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Exit poll CNN conducted an exit poll of 1751 voters in the 2010 Senatorial election in New York between Charles Schumer and Jay Townsend. It is possible that all 1751 voters sampled happened to be Charles Schumer supporters. Investigate how surprising this would be, if actually \(65 \%\) of the population voted for Schumer, by a. Finding the probability that all 1751 people voted for Schumer. (Hint: Use the binomial distribution.) b. Finding the number of standard deviations that a sample proportion of 1.0 for 1751 voters falls from the population proportion of \(0.65 .\)

Short Answer

Expert verified
The probability is nearly zero, and the Z-score is very high, indicating a highly unlikely event.

Step by step solution

01

Understand the Binomial Distribution

To determine the probability of a specific number of voters (out of 1751) supporting Schumer, we can model this situation using a binomial distribution. The probability mass function for a binomial distribution is given by: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \), where \( n \) is the number of trials, \( k \) is the number of successes, and \( p \) is the probability of success on an individual trial.
02

Calculate Probability All Voted for Schumer

Here, the probability \( p \) that a person voted for Schumer is 0.65, with \( n = 1751 \) voters, and \( k = 1751 \) successes (all voted for Schumer). Using the binomial probability formula, we get: \[ P(X = 1751) = \binom{1751}{1751} (0.65)^{1751} (1-0.65)^{0} = (0.65)^{1751} \].
03

Plug in Values and Compute

Compute \( (0.65)^{1751} \). This value is so small it approaches zero, indicating it's exceedingly unlikely.
04

Understand Standard Deviations from Mean

When assessing how a result compares to the expected result, we can use the formula for the standard deviation of a sample proportion: \( \sigma = \sqrt{\frac{p(1-p)}{n}} \). Use this to find how far the sample proportion of 1.0 deviates from the population proportion of 0.65.
05

Compute Standard Deviation

Substitute \( p = 0.65 \) and \( n = 1751 \) into the formula \( \sigma = \sqrt{\frac{0.65 \times 0.35}{1751}} \) to get the value for standard deviation.
06

Calculate Z-Score

The Z-score measures how many standard deviations the sample proportion \( \, \hat{p} = 1.0 \, \) is from the population proportion. Use the formula \( Z = \frac{\hat{p} - p}{\sigma} \) where \( \, \hat{p} = 1.0 \, \), \( \sigma \) from Step 5, and \( p = 0.65 \), to find the Z-score.
07

Conclusion

The probability that all 1751 voters voted for Schumer is nearly zero, and a sample proportion of 1.0 is many standard deviations away from 0.65, suggesting it would be extremely surprising if all supported Schumer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability helps us understand how likely it is that a certain event will occur. In the context of the exit poll, we want to know the likelihood that all 1751 voters support Charles Schumer given that 65% of the overall population does so. In this case, the binomial distribution is the tool we use. It's perfect for scenarios that involve a fixed number of independent trials, like casting a vote.

The probability formula for a binomial distribution is:
  • \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \)
Here, \( n \) is the number of trials (voters), \( k \) is the exact number of successes we care about (all voters choosing Schumer), and \( p \) is the probability of success on each trial (the chance a single voter supports Schumer).

For the scenario given, \( n = 1751 \) and \( k = 1751 \), which means we're calculating the probability that every single one of the 1751 voters picked Schumer. Plug in the respective values to find:
  • \( P(X = 1751) = (0.65)^{1751} \)
This probability is so tiny, it is almost zero, emphasizing that such an outcome is nearly impossible.
Standard Deviation
Standard deviation measures the amount of variation or dispersion in a set of values. When working with proportions, standard deviation tells us how much the sample proportion could fluctuate around the population proportion. In the exit poll example, we use it to see how much the sample proportion of those who support Schumer (hypothetically 1.0) deviates from the known population proportion of 0.65.

The formula to calculate the standard deviation of a sample proportion is:
  • \( \sigma = \sqrt{\frac{p(1-p)}{n}} \)
Where \( p \) is the population proportion and \( n \) is the sample size (1751 voters).

By substituting \( p = 0.65 \) and \( n = 1751 \), we can compute the standard deviation. This calculation helps to understand the expected range of sample proportions due to random sampling. Knowing the standard deviation prepares us to assess unusual results effectively.
Z-Score
A Z-score quantifies how far away a particular measurement is from the mean, in terms of standard deviations. In the case of the exit poll, it indicates how extreme having all 1751 voters support Schumer is relative to what is expected, based on the population proportion.

The formula for the Z-score is:
  • \( Z = \frac{\hat{p} - p}{\sigma} \)
In this formula, \( \hat{p} = 1.0 \) is the sample proportion of voters for Schumer, \( p = 0.65 \) is the expected proportion, and \( \sigma \) is the standard deviation we computed earlier.

Calculating the Z-score with these values gives us an insight into how unusual the result is. A high Z-score means that all voters supporting Schumer is far from the expected proportion, highlighting the rarity and significance of such an outcome.

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Most popular questions from this chapter

Education of the self-employed According to a recent Current Population Reports, the population distribution of number of years of education for self- employed individuals in the United States has a mean of 13.6 and a standard deviation of 3.0 . a. Identify the random variable \(X\) whose population distribution is described here. b. Find the mean and standard deviation of the sampling distribution of \(\bar{x}\) for a random sample of size 100 . Interpret the results. c. Repeat part b for \(n=400 .\) Describe the effect of increasing \(n\).

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Basketball shooting In college basketball, a shot made from beyond a designated arc radiating about 20 feet from the basket is worth three points, instead of the usual two points given for shots made inside that arc. Over his career, University of Florida basketball player Lee Humphrey made \(45 \%\) of his three-point attempts. In one game in his final season, he made only 3 of 12 three-point shots, leading a TV basketball analyst to announce that Humphrey was in a shooting slump. a. Assuming Humphrey has a \(45 \%\) chance of making any particular three-point shot, find the mean and standard deviation of the sampling distribution of the proportion of three-point shots he will make out of 12 shots. b. How many standard deviations from the mean is this game's result of making 3 of 12 three-point shots? c. If Humphrey was actually not in a slump but still had a \(45 \%\) chance of making any particular three-point shot, explain why it would not be especially surprising for him to make only 3 of 12 shots. Thus, this is not really evidence of a shooting slump.

Aunt Erma's restaurant In Example 5 about Aunt Erma's Restaurant, the daily sales follow a probability distribution that has a mean of \(\mu=\$ 900\) and a standard deviation of \(\sigma=\$ 300\). This past week the daily sales for the seven days had a mean of \(\$ 980\) and a standard deviation of \(\$ 276\). a. Identify the mean and standard deviation of the population distribution. b. Identify the mean and standard deviation of the data distribution. What does the standard deviation describe? c. Identify the mean and the standard deviation of the sampling distribution of the sample mean for samples of seven daily sales. What does this standard deviation describe?

Other scenario for exit poll Refer to Examples 1 and 2 about the exit poll, for which the sample size was \(3889 . \mathrm{In}\) that election, \(40.9 \%\) voted for Whitman. a. Define a binary random variable \(X\) taking values 0 and 1 that represents the vote for a particular voter \((1=\) vote for Whitman and \(0=\) another candidate \()\) State its probability distribution, which is the same as the population distribution for \(X\). b. Find the mean and standard deviation of the sampling distribution of the proportion of the 3889 people in the sample who voted for Whitman.

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