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Aunt Erma's restaurant In Example 5 about Aunt Erma's Restaurant, the daily sales follow a probability distribution that has a mean of \(\mu=\$ 900\) and a standard deviation of \(\sigma=\$ 300\). This past week the daily sales for the seven days had a mean of \(\$ 980\) and a standard deviation of \(\$ 276\). a. Identify the mean and standard deviation of the population distribution. b. Identify the mean and standard deviation of the data distribution. What does the standard deviation describe? c. Identify the mean and the standard deviation of the sampling distribution of the sample mean for samples of seven daily sales. What does this standard deviation describe?

Short Answer

Expert verified
a. Mean = $900, SD = $300; b. Mean = $980, SD = $276; c. Mean = $900, SD ≈ $113.38.

Step by step solution

01

Identify Population Parameters

The population distribution's mean is given by \(\mu = \\(900\) and the standard deviation by \(\sigma = \\)300\). These parameters describe the expected average daily sales and the variability of sales in Aunt Erma's restaurant over a long period.
02

Identify Sample Data Parameters

The mean of the data distribution (sample) is \(\\(980\) and the standard deviation is \(\\)276\). Here, the sample mean measures the average sales observed from the past week, and the sample standard deviation shows how the sales varied around this mean during these seven days.
03

Calculate Sampling Distribution Parameters

For a sample size of 7, the mean of the sampling distribution of the sample mean is the same as the population mean, \(\mu = \\(900\). The standard deviation of the sampling distribution (also known as the standard error) is calculated as \( \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} = \frac{300}{\sqrt{7}} \approx \\)113.38\). This standard deviation describes the variability of sample means one would expect when repeatedly taking samples of 7 days from the population.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Distribution
In the world of statistics, population distribution refers to the spread of values or data points across an entire population. The population is defined as the whole set of items or events that are of interest. For Aunt Erma's restaurant, the population distribution is illustrated through key statistical measures: the mean and standard deviation.
The mean of the population distribution, denoted as \(\mu\), is known as the central or expected value. In this example, it stands at \(\mu = 900\), indicating that, over time, the average daily sales are expected to be \(900. The mean provides a baseline expectation for what Aunt Erma's sales look like across all days.
The standard deviation, represented by \(\sigma\), gives insights into how the sales figures might scatter around the mean. Here, the standard deviation is \(\sigma = 300\). This implies that, while the average is \)900, sales can significantly vary, typically by about $300 more or less, from that average. In essence, a larger standard deviation indicates more variability in sales.
Sample Distribution
Sample distribution concerns the data obtained from a specific sample taken from the population. A sample is a smaller group chosen from the population at large, often representing the whole.
A vital aspect of understanding sample distribution involves calculating the sample mean and standard deviation. For the week's sales at Aunt Erma's, the sample mean is $980, which is slightly higher than the population mean. This could suggest An especially good week or just the natural variability from sampling.
The sample standard deviation is $276, which quantifies the spread of sales values during this week. It tells us how much Aunt Erma's sales diverged from the sample mean of $980. A smaller standard deviation would indicate tighter consistency in daily sales values around the mean, while a larger one suggests greater variability.
Sampling Distribution
Sampling distribution refers to the probability distribution of a statistic obtained through a large number of samples drawn from a population. This concept is especially important when looking to infer population parameters from sample statistics.
The mean of the sampling distribution of the sample mean aligns with the population mean. So, in Aunt Erma's case, even with fluctuating daily sales, the expected sample mean remains $900. It shows that when you take numerous small samples, the average of their means should concur with the population mean provided the sampling is adequate.
Another critical measure is the standard deviation of the sampling distribution, known as the standard error. This specific standard deviation calculates as \(\sigma_{\bar{x}} = \frac{300}{\sqrt{7}} \approx 113.38\). The standard error highlights how much variability we might expect in the sample mean, making it essential when determining the reliability of the sample mean. A lower standard error implies greater accuracy in using the sample mean to infer the population mean.

