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Unfair wealth distribution sentiment According to a study published in www.gallup.com in \(2015,63 \%\) of Americans said wealth should be more evenly distributed among a larger percentage of people. For a sample of 10 Americans, let \(X=\) number of respondents who said wealth was unfairly distributed. a. Explain why the conditions are satisfied for \(X\) to have the binomial distribution. b. Identify \(n\) and \(p\) for the binomial distribution. c. Find the probability that two Americans in the sample said wealth should be more evenly distributed.

Short Answer

Expert verified
The probability is approximately 0.0101 or 1.01%.

Step by step solution

01

Verify Binomial Conditions

To confirm that this is a binomial distribution, we need to check the following conditions: 1. There are a fixed number of trials, which in this case is 10, as we are sampling 10 Americans. 2. Each trial can result in one of two outcomes: either they believe wealth is unfairly distributed or they don't. 3. Each respondent's opinion is independent of the others. 4. The probability of success (saying wealth is unfairly distributed) remains constant, which is 0.63 in this study. Since all these conditions are met, we can model this scenario with a binomial distribution.
02

Identify n and p

In a binomial distribution, \(n\) represents the number of trials, and \(p\) represents the probability of success on a single trial. Here, \(n = 10\) because there are 10 respondents, and \(p = 0.63\) as given in the problem description.
03

Establish the Probability Formula

The probability of exactly \(k\) successes in \(n\) independent binomial trials is given by the formula: \(P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\). We need to substitute \(n = 10\), \(p = 0.63\), and \(k = 2\) into the formula to find the probability that exactly 2 out of 10 Americans surveyed think wealth should be more evenly distributed.
04

Apply the Formula

First, calculate the binomial coefficient \(\binom{10}{2} = \frac{10!}{2!(10-2)!} = 45\). Then, apply the binomial probability formula: \[ P(X = 2) = \binom{10}{2} (0.63)^2 (1-0.63)^{10-2} = 45 \times (0.63)^2 \times (0.37)^8 \]
05

Compute the Probability

Calculate \((0.63)^2 = 0.3969\) and \((0.37)^8 \approx 0.0005827\). Then multiply these together with the binomial coefficient calculated in the previous step: \( 45 \times 0.3969 \times 0.0005827 \approx 0.01009601\). Therefore, the probability that exactly 2 Americans out of the sample of 10 believe wealth should be more evenly distributed is approximately 0.0101.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Understanding how to calculate probabilities is crucial in statistics, especially when working with binomial distributions. In our exercise, we're interested in finding the likelihood that a specific number of individuals share a certain opinion. This probability is calculated using the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] This formula allows us to calculate the probability of exactly \( k \) successes (in this case, people who believe wealth should be distributed more evenly) in \( n \) independent trials (our sample of Americans).
  • \( \binom{n}{k} \) is the binomial coefficient, which counts the number of ways \( k \) successes can occur in \( n \) trials.
  • \( p^k \) is the probability of \( k \) successes, given each trial has a success probability \( p \).
  • \((1-p)^{n-k} \) represents the probability of the remaining \( n-k \) trials not being successful.
Using this approach, we combine these components to determine the probability of a specific outcome in our binomial experiment. It's a reliable method that simplifies these calculations across various scenarios.
Binomial Coefficient
In the context of binomial probability, the binomial coefficient \( \binom{n}{k} \) is a crucial element. It's often referred to as "n choose k," and it dictates how many different ways you can select \( k \) successes out of \( n \) trials. For example, when given a group of 10 people, the coefficient helps us understand all the possible ways to choose 2 people from this group who favor redistributing wealth. The formula for the binomial coefficient is: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] Here:
  • \( n! \) is the factorial of \( n \), representing the product of all positive integers up to \( n \).
  • \( k! \) is the factorial of \( k \).
  • \((n-k)! \) is the factorial of the difference between \( n \) and \( k \).
Understanding the binomial coefficient allows us to accurately count combinations and facilitates the calculation of probabilities in binomial distributions, which is essential for determining precise outcomes within probability scenarios.
Independent Trials
In binomial distributions, the concept of independent trials is foundational. Each trial in a binomial experiment must not influence the outcome of any other trial. This independence ensures that our calculated probabilities accurately reflect the scenario at hand. For example, when sampling 10 Americans for their opinion on wealth distribution, each individual's response should be independent. This means that one person's belief about wealth should not affect another's response in any way. This independence can usually be assumed when:
  • The sample size is relatively small compared to the population, ensuring no significant impact occurs across trials.
  • Random sampling techniques, such as selecting individuals without following certain patterns, are employed.
These measures help preserve independence, allowing us to use the binomial model reliably. Ensuring the trials are independent eliminates correlation effects between trials, which is crucial for applying the binomial probability formula successfully.

