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Abstainers The Harvard study mentioned in the previous exercise estimated that \(19 \%\) of college students abstain from drinking alcohol. To estimate this proportion in your school, how large a random sample would you need to estimate it to within 0.05 with probability \(0.95,\) if before conducting the study a. You are unwilling to predict the proportion value at your school. b. You use the Harvard study as a guideline. c. Use the results from parts a and \(\mathrm{b}\) to explain why strategy (a) is inefficient if you are quite sure you'll get a sample proportion that is far from \(0.50 .\)

Short Answer

Expert verified
Part a: 385 samples; Part b: 237 samples; Strategy (a) is inefficient if you expect the proportion to be far from 0.50.

Step by step solution

01

Understanding the Problem

We need to calculate the sample size required to estimate a population proportion with a specific confidence level and margin of error. The margin of error is given as 0.05 and the confidence level is 0.95.
02

Using No Prior Estimate (Part a)

When you cannot predict the proportion, the safest approach is to assume the most uncertain case, which is the proportion to be 0.5. The formula for the sample size needed is \( n = \frac{Z^2 \cdot p \cdot (1-p)}{E^2} \), where \( Z \) is the Z-score for 95% confidence (1.96), \( p = 0.5 \), and \( E = 0.05 \).
03

Calculate Sample Size for Part a

Substitute the values into the formula: \[ n = \frac{1.96^2 \cdot 0.5 \cdot (1-0.5)}{0.05^2} = \frac{3.8416 \cdot 0.25}{0.0025} = \frac{0.9604}{0.0025} = 384.16 \]Therefore, you need a sample size of approximately 385.
04

Using Harvard Study Estimate (Part b)

Using the Harvard study's proportion of 19% or 0.19, substitute this into the sample size formula: \[ n = \frac{1.96^2 \cdot 0.19 \cdot (1-0.19)}{0.05^2} = \frac{3.8416 \cdot 0.19 \cdot 0.81}{0.0025} \]
05

Calculate Sample Size for Part b

Continuing from Step 4, calculate: \[ n = \frac{3.8416 \cdot 0.1539}{0.0025} = \frac{0.59069024}{0.0025} = 236.276096 \]Therefore, a sample size of approximately 237 is required.
06

Strategy Comparison (Part c)

Strategy (a) which assumes a proportion of 0.5 leads to a larger sample size (385) compared to strategy (b) using a more accurate guess (237). If you have a reasonable estimate of the proportion, strategy (b) is more efficient as it requires fewer samples.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
Understanding population proportion is essential in statistics, especially when estimating or predicting outcomes based on a sample. Population proportion, denoted as \( p \), refers to the fraction of a population that exhibits a particular characteristic. For instance, if we consider a study about students abstaining from alcohol, this proportion would represent the percentage of students who don't drink.

When conducting studies or surveys, knowing your population proportion helps in making accurate predictions and decisions. However, sometimes the actual proportion isn't known beforehand, like in initial stages of certain research studies, requiring estimations based on sample data or assumptions. Such estimations become particularly crucial when calculating sample sizes for new research, as they directly affect the resources and time invested in the study.

Remember, an accurate population proportion can lead to more reliable survey results, better predictions, and more efficient use of resources.
Margin of Error
The Margin of Error (MoE) is a key statistical concept that expresses the amount of random sampling error in a survey's results. It provides a range that you expect the true population parameter to fall within, based on the sample data. For example, if a study states that 20% of college students abstain from alcohol with a margin of error of \(0.05\), this indicates that the true proportion of abstainers lies between 15% to 25%.

The margin of error is crucial for interpreting the reliability and accuracy of survey results. A smaller margin indicates more precision, which is typically achieved with a larger sample size. Thus, determining the appropriate margin of error is essential when planning a survey or research, as it balances between the desired precision and available resources. By setting a stricter margin of error, researchers can identify the required sample size and manage the scope of the study effectively while ensuring valid and trustworthy conclusions.
Confidence Level
In statistics, the confidence level represents the degree of certainty we have that a particular parameter falls within the specified range determined by the margin of error. Commonly used confidence levels are 90%, 95%, and 99%, with higher percentages indicating greater confidence in the interval estimate.

For example, a confidence level of 95% implies that if the survey were conducted 100 times, the results would fall within the margin of error 95 times out of 100. In a sense, it measures the reliability of the estimation process. Choosing the right confidence level depends on the field of study and the acceptable risk threshold for error. Applications demanding precision, such as medical or safety studies, often use higher confidence levels.

Achieving a particular confidence level requires balancing the sample size and margin of error; a higher confidence level generally necessitates a larger sample size to ensure results accuracy.
Z-score
The Z-score is a statistical measurement that describes the relation of a data point to the mean of a group of points. In sample size calculations, it is used to identify the required sample size given a specific confidence level. The Z-score relates to the standard normal distribution, where different Z-values correspond to probability areas under the curve.

For a 95% confidence level, the Z-score is approximately 1.96. This score captures the central 95% of the normal distribution curve, indicating where sample estimates should be located within the population's range. Understanding Z-scores is critical as they directly influence the sample size; a higher Z-score (higher confidence level) typically necessitates a greater sample size.

Thus, Z-scores bridge the theoretical statistical concepts with practical survey needs, helping researchers understand variations and the potential variability in their estimates.

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Most popular questions from this chapter

Width of a confidence interval Why are confidence intervals wider when we use larger confidence levels but narrower when we use larger sample sizes, other things being equal?

t-scores a. Show how the \(t\) -score for a \(95 \%\) confidence interval changes as the sample size increases from 10 to 20 to 30 to infinity. b. What does the answer in part a suggest about how the \(t\) distribution compares to the standard normal distribution?

Mean property tax A tax assessor wants to estimate the mean property tax bill for all homeowners in Madison, Wisconsin. A survey 10 years ago got a sample mean and standard deviation of \(\$ 1400\) and \(\$ 1000\). a. How many tax records should the tax assessor randomly sample for a \(95 \%\) confidence interval for the mean to have a margin of error equal to \(\$ 100 ?\) What assumption does your solution make? b. In reality, suppose that they'd now get a standard deviation equal to \(\$ 1500 .\) Using the sample size you derived in part a, without doing any calculation, explain whether the margin of error for a \(95 \%\) confidence interval would be less than \(\$ 100\), equal to \(\$ 100\), or more than \(\$ 100\). c. Refer to part b. Would the probability that the sample mean falls within \(\$ 100\) of the population mean be less than \(0.95,\) equal to \(0.95,\) or greater than \(0.95 ?\) Explain.

Driving after drinking In December \(2004,\) a report based on the National Survey on Drug Use and Health estimated that \(20 \%\) of all Americans of ages 16 to 20 drove under the influence of drugs or alcohol in the previous year (AP, December 30,2004 ). A public health unit in Wellington, New Zealand, plans a similar survey for young people of that age in New Zealand. They want a \(95 \%\) confidence interval to have a margin of error of 0.04 . a. Find the necessary sample size if they expect results similar to those in the United States. b. Suppose that in determining the sample size, they use the safe approach that sets \(\hat{p}=0.50\) in the formula for \(n\). Then, how many records need to be sampled? Compare this to the answer in part a. Explain why it is better to make an educated guess about what to expect for \(\hat{p},\) when possible.

Population data You would like to find the proportion of bills passed by Congress that were vetoed by the president in the last congressional session. After checking congressional records, you see that for the population of all 40 bills passed, 15 were vetoed. Does it make sense to construct a confidence interval using these data? Explain. (Hint: Identify the sample and population.)

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