/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 How to sell a burger A fast-food... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

How to sell a burger A fast-food chain wants to compare two ways of promoting a new burger (a turkey burger). One way uses a coupon available in the store. The other way uses a poster display outside the store. Before the promotion, their marketing research group matches 50 pairs of stores. Each pair has two stores with similar sales volume and customer demographics. The store in a pair that uses coupons is randomly chosen, and after a monthlong promotion, the increases in sales of the turkey burger are compared for the two stores. The increase was higher for 28 stores using coupons and higher for 22 stores using the poster. Is this strong evidence to support the coupon approach, or could this outcome be explained by chance? Answer by performing all five steps of a two-sided significance test about the population proportion of times the sales would be higher with the coupon promotion.

Short Answer

Expert verified
There is moderate evidence that coupons are more effective, as we did not find a highly significant difference.

Step by step solution

01

State the Hypotheses

We need to set up our null and alternative hypotheses. The null hypothesis (\(H_0\)) states that there is no difference in effectiveness between using coupons and posters, meaning the probability (\

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions about a population parameter based on sample data. The process helps determine whether there is enough evidence to reject a null hypothesis, which often claims that there is no effect or no difference between groups.
Here are the main components:
  • Null Hypothesis (87): Typically a statement of no effect or no difference, it serves as the default assumption. In this case, the null hypothesis would be that the use of coupons is equally effective as posters in increasing sales of the turkey burger.
  • Alternative Hypothesis (88): This is what the researcher wants to prove. In the burger promotion scenario, the alternative hypothesis would propose that coupons are more effective than posters in boosting sales.
  • Significance Level (19): Often set at 0.05, it's the threshold for determining whether an observed effect is statistically significant.
  • Test Statistic: A numerical value calculated from the sample data, compared against a critical value to decide whether to reject the null hypothesis.
  • Decision Rule: If the test statistic exceeds the critical value, the null hypothesis is rejected in favor of the alternative hypothesis.
Understanding hypothesis testing is essential as it helps companies like the fast-food chain make informed decisions about promotional strategies.
Population Proportion
Population proportion is a statistical measure that represents the fraction of the population with a particular characteristic. In the context of the sales promotion analysis, the population proportion is the probability that the coupon strategy results in a higher increase in burger sales compared to the poster strategy.
For hypothesis testing of population proportions, we often compare the observed proportion from the sample with a known proportion or hypothesized proportion based on the null hypothesis.
In our example, the observed result shows that out of the 50 pairs of stores, 28 used the coupon strategy effectively, giving us an observed proportion (7_hat) of 7_hat = 28/50 = 0.56.
  • Null Hypothesis (87): Here, the hypothesized population proportion (P) might be 0.5, suggesting equal effectiveness between coupons and posters.
  • Alternative Hypothesis (88): This states that the population proportion is greater than 0.5, supporting that the coupon strategy is more effective.
  • Z-test for Proportion: Used to assess whether the observed proportion significantly deviates from the hypothesized proportion.
By analyzing these proportions, the company can assess the relative success of the coupon promotion strategy against the poster strategy.
Sales Promotion Analysis
Sales promotion analysis involves examining the effects of different marketing strategies on sales figures. It helps businesses understand what works best to enhance their revenue streams.
For this particular exercise, the fast-food chain is evaluating whether coupons or poster displays are more effective at increasing burger sales.
  • Matched Pairs Design: Stores are paired based on similar characteristics to limit variability that could skew results, ensuring a fair comparison between the two promotional efforts.
  • Significance of Differences: By comparing sales increases between matched pairs, the chain can determine if coupons outperform posters beyond what might be expected by chance.
  • Quantitative Analysis: Examining numerical differences in sales provides concrete data on promotional effectiveness, facilitating data-driven decision-making.
The results of the analysis offer actionable insights, guiding the chain's future marketing strategies and aiding in the efficient allocation of promotional resources.

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Most popular questions from this chapter

Low-carbohydrate diet A study plans to have a sample of obese adults follow a proposed low-carbohydrate diet for three months. The diet imposes limited eating of starches (such as bread and pasta) and sweets, but otherwise no limit on calorie intake. Consider the hypothesis, The population mean of the values of weight change \((=\) weight at start of study \(-\) weight at end of study) is a positive number. a. Is this a null or an alternative hypothesis? Explain your reasoning. b. Define a relevant parameter, and express the hypothesis that the diet has no effect in terms of that parameter. Is it a null or alternative hypothesis?

Get P-value from \(z\) For a test of \(\mathrm{H}_{0}: p=0.50,\) the \(z\) test statistic equals 1.04 a. Find the P-value for \(\mathrm{H}_{a} \cdot p>0.50\). b. Find the P-value for \(\mathrm{H}_{a}: p \neq 0.50\). c. Find the P-value for \(\mathrm{H}_{c}: p<0.50 .\) (Hint: The P-values for the two possible one-sided tests must sum to \(1 .)\) d. Do any of the P-values in part a, part b, or part c give strong evidence against \(\mathrm{H}_{0}\) ? Explain.

A binomial headache A null hypothesis states that the population proportion \(p\) of headache sufferers who have more pain relief with aspirin than with another pain reliever equals \(0.50 .\) For a crossover study with 10 subjects, all 10 have more relief with aspirin. If the null hypothesis were true, by the binomial distribution the probability of this sample result equals \((0.50)^{10}=0.001\). In fact, this is the small-sample P-value for testing \(\mathrm{H}_{0}: p=0.50\) against \(\mathrm{H}_{a}: p>0.50 .\) Does this P-value give (a) strong evidence in favor of \(\mathrm{H}_{0}\) or \((\mathrm{b})\) strong evidence against \(\mathrm{H}_{0}\) ? Explain why.

Men at work When the 636 male workers in the 2008 GSS were asked how many hours they worked in the previous week, the mean was 45.5 with a standard deviation of 15.16 . Does this suggest that the population mean work week for men exceeds 40 hours? Answer by: a. Identifying the relevant variable and parameter. b. Stating null and alternative hypotheses. c. Reporting and interpreting the P-value for the test statistic value of \(t=9.15\). d. Explaining how to make a decision for the significance level of 0.01

Fishing for significance A marketing study conducts 60 significance tests about means and proportions for several groups. Of them, 3 tests are statistically significant at the 0.05 level. The study's final report stresses only the tests with significant results, not mentioning the other 57 tests. What is misleading about this?

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