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Most popular questions from this chapter

Baseball hitting Suppose a baseball player has a 0.200 probability of getting a hit in each time at-bat. a. Describe the shape, mean, and standard deviation of the sampling distribution of the proportion of times the player gets a hit after 36 at- bats. b. Explain why it would not be surprising if the player has a 0.300 batting average after 36 at-bats.

Comparing pizza brands \(\quad\) The owners of Aunt Erma's Restaurant plan an advertising campaign with the claim that more people prefer the taste of their pizza (which we'll denote by A) than the current leading fast-food chain selling pizza (which we'll denote by \(\mathrm{D}\) ). To support their claim, they plan to randomly sample three people in Boston. Each person is asked to taste a slice of pizza \(A\) and a slice of pizza \(D\). Subjects are blindfolded so they cannot see the pizza when they taste it, and the order of giving them the two slices is randomized. They are then asked which pizza tastes better. Use a symbol with three letters to represent the responses for each possible sample. For instance, ADD represents a sample in which the first subject sampled preferred pizza \(A\) and the second and third subjects preferred pizza \(\mathrm{D}\) a. Identify the eight possible samples of size \(3,\) and for each sample report the proportion that preferred pizza \(A\). b. In the entire Boston population, suppose that exactly half would prefer pizza \(\mathrm{A}\) and half would prefer pizza D. Explain why the sampling distribution of the sample proportion who prefer Aunt Erma's pizza, when \(n=3,\) is \begin{tabular}{cc} \hline Sample Proportion & Probability \\ \hline 0 & \(1 / 8\) \\ \(1 / 3\) & \(3 / 8\) \\ \(2 / 3\) & \(3 / 8\) \\ 1 & \(1 / 8\) \\ \hline \end{tabular} c. In part b, we can also find the probabilities for each possible sample proportion value using the binomial distribution. Use the binomial with \(n=3\) and \(p=0.50\) to show that the probability of a sample proportion of \(1 / 3\) equals \(3 / 8 .\) (Hint: This equals the probability that \(x=1\) person out of \(n=3\) prefer pizza A. It's especially helpful to use the binomial formula when \(p\) differs from \(0.50,\) since then the eight possible samples listed in part a would not be equally likely.)

Physicians' assistants The 2006 AAPA survey of the population of physicians' assistants who were working full time reported a mean annual income of \(\$ 84,396\) and standard deviation of \(\$ 21,975 .\) (Source: Data from 2006 AAPA survey [www.apa.org].) a. Suppose the AAPA had randomly sampled 100 physicians' assistants instead of collecting data for all of them. Describe the mean, standard deviation, and shape of the sampling distribution of the sample mean. b. Using this sampling distribution, find the \(z\) -score for a sample mean of \(\$ 80,000\) c. Using parts a and b, find the probability that the sample mean would fall within approximately \(\$ 4000\) of the population mean.

Syracuse full-time students You'd like to estimate the proportion of the 14,201 (www.syr.edu/about/facts .html) undergraduate students at Syracuse University who are full-time students. You poll a random sample of 100 students, of whom 94 are full-time. Unknown to you, the proportion of all undergraduate students who are fulltime students is \(0.951 .\) Let \(X\) denote a random variable for which \(x=1\) denotes full-time student and for which \(x=0\) denotes part-time student. a. Describe the data distribution. Sketch a graph representing the data distribution. b. Describe the population distribution. Sketch a graph representing the population distribution. c. Find the mean and standard deviation of the sampling distribution of the sample proportion for a sample of size \(100 .\) Explain what this sampling distribution represents. Sketch a graph representing this sampling distribution.

Standard deviation of a proportion Suppose \(x=1\) with probability \(p,\) and \(x=0\) with probability \((1-p) .\) Then, \(x\) is the special case of a binomial random variable with \(n=1,\) so that \(\sigma=\sqrt{n p(1-p)}=\sqrt{p(1-p)} .\) With \(n\) trials, using the formula \(\sigma / \sqrt{n}\) for a standard deviation of a sample mean, explain why the standard deviation of a sample proportion equals \(\sqrt{p(1-p) / n}\)

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