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Find test statistic and P-value For a test of \(\mathrm{H}_{0}: p=0.50\), the sample proportion is 0.35 based on a sample size of 100 . a. Show that the test statistic is \(z=-3.0\). b. Find the \(\mathrm{P}\) -value for \(\mathrm{H}_{a}: p<0.50\). c. Does the P-value in part b give much evidence against \(\mathrm{H}_{0}\) ? Explain.

Short Answer

Expert verified
a. Test statistic is \(z=-3.0\). b. P-value is 0.00135. c. Yes, the P-value provides strong evidence against \(H_0\).

Step by step solution

01

Understand the Hypotheses

We are conducting a hypothesis test with the null hypothesis being \( H_0: p = 0.50 \) and the alternative hypothesis \( H_a: p < 0.50 \). The sample proportion \( \hat{p} \) is given as 0.35, and the sample size \( n \) is 100.
02

Calculate Standard Error

The standard error \( SE \) of the sample proportion is calculated using the formula: \[ SE = \sqrt{\frac{p(1-p)}{n}} \] where \( p = 0.50 \) and \( n = 100 \). Thus, \[ SE = \sqrt{\frac{0.50(1-0.50)}{100}} = \sqrt{\frac{0.25}{100}} = \sqrt{0.0025} = 0.05 \]
03

Calculate the Test Statistic

The test statistic \( z \) is calculated using the formula: \[ z = \frac{\hat{p} - p}{SE} \] where \( \hat{p} = 0.35 \), \( p = 0.50 \), and \( SE = 0.05 \). So, \[ z = \frac{0.35 - 0.50}{0.05} = \frac{-0.15}{0.05} = -3.0 \]
04

Determine the P-Value

Since \( H_a: p < 0.50 \), this is a left-tailed test. We find the P-value by looking up the z-score of -3.0 in the standard normal distribution table, or using a calculator, which gives a P-value of approximately 0.00135.
05

Analyze the Result

The P-value of 0.00135 is very small and indicates strong evidence against the null hypothesis \( H_0 \). Typically, if the P-value is less than the significance level (often 0.05), we reject \( H_0 \). Here, 0.00135 is much smaller than 0.05, suggesting significant evidence against \( H_0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The standard error (SE) is a crucial concept in hypothesis testing as it measures the variability or dispersion of the sample proportion from the true population proportion. In simpler terms, it indicates how much the sample proportion you calculated is expected to vary from one sample to another.
Given a scenario where the true proportion, \( p \), is 0.50, and the sample size, \( n \), is 100, the formula for calculating the standard error is:
  • \[ SE = \sqrt{\frac{p(1-p)}{n}} \]
Plugging in our values, we get:
  • \[ SE = \sqrt{\frac{0.50(1-0.50)}{100}} = \sqrt{\frac{0.25}{100}} = \sqrt{0.0025} = 0.05 \]

Here, our SE is 0.05, representing the expected standard deviation of the sample proportion measurements from the true population proportion. A smaller SE suggests that the sample proportion is more closely likely to reflect the true population proportion, which is key in determining the reliability of our hypothesis test results.
P-value
The P-value is an important part of hypothesis testing because it helps us determine the strength of the evidence against the null hypothesis. The P-value represents the probability of obtaining a test result that is at least as extreme as the one observed, assuming that the null hypothesis is true.
In our context where the alternative hypothesis is \( H_a: p < 0.50 \), we deal with a left-tailed test. This means we are interested in finding the probability that the sample proportion is significantly less than the hypothesized population proportion.
With a test statistic \( z = -3.0 \), the P-value can be found using a standard normal distribution table or a statistical calculator. For this example, the P-value is approximately 0.00135.

This very low P-value indicates that there is only a 0.135% chance of observing a sample proportion of 0.35 or less if the true population proportion is 0.50. Since this probability is considerably lower than common significance levels like 0.05, it suggests that the observed sample proportion is statistically significant and provides strong evidence against the null hypothesis.
Test Statistic
A test statistic is a standardized value used in statistical hypothesis testing to determine whether to reject the null hypothesis. It measures the degree of deviation of the sample result from the null hypothesis.
In standard problems involving proportions, the test statistic often used is the z-score. The formula for this z-score is:
  • \[ z = \frac{\hat{p} - p}{SE} \]
Here, \( \hat{p} \) is the sample proportion, \( p \) is the hypothesized proportion from the null hypothesis, and \( SE \) is the standard error. In our example, we have a sample proportion \( \hat{p} = 0.35 \), a hypothesized proportion \( p = 0.50 \), and a standard error \( SE = 0.05 \).
Using the formula, we find:
  • \[ z = \frac{0.35 - 0.50}{0.05} = \frac{-0.15}{0.05} = -3.0 \]

This calculated z-score of -3.0 tells us how far and in which direction our sample proportion deviates from the null hypothesis in units of standard deviation. A high absolute value of the test statistic often indicates that the sample result is unusual under the null hypothesis, leading us to question its validity.

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