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Kicking accuracy A football coach decides to estimate the kicking accuracy of a player who wants to join the team. Of 10 extra point attempts, the player makes all 10 . a. Find an appropriate \(95 \%\) confidence interval for the probability that the player makes any given extra point attempt. b. What's the lowest value that you think is plausible for that probability? c. How would you interpret the random sample assumption in this context? Describe a scenario such that it would not be sensible to treat these 10 kicks as a random sample.

Short Answer

Expert verified
a) CI: [0.661, 1]. b) Lowest plausible: 0.661. c) Randomness requires independence; similar conditions for all kicks ensure it.

Step by step solution

01

Understanding the Problem

We have a player who made 10 out of 10 extra-point kicks. We need to create a 95% confidence interval to estimate the probability of making any given kick.
02

Defining the Parameters

Set the observed probability, \( \hat{p} \), of making a kick as 1 (since the player made all 10 kicks). The total number of kicks, \( n \), is 10.
03

Using the Formula for Confidence Interval

The confidence interval for a proportion is given by \( \hat{p} \pm Z \times \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \), where \( Z \) is the Z-score for your confidence level.
04

Calculating the 95% Confidence Interval

For a 95% confidence interval, \( Z \approx 1.96 \). Since \( \hat{p} = 1 \), the interval becomes \( 1 \pm 1.96 \times \sqrt{\frac{1(1-1)}{10}} = 1 \pm 0 \). Producers often use a special adjustment when \( \hat{p} = 1 \) to avoid an interval of zero width.
05

Adjusting Using the Agresti-Coull Method

The Agresti-Coull interval suggests adding 2 successes and 2 failures, treating it as 12 kicks with \( p = 0.9167 \). Calculate: \( \hat{p} = \frac{12}{12} = 1 \), find the interval: \( \frac{12+2}{12+4} \pm 1.96 \times \sqrt{\frac{14/16 \cdot 2/16 }{16}} \).\( \frac{14}{16} = 0.875 \), so interval becomes \(0.875 \pm 0.214\approx[0.661,1.089]\). Adjust appropriately to fit within probability range: \([0.661, 1]\).
06

Identifying the Lowest Plausible Value

The lowest plausible value for the confidence interval calculated using the adjusted method is approximately 0.661.
07

Interpreting the Random Sample Assumption

In statistical terms, a random sample means each trial (kick) is independent and identically distributed. If conditions such as uniform setting or consistent player state are not met, these 10 kicks are not a random sample.
08

Envisioning Non-Random Scenario

If the player practiced under consistent conditions or had external pressure during some attempts, treating this as a random sample would misconstrue the variability and external influences.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Sample Assumption
The random sample assumption is critical in statistics. When we talk about random samples, each trial or observation must be independent and identically distributed.
This means that each event, in this case, each kick, should not be influenced by the others. It should be like drawing random samples from an urn without any predetermination or influence over which sample gets drawn.
In the context of the football player's kicks, we assume that each attempt is independent. The accuracy of each kick should not depend on the kicks before it or external changes.
For instance, variations in weather conditions or a change in the player's mental state from one kick to the next could violate this assumption. Several scenarios might lead to non-random samples, like if the player had a strong supporting wind in half the kicks or only tried under ideal conditions, such as no audience pressure.
This would skew the observations since certain non-random factors would affect some attempts and not others.
Agresti-Coull Interval
When estimating probabilities for binary outcomes, like kicks made or missed, traditional methods may fail with extreme proportions, usually 0 or 1.
In such cases, the Agresti-Coull method comes in handy by adding pseudo-counts to the observations. This method ensures a more reliable confidence interval.
By adding 2 successes and 2 failures to the counts, it helps generate a better statistical estimate, especially when the sample size is small. For our football player's scenario, this translates to working with 12 kicks instead of the observed 10.
With the adjustment, the probability estimation becomes 0.875 instead of 1.Using the Agresti-Coull adjustment, our estimated confidence interval becomes \(0.875 \pm 1.96 \times \sqrt{\frac{0.875 \times 0.125}{16}} \), simplifying to \([0.661, 1]\).This approach allows us to describe a range where the true kicking accuracy likely falls, addressing any sampling variability due to sample size.
Probability Estimation
For probability estimation, the observed rate of success serves as a base to predict future outcomes. However, with small sample sizes, it can be misleading.
This is where methods like the confidence interval become essential. A confidence interval provides a range of plausible values for the true success rate.
In our example, the initial estimation yields a probability of 1. Yet, intuitively, such certainty is rare in real life.A confidence interval, particularly when adjusted with methods like Agresti-Coull, offers us a more credible estimation band. It accounts for variability, giving us insight into what is truly expected. Hence, while the observation is a 100% success rate, statistical methods show that realistically, the true accuracy might be between 66.1% and 100%, as estimated by the \([0.661, 1]\) interval.These intervals help us remain cautious in our estimates, accounting for variability and acknowledging the practical limits of small sample observations.

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Most popular questions from this chapter

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