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You are bidding on four items available on eBay. You think that for each bid, you have a \(25 \%\) chance of winning it, and the outcomes of the four bids are independent events. Let \(X\) denote the number of winning bids out of the four items you bid on. a. Explain why the distribution of \(X\) can be modeled by the binomial distribution. b. Find the probability that you win exactly 2 bids. c. Find the probability that you win 2 bids or fewer. d. Find the probability that you win more than 2 bids.

Short Answer

Expert verified
a. Binomial distribution with \( n=4 \), \( p=0.25 \). b. \( P(X=2) = 0.2109 \). c. \( P(X \leq 2) = 0.9492 \). d. \( P(X > 2) = 0.0508 \).

Step by step solution

01

Define the Probability Model

Since each bid has two mutually exclusive outcomes (win or lose) and the probability of winning each bid is constant at \( p = 0.25 \), with the outcomes being independent of each other, the number of winning bids \( X \) follows a binomial distribution. This is characterized by the parameters \( n = 4 \) (number of trials or bids) and \( p = 0.25 \) (probability of success or winning a single bid).
02

Determine Probability of Winning Exactly 2 Bids

To find the probability of winning exactly 2 out of 4 bids, use the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}, \] where \( n = 4 \), \( k = 2 \), and \( p = 0.25 \). Calculate \[ P(X = 2) = \binom{4}{2} (0.25)^2 (0.75)^2. \] Compute \( \binom{4}{2} = 6 \). Thus, \[ P(X = 2) = 6 \times (0.25)^2 \times (0.75)^2 = 6 \times 0.0625 \times 0.5625 = 0.2109. \]
03

Calculate Probability of Winning 2 Bids or Fewer

To find \( P(X \leq 2) \), sum up the probabilities of winning 0, 1, and 2 bids. Compute individually using the formula: \[ P(X = 0) = \binom{4}{0} (0.25)^0 (0.75)^4 = 0.3164, \] \[ P(X = 1) = \binom{4}{1} (0.25)^1 (0.75)^3 = 0.4219, \] and use the value from the previous step \( P(X = 2) = 0.2109 \). Thus, \[ P(X \leq 2) = 0.3164 + 0.4219 + 0.2109 = 0.9492. \]
04

Find Probability of Winning More Than 2 Bids

To find \( P(X > 2) \), compute it as the complement of \( P(X \leq 2) \). Thus, \[ P(X > 2) = 1 - P(X \leq 2). \] Using the value calculated previously, \( P(X \leq 2) = 0.9492 \), therefore, \[ P(X > 2) = 1 - 0.9492 = 0.0508. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a fundamental mathematical framework that deals with the concept of uncertainty. It allows us to quantify the chance of certain outcomes occurring in a random experiment. When we say that an event has a certain probability, we mean it's the likelihood or chance of the event happening. For instance, in the eBay bidding scenario, there is a 25% probability (or 0.25 chance) that each bid will be successful.

Several key components of probability theory helped in solving the eBay bidding problem:
  • **Outcomes are Mutually Exclusive:** Each bid can either result in a win or a loss, but not both simultaneously.
  • **Probability Remains Constant:** Each bid has a constant success probability of 0.25, which remains unchanged by other bids.
  • **Sum of Probabilities:** The sum of all possible outcomes (winning one of the bids or not) is 1, which is a fundamental concept in probability theory.
Through such definitions and parameters, probability theory aids in setting up models like the binomial distribution to predict the outcomes of scenarios by providing us the mathematical tools needed to make these calculations.
Statistical Modeling
In statistical modeling, we use mathematical structures to describe and predict real-world phenomena. Specifically, in the exercise about bidding on eBay, we applied the binomial distribution model. This distribution is suitable to use when you have:
  • **A Fixed Number of Trials:** Here, the trials are the four bids you place. Each bid acts as an independent trial.
  • **Binary Outcomes:** The outcomes in this case are winning or losing a bid.
  • **Independent Trials:** Each bid result doesn't affect the others, which makes them independent.
  • **Constant Probability of Success:** Each bid has the same 25% chance of winning.
This exercise is an example of how statistical models like the binomial distribution can provide a structured way to solve and interpret probabilistic problems.

