence that the proportion of American adults who oppose reinstatement of the draft is greater than twothirds? Use a significance level of \(.05\).

Short Answer

Expert verified
The conclusion will depend on the calculated p-value. If the p-value \(≤ 0.05\), then the null hypothesis is rejected and there is convincing evidence that more than two-thirds of American adults oppose the reinstatement of the draft. If the p-value is \(> 0.05\), then the null hypothesis is not rejected and there is not convincing evidence that more than two-thirds of American adults oppose the reinstatement of the draft.

Step by step solution

01

State the Hypotheses

Firstly, the null and alternative hypotheses need to be set up. The null hypothesis (\(H_0\)) is that the population proportion \(p\) equals \(2/3\) (or \(0.67\)). The alternative hypothesis (\(H_a\)) is that the population proportion \(p\) is greater than \(2/3\) (or \(0.67\)). So, \(H_0: p = 0.67\) and \(H_a: p > 0.67\).
02

Calculate the Test Statistic

Use the formula for the standard score (z-score) which is \(z = (p' - p_0) / \sqrt{(p_0(1 - p_0) / n)}\), where \(p'\) is the sample proportion, \(p_0\) is the proportion in the null hypothesis, and \(n\) is the sample size. In this case, \(p' = 700/1000 = 0.7\), \(p_0 = 0.67\), and \(n = 1000\). Substituting these gives \(z = (0.7 - 0.67) / \sqrt{(0.67 \times 0.33) / 1000}\). Calculate to obtain the value of \(z\).
03

Find the P-value

Use a z-table or a technology tool to find the p-value corresponding to the calculated z-score. Given that this is a one-sided test (greater than), you need to find the area to the right of the calculated z-score.
04

Draw a Conclusion

Compare the p-value with the significance level (\(0.05\)). If the p-value is less than or equal to the significance level, reject the null hypothesis. If the p-value is greater than the significance level, fail to reject the null hypothesis. Based on the comparison, draw the conclusion for the test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
In hypothesis testing, the term 'population proportion' refers to the percentage of individuals in a population who have a particular characteristic. For instance, if we're considering the number of people who oppose the reinstatement of a military draft, the population proportion would be the total number of individuals against the draft out of the entire population. To estimate this, researchers conduct surveys and use the sample data to infer the population proportion. The population proportion is denoted by the symbol \(p\) in statistical formulas. Understanding population proportion is crucial, as it serves as the basis for making decisions about the population from sample data.
Significance Level
The significance level is a threshold that researchers choose before conducting a hypothesis test to determine the strength of the evidence needed to reject the null hypothesis. It is denoted by \(\alpha\). A commonly used significance level is \(0.05\), which indicates a 5% risk of concluding that a difference exists when there is no actual difference—this is known as a Type I error. Setting a low significance level makes it harder to reject the null hypothesis, thus requiring stronger evidence for a claim to be considered statistically significant. In our exercise, we use a significance level of \(0.05\) to assess whether the observed sample proportion of adults opposing the draft significantly exceeds two-thirds of the population.
Z-score
The Z-score in hypothesis testing is a standardized score that tells us how many standard deviations a sample observation is from the mean under the null hypothesis. It's calculated using the formula \(z = (p' - p_0) / \sqrt{(p_0(1 - p_0) / n)}\), where \(p'\) is the sample proportion, \(p_0\) is the hypothesized population proportion, and \(n\) is the sample size. The Z-score corresponds to the test statistic in hypothesis testing and allows us to compare the observed data to what we would expect under the null hypothesis. A high absolute value of the Z-score indicates that the sample observation is far from what the null hypothesis predicts, potentially leading to the null hypothesis being rejected.
P-value
The p-value is a probability that measures the evidence against the null hypothesis. It answers the question: 'If the null hypothesis is true, what is the probability of observing a test statistic as extreme or more extreme than the one calculated from the sample data?' A p-value less than the significance level \(\alpha\) indicates strong evidence against the null hypothesis, which means it can be rejected. Conversely, a p-value greater than \(\alpha\) suggests insufficient evidence to reject the null hypothesis. In essence, the p-value quantifies the uncertainty—in the context of our exercise, it helps gauge whether the sample proportion of those opposing the draft is statistically higher than two-thirds.
Null and Alternative Hypotheses
The null hypothesis \(H_0\) is a statement that there is no effect or no difference, and it's what we seek evidence against. In contrast, the alternative hypothesis \(H_a\) represents what we're attempting to find evidence for. In our case, the null hypothesis states that the population proportion of adults who oppose the draft is two-thirds (\(p = 0.67\)), while the alternative hypothesis posits that more than two-thirds (\(p > 0.67\)) oppose it. Hypotheses are mutually exclusive: if one is true, the other must be false. Hypothesis testing is the process of determining which hypothesis the data supports more strongly.

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Most popular questions from this chapter

When a published article reports the results of many hypothesis tests, the \(P\) -values are not usually given. Instead, the following type of coding scheme is frequently used: \(^{*} p<.05,^{* *} p<.01,^{*} *^{*} p<.001, *\) Which of the symbols would be used to code for each of the following \(P\) -values? a. 037 c. \(.072\) b. \(.0026\) d. \(.0003\)

Duck hunting in populated areas faces opposition on the basis of safety and environmental issues. The San Luis Obispo Telegram-Tribune (June 18,1991 ) reported the results of a survey to assess public opinion regarding duck hunting on Morro Bay (located along the central coast of California). A random sample of 750 local residents included 560 who strongly opposed hunting on the bay. Does this sample provide sufficient evidence to conclude that the majority of local residents oppose hunting on Morro Bay? Test the relevant hypotheses using \(\alpha=.01\).

A number of initiatives on the topic of legalized gambling have appeared on state ballots. Suppose that a political candidate has decided to support legalization of casino gambling if he is convinced that more than twothirds of U.S. adults approve of casino gambling. USA Today (June 17,1999 ) reported the results of a Gallup poll in which 1523 adults (selected at random from households with telephones) were asked whether they approved of casino gambling. The number in the sample who approved was 1035 . Does the sample provide convincing evidence that more than two-thirds approve?

Explain why the statement \(\bar{x}=50\) is not a legitimate hypothesis.

A hot tub manufacturer advertises that with its heating equipment, a temperature of \(100^{\circ} \mathrm{F}\) can be achieved in at most 15 min. A random sample of 25 tubs is selected, and the time necessary to achieve a \(100^{\circ} \mathrm{F}\) temperature is determined for each tub. The sample average time and sample standard deviation are \(17.5 \mathrm{~min}\) and \(2.2 \mathrm{~min}, \mathrm{re}-\) spectively. Does this information cast doubt on the company's claim? Carry out a test of hypotheses using significance level \(.05 .\)

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