/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Catalog mail-order sales A compa... [FREE SOLUTION] | 91Ó°ÊÓ

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Catalog mail-order sales A company that sells its products through mail-order catalogs wants information about the success of its most recent catalog. The company decides to estimate the mean dollar amount of items ordered from those who received the catalog. For a random sample of 100 customers from their files, only 5 made an order, so 95 of the response values were $$\$ 0 .$$ The overall mean of all 100 orders was $$\$ 10,$$ with a standard deviation of $$\$ 10 .$$ a. Is it plausible that the population distribution is normal? Explain, and discuss how much this affects the validity of a confidence interval for the mean. b. Find a \(95 \%\) confidence interval for the mean dollar order for the population of all customers who received this catalog. Normally, the mean of their sales per catalog is about \(\$ 15\), Can we conclude that it declined with this catalog? Explain.

Short Answer

Expert verified
The distribution is not normal, affecting reliability. The 95% confidence interval is (8.04, 11.96), indicating a decline from $15.

Step by step solution

01

Assess Normality of Distribution

The population distribution is not likely normal because 95% of the responses are zero, which means a large skew in data. A normal distribution would have data more symmetrically distributed around the mean. This skewness violates the assumption of normality, potentially affecting the reliability of any confidence interval estimation.
02

Calculate Standard Error

Given the sample standard deviation (\[s = 10\]) and sample size (\[n = 100\]), we calculate the standard error (SE) as:\[SE = \frac{s}{\sqrt{n}} = \frac{10}{\sqrt{100}} = 1\].
03

Compute Critical Value for 95% Confidence

For a 95% confidence level, the critical z-value is approximately 1.96 because it corresponds to the 95% cumulative probability in a standard normal distribution.
04

Calculate the Confidence Interval

Use the formula for the confidence interval:\[ \text{Confidence Interval} = \bar{x} \pm z \times SE \]Substitute \(\bar{x} = 10\), \(z = 1.96\), and \(SE = 1\):\[ CI = 10 \pm 1.96 \times 1 = (8.04, 11.96)\].
05

Conclusion about Catalog Sales

The usual sales per catalog was $15, which lies outside the calculated confidence interval of ($8.04, $11.96). This suggests, with 95% confidence, that the mean dollar order for the population has declined. However, this result should be interpreted with caution due to the non-normal distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normality of Distribution
Understanding the normality of a distribution is important in statistics because many statistical techniques assume that data follows a normal distribution. A normal distribution, often depicted as a bell curve, is symmetrical around the mean and has most of its data points clustered close to the center. When data is not normally distributed, it may be skewed or have outliers, impacting the validity of statistical conclusions drawn from such data.

In the case of the mail-order company, most customers did not place an order, resulting in a lot of zero-dollar entries. This creates a skewed distribution rather than a normal one, as the majority of data points are at the lower end of the scale. Because the distribution is not normal, it can affect the reliability of statistical methods like calculating a confidence interval. Therefore, it is essential to examine the distribution first to assess if adjustments or different methods are needed.
Confidence Interval
A confidence interval provides a range of values within which we can expect a population parameter, like the mean, to lie. It’s helpful because it gives an estimate of uncertainty associated with sample data. The wider the confidence interval, the less precise the estimate is. The level of confidence, often expressed as a percentage like 95%, indicates the probability that the interval contains the true parameter value.

For the company's catalog sales problem, calculating a 95% confidence interval for the mean order value involves determining how far above and below the sample mean the true mean population order could be. This interval suggests where the true mean might fall, considering sample variability. In this exercise, the confidence interval was \(8.04, 11.96\), which means the company can be 95% confident that the true mean order amount lies within this range.
  • Calculate Standard Error (SE) to assess variability: \[SE = \frac{s}{\sqrt{n}} = \frac{10}{\sqrt{100}} = 1\]
  • Identify the critical value (z) for desired confidence level: typically 1.96 for 95%
  • Apply the formula: \[CI = \bar{x} \pm z \times SE\]
Despite having this calculated, the non-normal distribution of the data can affect the reliability of the interval.
Population Distribution
In statistics, population distribution refers to the distribution of all possible values or scores of a specific variable for everyone of interest. It provides a complete picture of the variable's behavior in a wider context. This is in contrast to a sample distribution, which considers only a subset of the whole population.

Population distribution helps in understanding overall tendencies and variability. In cases where the distribution is very skewed, like the mail-order example, it signals the real-world behavior that needs to be considered in analysis. The sample mean does not always reflect the population mean accurately when the distribution is not normal, meaning there's a risk of underestimating or overestimating key measures.

Analyzing population distribution is foundational in deciding the statistical methods to implement, ensuring that results are reliable and applicable to the population at large.

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Most popular questions from this chapter

Width of a confidence interval Why are confidence intervals wider when we use larger confidence levels but narrower when we use larger sample sizes, other things being equal?

Wage discrimination? According to a union agreement, the mean income for all senior-level assembly-line workers in a large company equals $$\$ 500$$ per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. For a random sample of nine female employees, using software she obtains a \(95 \%\) confidence interval of (371,509) . Explain what is wrong with each of the following interpretations of this interval. a. We infer that \(95 \%\) of the women in the population have income between $$\$ 371$$ and $$\$ 509$$ per week. b. If random samples of nine women were repeatedly selected, then \(95 \%\) of the time the sample mean income would be between \(\$ 371\) and \(\$ 509\). c. We can be \(95 \%\) confident that \(\bar{x}\) is between \(\$ 371\) and \(\$ 509\). d. If we repeatedly sampled the entire population, then \(95 \%\) of the time the population mean would be between $$\$ 371$$ and $$\$ 509$$

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General electric stock volume Example 7 analyzed the trading volume of shares of General Electric stock between February and April 2011. Summary statistics of the data were calculated using MINITAB and are shown below: The \(95 \%\) confidence intervals for the means are \((40.2685 .\) 63.3679 ) for Monday's volume and (42.7963,57.2037) for Friday's. Interpret each of these intervals, and explain what you learn by comparing them.

Bootstrap the proportion We want a \(95 \%\) confidence interval for the population proportion of students in a high school in Dallas, Texas, who can correctly find Iraq on an unlabeled globe. For a random sample of size 50,10 get the correct answer. a. Using software or the Sampling Distributions applet on the text \(\mathrm{CD},\) set the population menu to Binary and treat the sample proportion as the population proportion by setting the proportion parameter to \(0.20=10 / 50\) (Binary: \(p=0.2\) ). Take a random sample of size \(50,\) and find the sample proportion of correct answers. b. Take 100 resamples like the one in part a, each time calculating the sample proportion. Take one sample at a time, recording each sample proportion. Now, construct a \(90 \%\) confidence interval by identifying the 5 th and 95 th percentiles of the sample proportions. This is the \(90 \%\) bootstrap confidence interval. c. Explain why the sample proportion does not fall exactly in the middle of the bootstrap confidence interval. (Hint: Is the sampling distribution symmetric or skewed?)

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