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True or false: Positive values in CI If a \(95 \%\) confidence interval for \(\left(\mu_{1}-\mu_{2}\right)\) contains only positive numbers, then we can conclude that both \(\mu_{1}\) and \(\mu_{2}\) are positive.

Short Answer

Expert verified
False, the confidence interval only indicates \(\mu_1 > \mu_2\), not their individual positivity.

Step by step solution

01

Understanding Confidence Intervals

Confidence intervals (CIs) provide a range of values within which we can be reasonably confident that a population parameter lies. A 95% confidence interval implies there is a 95% probability that the interval calculated from sample data contains the true parameter value.
02

Identify the Parameter of Interest

In this exercise, the parameter of interest is the difference between two population means, denoted as \(\mu_1 - \mu_2\). The given confidence interval reflects only on this difference.
03

Analyzing the Given Confidence Interval

The exercise states that the confidence interval for \(\mu_1 - \mu_2\) contains only positive numbers. This implies \(\mu_1\) is significantly greater than \(\mu_2\), but does not provide individual values of \(\mu_1\) or \(\mu_2\).
04

Evaluating the Conclusion Regarding Positivity

Since the confidence interval only informs us about the difference, \(\mu_1 - \mu_2 > 0\), it does not provide information on the absolute values of \(\mu_1\) or \(\mu_2\). Both could potentially be negative as long as \(\mu_1\) is greater by a positive margin.
05

Conclusion on the Statement

The statement given is false. The confidence interval containing only positive values for \(\mu_1 - \mu_2\) does not imply that \(\mu_1\) and \(\mu_2\) are individually positive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Parameters
When discussing confidence intervals, it's important to understand the concept of population parameters. A population parameter is a characteristic or measure that is intended to describe an entire population.
A common example is the population mean, denoted by \( \mu \), which is the average value of a particular characteristic in a population. In statistical studies, we often try to estimate these parameters because they give us insight into the entire population.
Population parameters are typically unknown because measuring every single member of a large population is often impractical or impossible. So instead, we use samples.
This is where confidence intervals come in—they provide a range of plausible values for these parameters based on a sample from the population.
For instance:
  • Mean (\(\mu\)): The average of a variable in the population.
  • Variance: How much variation exists from the average.
  • Proportions: The fraction of the population with a certain characteristic.
Each of these quantities captures different aspects of a population and can be estimated using data from a sample.
Difference of Means
The difference of means is a crucial concept when comparing two separate groups or populations. It represents the difference between the average values of a particular characteristic in these two groups.
In mathematical terms, if you have two populations with means \( \mu_1 \) and \( \mu_2 \), the difference of means is \( \mu_1 - \mu_2 \). This parameter tells us whether one population tends to have higher or lower values of the measured characteristic compared to the other.
In the context of confidence intervals, the range of values calculated for \( \mu_1 - \mu_2 \) helps us understand if the observed difference is statistically significant or could have occurred by random chance.
Here are some insights into the practical importance of the difference of means:
  • If the confidence interval for \( \mu_1 - \mu_2 \) is positive, it indicates the first group likely has higher average values.
  • If it's negative, the second group has higher averages.
  • If the interval includes zero, this suggests no strong evidence of a difference in means.
Understanding this concept is vital for making decisions based on data comparisons.
Statistical Inference
Statistical inference is the process through which we make conclusions about a population based on sample data. This is done by using sample statistics to estimate population parameters.
Since we cannot always access data for an entire population, statistical inference allows us to draw conclusions using limited information. One of the key tools of statistical inference is the confidence interval, which estimates the range within which a population parameter will fall a certain percentage of the time (such as 95%).
Through statistical inference, we can:
  • Determine the reliability of an estimated parameter (by assessing the width and position of a confidence interval).
  • Test hypotheses about population parameters.
  • Make predictions about population behavior based on sample observations.
The ultimate goal is to make informed decisions and predictions that reflect the true nature of the whole group, despite only having a subset of the data.
This requires a clear understanding of probability and its role in making reliable inferences, ensuring our conclusions are as accurate as possible given the available data.

