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Wife doesn't want kids The 1996 GSS asked, "If the husband in a family wants children, but the wife decides that she does not want any children, is it all right for the wife to refuse to have children?" Of 699 respondents, 576 said yes. a. Find a \(99 \%\) confidence interval for the population proportion who would say yes. Can you conclude that the population proportion exceeds \(75 \%\) ? Why? b. Without doing any calculation, explain whether the interval in part a would be wider or narrower than a \(95 \%\) confidence interval for the population proportion who would say yes.

Short Answer

Expert verified
The 99% confidence interval is (0.7869, 0.8611), exceeding 75%. A 99% interval is wider than 95%.

Step by step solution

01

Calculate Sample Proportion

The sample proportion \( \hat{p} \) can be calculated by dividing the number of respondents who said yes by the total number of respondents. Thus, \( \hat{p} = \frac{576}{699} \approx 0.824 \).
02

Calculate the Standard Error

The standard error for the sample proportion is given by the formula \( SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \), where \( n \) is the sample size. Substituting the values, \( SE = \sqrt{\frac{0.824 \times (1-0.824)}{699}} \approx 0.0144 \).
03

Find the Critical Value for 99% Confidence

For a 99% confidence interval, the critical value \( z^* \) from the standard normal distribution is approximately 2.576.
04

Calculate the Margin of Error

The margin of error (ME) is given by \( ME = z^* \times SE \). So, \( ME = 2.576 \times 0.0144 \approx 0.0371 \).
05

Construct the 99% Confidence Interval

The confidence interval is \( \hat{p} \pm ME \). Thus, the 99% confidence interval is \( 0.824 \pm 0.0371 \), which results in \( (0.7869, 0.8611) \).
06

Conclusion About Population Proportion Exceeding 75%

Since the entire confidence interval (0.7869, 0.8611) is above 0.75, we can conclude that the population proportion exceeds 75% with 99% confidence.
07

Compare 99% and 95% Confidence Intervals

A 99% confidence interval is wider than a 95% confidence interval because a larger confidence level means we require more certainty, resulting in a larger range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is a fundamental concept in statistics. It represents the fraction or percentage of the entire population that has a particular characteristic. In this context, we're looking at the proportion of people who believe that a wife can refuse to have children if she chooses. To make statistical inferences about a population proportion, it is crucial to have a good understanding of the sample from which the data is drawn. In the featured exercise, the population proportion we are interested in is those who would answer 'yes' to the question posed in the survey.
By calculating a confidence interval for the population proportion, we aim to estimate this true proportion within a certain level of certainty. The objective is to determine whether this proportion is above a specific threshold—in this case, 75%. This illustration highlights how surveys can be used to draw conclusions about broader societal views through a well-defined mathematical framework.
Sample Proportion
The sample proportion is a critical piece of the puzzle when estimating the population proportion. It is denoted by \( \hat{p} \) and represents the ratio of participants in the sample exhibiting the trait of interest. Calculating this is straightforward: divide the number of favorable responses (in this case, those who say 'yes') by the total number of respondents.

So, \( \hat{p} = \frac{576}{699} \approx 0.824 \). This means that approximately 82.4% of the sampled individuals think it is acceptable for the wife to refuse. This sample proportion helps in creating a bridge to understand and infer the population proportion by serving as the center of our confidence interval.

The accuracy of our inferences about the population largely hinges on the calculated sample proportion. Thus, carefully selecting and composing the sample is essential for meaningful statistical analysis.
Standard Error
Understanding the standard error (SE) is crucial when dealing with sample distribution in statistics. The SE is a measure of variability or dispersion in the context of a sampling distribution, indicating how much the sample proportion is expected to fluctuate from the true population proportion.
The standard error is derived using the formula:
\[ SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \]
Here, \( \hat{p} \) is the sample proportion and \( n \) is the sample size. Substituting our values:
\[ SE = \sqrt{\frac{0.824 \times (1-0.824)}{699}} \approx 0.0144 \]
Having a smaller standard error means our sample proportion is a more accurate estimator of the population proportion, which increases the reliability of our confidence interval.
Margin of Error
The margin of error is often seen on media reports or survey findings; it is a vital tool for representing the uncertainty in sampling. It quantifies the range within which we expect the true population proportion to lie, given a specified confidence level.
To compute the margin of error, use the formula:
\[ ME = z^* \times SE \]
Where \( z^* \) is the critical value associated with your chosen level of confidence—in this case, 99%. Having a larger \( z^* \) value leads to a wider margin because higher confidence levels require us to account for more variation.
For our example:
\[ ME = 2.576 \times 0.0144 \approx 0.0371 \]
Thus, our confidence interval around the sample proportion, \( 0.824 \), is 0.7869 to 0.8611 after adjusting for the margin of error. This interval provides a reliable statistical estimate of where the true population proportion lies.

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