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Most popular questions from this chapter

SAT math scores follow a normal distribution with an approximate \(\mu=500\) and \(\sigma=100\). Also ACT math scores follow a normal distrubution with an approximate \(\mu=21\) and \(\sigma=4.7\). You are an admissions officer at a university and have room to admit one more student for the upcoming year. Joe scored 600 on the SAT math exam, and Kate scored 25 on the \(\mathrm{ACT}\) math exam. If you were going to base your decision solely on their performances on the exams, which student should you admit? Explain.

For each of the following situations, explain whether the binomial distribution applies for \(X\). a. You are bidding on four items available on eBay. You think that you will win the first bid with probability \(25 \%\) and the second through fourth bids with probability \(30 \%\). Let \(X\) denote the number of winning bids out of the four items you bid on. b. You are bidding on four items available on eBay. Each bid is for \(\$ 70\), and you think there is a \(25 \%\) chance of winning a bid, with bids being independent events. Let \(X\) be the total amount of money you pay for your winning bids.

Verify the empirical rule by using Table A, software, or a calculator to show that for a normal distribution, the probability (rounded to two decimal places) within a. 1 standard deviation of the mean equals 0.68 . b. 2 standard deviations of the mean equals 0.95 . c. 3 standard deviations of the mean is very close to 1.00 .

San Francisco Giants hitting The table shows the probability distribution of the number of bases for a randomly selected time at bat for a San Francisco Giants player in 2010 (excluding times when the player got on base because of a walk or being hit by a pitch). In \(74.29 \%\) of the at-bats the player was out, \(17.04 \%\) of the time the player got a single (one base), \(5.17 \%\) of the time the player got a double (two bases), \(0.55 \%\) of the time the player got a triple, and \(2.95 \%\) of the time the player got a home run. a. Verify that the probabilities give a legitimate probability distribution. b. Find the mean of this probability distribution. c. Interpret the mean, explaining why it does not have to be a whole number, even though each possible value for the number of bases is a whole number. $$ \begin{array}{cc} \hline {\text { San Francisco Giants Hitting }} \\ \hline \text { Number of Bases } & \text { Probability } \\ \hline 0 & 0.7429 \\ 1 & 0.1704 \\ 2 & 0.0517 \\ 3 & 0.0055 \\ 4 & 0.0295 \\ \hline \end{array} $$

Binomial assumptions For the following random variables, check whether the conditions needed to use the binomial distribution are satisfied or not. Explain a. \(X=\) number of people suffering from a contagious disease in a family of \(4,\) when the probability of catching this disease is \(2 \%\) in the whole population (binomial, \(n=4, p=0.02\) ). (Hint: Is the independence assumption plausible?) b. \(X=\) number of unmarried women in a sample of 100 females randomly selected from a large population where \(40 \%\) of women in the population are unmarried \((\) binomial, \(n=100, p=0.40)\) c. \(X=\) number of students who use an iPhone in a random sample of five students from a class of size \(20,\) when half the students use iPhones (binomial, \(n=5, p=0.50\) ). d. \(X=\) number of days in a week you go out for dinner. (Hint: Is the probability of dining out the same for each day?)

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