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Most popular questions from this chapter

A Danish study of individuals born at a Copenhagen hospital between 1959 and 1961 reported higher mean IQ scores for adults who were breast-fed for longer lengths of time as babies (E. Mortensen et al., \(J A M A,\) vol. \(287,2002,\) pp. \(2365-2371\) ). The mean IQ score was \(98.1(s=15.9)\) for the \(272 \mathrm{sub}\) jects who had been breast-fed for no longer than a month and \(108.2(s=13.1)\) for the 104 subjects who had been breast-fed for seven to nine months. a. With software that can analyze summarized data, use an inferential method to analyze whether the corresponding population means differ, assuming the population standard deviations are equal. Interpret. b. Was this an experimental or an observational study? Can you think of a potential lurking variable?

In the study for cancer death rates, consider the null hypothesis that the population proportion of cancer deaths \(p_{1}\) for placebo is the same as the population proportion \(p_{2}\) for aspirin. The sample proportions were \(\hat{p}_{1}=347 / 11535=0.0301\) and \(\hat{p}_{2}=327 / 14035=0.0233 .\) a. For testing \(\mathrm{H}_{0}: p_{1}=p_{2}\) against \(\mathrm{H}_{a}: p_{1} \neq p_{2},\) show that the pooled estimate of the common value \(p\) under \(\mathrm{H}_{0}\) is \(\hat{p}=0.026\) and the standard error is 0.002 . b. Show that the test statistic is \(z=3.4\). c. Find and interpret the P-value in context.

Change coffee brand? A study was conducted to see if an advertisement campaign would increase market share for Sanka instant decaffeinated coffee (R. Grover and \(\mathrm{V}\). Srinivasan, \(J .\) Marketing Research, vol. \(24,1987,\) pp. 139 - 153). Subjects who use instant decaffeinated coffee were asked which brand they bought last. They were asked this before the campaign and after it. The results are shown in the table, with computer output based on it below. a. Estimate the population proportion choosing Sanka for the (i) first purchase and (ii) second purchase. Find the difference and interpret it. b. Explain how to interpret the \(95 \%\) confidence interval. c. The software output also shows a P-value. State the hypotheses that this P-value refers to in the context of this exercise and give the conclusion of the test when using a significance level of \(0.05 .\) \begin{tabular}{lcc} \hline Two Purchases of Coffee & \\ \hline & \multicolumn{2}{c} { Second Purchase } \\ \cline { 2 - 3 } First Purchase & Sanka & Other Brand \\ \hline Sanka & 155 & 49 \\ Other brand & 76 & 261 \\ \hline \end{tabular}

A researcher in the College of Nursing, University of Florida, hypothesized that women who undergo breast augmentation surgery would gain an increase in self-esteem. The article about the study \(^{15}\) indicated that for the 84 subjects who volunteered for the study, the scores on the Rosenberg Self- Esteem Scale were 20.7 before the surgery (std. dev. \(=6.3\) ) and 24.9 after the surgery (std. \(\mathrm{dev}=4.6\) ). The author reported that a paired difference significance test had \(t=9.8\) and a P-value below 0.0001 . a. Were the samples compared dependent samples, or independent samples? Explain. b. Can you obtain the stated \(t\) statistic from the values reported for the means, standard deviation, and sample size? Why or why not?

Suppose that a \(99 \%\) confidence interval for the difference \(p_{1}-p_{2}\) between the proportions of men and women in California who are alcoholics equals \((0.02,0.09) .\) Choose the best correct choice. a. We are \(99 \%\) confident that the proportion of alcoholics is between 0.02 and 0.09 . b. We are \(99 \%\) confident that the proportion of men in California who are alcoholics is between 0.02 and 0.09 larger than the proportion of women in California who are. c. We can conclude that the population proportions may be equal. d. We are \(99 \%\) confident that a minority of California residents are alcoholics. e. Since the confidence interval does not contain \(0,\) it is impossible that \(p_{1}=p_{2}\)

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