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Standardized residuals for \(2 \times 2\) tables The table that follows shows the standardized residuals in parentheses for GSS data about the statement, "Women should take care of running their homes and leave running the country up to men." The absolute value of the standardized residual is 13.2 in every cell. For chi-squared tests with \(2 \times 2\) tables, since \(d f=1,\) only one nonredundant piece of information exists about whether an association exists. If observed count \(\geq\) expected count in one cell, observed count \(<\) expected count in the other cell in that row or column. Explain why this is true, using the fact that observed and expected counts have the same row and column totals. (In fact, in \(2 \times 2\) tables, all four standardized residuals have absolute value equal to the square root of the \(X^{2}\) test statistic.) \begin{tabular}{lcc} \hline Year & Agree & Disagree \\ \hline 1974 & 509(13.2) & 924(-13.2) \\ 1998 & 280(-13.2) & 1534(13.2) \\ \hline \end{tabular}

Short Answer

Expert verified
Observed and expected counts must balance row and column totals; hence deviations are symmetrical with residuals showing strength of association.

Step by step solution

01

Understanding 2x2 Table

Consider a 2x2 table where we have two categories (Agree/Disagree) for two different years (1974 and 1998). The observed counts (e.g., 509, 924) are given, and their corresponding standardized residuals (e.g., 13.2, -13.2) indicate deviation from the expected counts under the null hypothesis that the categories are independent. The absolute value of the residual tells us the magnitude of this deviation.
02

Row and Column Totals Consistency

Since the row and column totals are consistent for both observed and expected counts, any deviation in one cell must be offset by an opposite deviation in its pair to maintain these totals. That's why if one cell in a row or column has an observed count greater than expected, another cell in the same row or column must have observed count less than expected.
03

Chi-Squared Statistic Correlation

In a 2x2 table, the chi-squared test statistic gives a measure of association between the row and column variables. With only 1 degree of freedom (df = 1), there's one relevant piece of information about the association. For this table, the standardized residuals are equal to the square root of the chi-squared statistic, illustrating the strength and direction of deviation for each cell.
04

Symmetry of Standardized Residuals

The standardized residuals are symmetrical (13.2 and -13.2) because if one cell shows a positive deviation (observed > expected), another must show a negative deviation. This symmetry, due to paired nature in 2x2 table, keeps the total deviation balanced while indicating a strong effect as shown by the square root of the chi-squared statistic being 13.2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standardized Residuals
In statistical analysis, standardized residuals provide a measure of how much our observed count deviates from the expected count under the null hypothesis. When we perform a chi-squared test, these residuals help us understand the significance and direction of the deviations.

For a standardized residual, think of it as a way to put the deviation into perspective by comparing it against the expected spread or variation of counts. Mathematically, a standardized residual is calculated as:

\[\text{Standardized Residual} = \frac{\text{Observed Count} - \text{Expected Count}}{\sqrt{\text{Expected Count}}}\]

The magnitude of a standardized residual (its absolute value) indicates how unusual the observed count is, considering the expected. A high magnitude implies a large deviation, which can be interpreted as the cell contributing significantly to the chi-squared test statistic. In the context of a 2x2 table, these residuals can directly reveal the nature of association between the variables by comparing the agreement and disagreement counts across the different years.
2x2 Contingency Table
A 2x2 contingency table is an essential tool in statistics for representing the relationship between two categorical variables. The name "2x2" comes from the fact that the table contains two rows and two columns, making it simple yet powerful for analyzing small datasets.

In such a table, each cell shows the frequency count of observations that fall into that particular combination of categories. For example, the count of people who "Agree" in 1974 is in one cell, while those who "Disagree" in the same year appear in another. This structured organization allows for clear insights into how the variables interact or associate with each other.

As you work with a 2x2 table, you also compute the row and column totals which play a crucial role in analyzing any relationship. When performing a chi-squared test, these totals help us calculate expected counts assuming no association between the variables. These expected counts serve as a baseline to determine if there's a statistically significant association by comparing them to the observed counts.
Degrees of Freedom
In statistics, degrees of freedom refer to the number of independent values that can vary in an analysis without breaking any constraints. For a chi-squared test involving a 2x2 contingency table, the degrees of freedom are calculated as:

\[\text{Degrees of Freedom (df)} = ( ext{number of rows} - 1) \times ( ext{number of columns} - 1)\]

For a 2x2 contingency table, this results in only one degree of freedom (df = 1). This is because once you know the totals of the rows and columns, knowing three of the cell values automatically determines the fourth.

This singular degree of freedom simplifies the chi-squared analysis but also limits the amount of non-redundant information available about any association between the variables in the table. This constraint ensures that the table’s totals remain consistent between the observed and expected counts, playing a pivotal role in the test's validity.
Expected Counts
Expected counts are fundamental in statistics for testing hypotheses using a chi-squared test. They represent the counts we'd expect to see in each cell of a contingency table if there were no association between the variables.