By using the binomial formula, we calculated probabilities for different scenarios, such as the probability of winning exactly two bids or fewer, and the chance of winning more than two bids. In essence, statistical modeling simplifies complex real-world situations into understandable mathematical frameworks, allowing predictions and analyses to be performed efficiently.
Independent Events
Independent events are an essential concept in probability theory, particularly in statistical modeling like our exercise. An event is considered independent if the outcome of one event does not affect the outcome of another. In the context of the eBay bids:
  • Each bidding outcome is independent; winning one bid does not change the probability of winning another.
  • This independence is crucial when applying the binomial distribution, as it ensures that each trial's outcome is unaffected by others, maintaining a consistent probability across all trials.
Understanding independent events can be quite intuitive. Think of flipping a coin; the result of one flip (head or tails) doesn't change the probability of what the next flip will be.

In our scenario of four bids, the assumption of independence means that each bid is treated as a separate scenario, linking up to influence the final outcome expressed through the binomial model. Still, keep in mind, real-life cases may sometimes exhibit dependencies, which need other probabilistic models to address them correctly. The binomial model's utility and accuracy significantly stem from this independence property, helping in reliably predicting probabilities.

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Most popular questions from this chapter

A balanced die with six sides is rolled 60 times. a. For the binomial distribution of \(X=\) number of \(6 \mathrm{~s}\), what is \(n\) and what is \(p ?\) b. Find the mean and the standard deviation of the distribution of \(X\). Interpret. c. If you observe \(x=0,\) would you be skeptical that the die is balanced? Explain why, based on the mean and standard deviation of \(X\). d. Show that the probability that \(x=0\) is 0.0000177 .

Selling houses Let \(X\) represent the number of homes a real estate agent sells during a given month. Based on previous sales records, she estimates that \(\mathrm{P}(0)=0.68\), \(\mathrm{P}(1)=0.19, \mathrm{P}(2)=0.09, \mathrm{P}(3)=0.03, \mathrm{P}(4)=0.01\) with negligible probability for higher values of \(x\). a. Explain why it does not make sense to compute the mean of this probability distribution as \((0+1+2+3+4) / 5=2.0\) and claim that, on average, she expects to sell 2 homes. b. Find the correct mean and interpret.

Playing the lottery The state of Ohio has several statewide lottery options. One is the Pick 3 game in which you pick one of the 1000 three-digit numbers between 000 and 999\. The lottery selects a three-digit number at random. With a bet of \(\$ 1,\) you win \(\$ 500\) if your number is selected and nothing (\$0) otherwise. (Many states have a very similar type of lottery.) (Source: Background information from www.ohiolottery.com.) a. With a single \(\$ 1\) bet, what is the probability that you win \(\$ 500 ?\) b. Let \(X\) denote your winnings for a \(\$ 1\) bet, so \(x=\$ 0\) or \(x=\$ 500\). Construct the probability distribution for \(X\). c. Show that the mean of the distribution equals 0.50 , corresponding to an expected return of 50 cents for the dollar paid to play. Interpret the mean. d. In Ohio's Pick 4 lottery, you pick one of the 10,000 fourdigit numbers between 0000 and 9999 and (with a \(\$ 1\) bet) win \(\$ 5000\) if you get it correct. In terms of your expected winnings, with which game are you better off \(-\) playing Pick \(4,\) or playing Pick 3 ? Justify your answer.

SAT math scores follow a normal distribution with an approximate \(\mu=500\) and \(\sigma=100\). Also ACT math scores follow a normal distrubution with an approximate \(\mu=21\) and \(\sigma=4.7\). You are an admissions officer at a university and have room to admit one more student for the upcoming year. Joe scored 600 on the SAT math exam, and Kate scored 25 on the \(\mathrm{ACT}\) math exam. If you were going to base your decision solely on their performances on the exams, which student should you admit? Explain.

The juror pool for the upcoming murder trial of a celebrity actor contains the names of 100,000 individuals in the population who may be called for jury duty. The proportion of the available jurors on the population list who are Hispanic is 0.40 . A jury of size 12 is selected at random from the population list of available jurors. Let \(X=\) the number of Hispanics selected to be jurors for this jury. a. Is it reasonable to assume that \(X\) has a binomial distribution? If so, identify the values of \(n\) and \(p\). If not, explain why not. b. Find the probability that no Hispanic is selected. c. If no Hispanic is selected out of a sample of size 12 , does this cast doubt on whether the sampling was truly random? Explain.

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