To calculate the expected count for a cell in a 2x2 table, use this formula:

\[\text{Expected Count} = \left(\frac{\text{Row Total} \times \text{Column Total}}{\text{Grand Total}}\right)\]

By comparing expected counts with observed counts, we assess if deviations are due to random chance or indicate a potential association. Large differences between observed and expected counts, which would translate into large absolute values for standardized residuals, imply a more significant association.

Ensuring that observed counts differ significantly from expected counts supports rejecting the null hypothesis, which posits no relationship between the variables studied. Expected counts thus hold a pivotal place in the calculation and interpretation of the chi-squared test, weaving together the observed strengths of association in a dataset's structure.

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Most popular questions from this chapter

Herbs and the common cold A recent randomized experiment of a multiherbal formula (Immumax) containing echinacea, garlic, ginseng, zinc, and vitamin C was found to improve cold symptoms in adults over a placebo group. "At the end of the study, eight ( \(39 \%\) ) of the placebo recipients and \(18(60 \%)\) of the Immumax recipients reported that the study medication had helped improve their cold symptoms (chi-squared P-value \(=0.01\) )." (M. Yakoot et al., International Joumal of General Medicine, vol. 4,2011 , pp. \(45-51\) ). a. Identify the response variable and the explanatory variable and their categories for the \(2 \times 2\) contingency table that provided this particular analysis.

Female participation in defense services? When people participating in recent surveys were asked if women should actively participate in defense services, about \(91 \%\) of females and \(91 \%\) of males answered yes and the rest answered no. a. For males and for females, report the conditional distributions on this response variable in a \(2 \times 2\) table, using outcome categories (yes, no). b. If results for the entire population are similar to these, does it seem possible that gender and opinion about having active participation of women in defense services are independent? Explain.

Karl Pearson devised the chi-squared goodness-of-fit test partly to analyze data from an experiment to analyze whether a particular roulette wheel in Monte Carlo was fair, in the sense that each outcome was equally likely in a spin of the wheel. For a given European roulette wheel with 37 pockets (with numbers \(0,1,2, \ldots, 36\) ), consider the null hypothesis that the wheel is fair. a. For the null hypothesis, what is the probability for each pocket? b. For an experiment with 3,700 spins of the roulette wheel, find the expected number of times each pocket is selected. c. In the experiment, the 0 pocket occurred 110 times. Show the contribution to the \(X^{2}\) statistic of the results for this pocket. d. Comparing the observed and expected counts for all 37 pockets, we get \(X^{2}=34.4\) Specify the df value and indicate whether there is strong evidence that the roulette wheel is not balanced. (Hint: Recall that the \(d f\) value is the mean of the distribution.)

Serious side effects In \(2007,\) the FDA announced that the popular drug Zelnorm used to treat irritable bowel syndrome was withdrawn from the market, citing concerns about serious side effects. The analysis of several studies revealed that 13 of 11,614 patients receiving the drug had a serious side effect such as heart attack or stroke, compared to just 1 out of 7,031 on placebo. a. Construct a \(2 \times 2\) contingency table from these data. b. Compute the relative risk and interpret. c. Compute the odds ratio and interpret. d. In a letter to health care professionals, the drug maker quoted a P-value of 0.024 for the comparison between the probability of a serious side effect in the drug and placebo group. By entering the data into the Fisher's Exact Test web app (or other software), show that this is the P-value for Fisher's exact test with a two-sided alternative hypothesis. What are the conclusions at a 0.05 significance level?

Down syndrome diagnostic test The table shown, from Example 8 in Chapter \(5,\) cross-tabulates whether a fetus has Down syndrome by whether the triple blood diagnostic test for Down syndrome is positive (that is, indicates that the fetus has Down syndrome). a. Tabulate the conditional distributions for the blood test result, given the true Down syndrome status. b. For the Down cases, what percentage was diagnosed as positive by the diagnostic test? For the unaffected cases, what percentage got a negative test result? Does the diagnostic test appear to be a good one? c. Construct the conditional distribution on Down syndrome status for those who have a positive test result. (Hint: You condition on the first column total and find proportions in that column.) Of those cases, what percentage truly have Down syndrome? Is the result surprising? Explain why this probability is small. \begin{tabular}{lrrr} \hline & \multicolumn{2}{c} { Blood Test Result } & \\ \cline { 2 - 3 } Down Syndrome Status & Positive & Negative & Total \\ \hline D (Down) & 48 & 6 & 54 \\ D \(^{c}\) (unaffected) & 1307 & 3921 & 5228 \\ Total & 1355 & 3927 & 5282 \\ \hline \end{tabular}

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