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91Ó°ÊÓ

For students who take Statistics 101 at Lake Wobegon College in Minnesota, both the midterm and final exams have mean \(=75\) and standard deviation \(=10 .\) The professor explores using the midterm exam score to predict the final exam score. The regression equation relating \(y=\) final exam score to \(x=\) midterm exam score is \(\hat{y}=30+0.60 x\). a. Find the predicted final exam score for a student who has (i) midterm score \(=100,\) (ii) midterm score \(=50\). Note that in each case the predicted final exam score regresses toward the mean of \(75 .\) (This is a property of the regression equation that is the origin of its name, as Chapter 12 will explain.) b. Show that the correlation equals 0.60 and interpret it. (Hint: Use the relation between the slope and correlation.)

Short Answer

Expert verified
Predicted scores: (i) 90, (ii) 60. Correlation: 0.60, indicating moderate positive relationship.

Step by step solution

01

Understand the Regression Equation

The regression equation given is \(\hat{y} = 30 + 0.60x\). Here, \(\hat{y}\) is the predicted final exam score, and \(x\) is the midterm exam score. The coefficient 30 is the intercept, and 0.60 is the slope which indicates the expected increase in the final exam score for every one-point increase in the midterm score.
02

Predict Final Exam Score for Midterm Score = 100

Substitute \(x = 100\) into the regression equation \(\hat{y} = 30 + 0.60x\). This gives:\[ \hat{y} = 30 + 0.60 \times 100 = 30 + 60 = 90 \]Therefore, the predicted final exam score for a midterm score of 100 is 90.
03

Predict Final Exam Score for Midterm Score = 50

Substitute \(x = 50\) into the regression equation \(\hat{y} = 30 + 0.60x\). This gives:\[ \hat{y} = 30 + 0.60 \times 50 = 30 + 30 = 60 \]Therefore, the predicted final exam score for a midterm score of 50 is 60.
04

Understanding Regression towards the Mean

In regression, predictions tend to pull toward the mean of the distribution (75 in this case). Hence, extreme midterm scores (like 100 or 50) result in predicted final scores (90 or 60) that are closer to the mean.
05

Verify Correlation Using Slope

The regression slope \(b = 0.60\) is related to the correlation \(r\) by the formula \(b = r \cdot \frac{s_y}{s_x}\), where \(s_y\) and \(s_x\) are the standard deviations of \(y\) and \(x\), both equal to 10 here. Rearrange to solve for \(r\):\[ r = b \cdot \frac{s_x}{s_y} = 0.60 \times \frac{10}{10} = 0.60 \]Thus, the correlation is 0.60.
06

Interpret the Correlation

A correlation of 0.60 indicates a moderate positive linear relationship between midterm and final exam scores. As midterm scores increase, we expect final scores to increase as well, but not perfectly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Correlation Coefficient
The correlation coefficient, often represented by the symbol \( r \), is a crucial statistic within regression analysis. It measures the strength and direction of a linear relationship between two variables. In our example, this is between the midterm and final exam scores.
The correlation coefficient ranges from -1 to 1. A value of 0.60, as seen here, tells us that there is a moderate positive relationship. This indicates that if a student's midterm score increases, we expect their final score to rise as well. However, it's important to remember that this relationship is not perfect due to the less than maximum value of 1.
This value can provide us with confidence in using midterm scores as a predictor for final scores, as the positive correlation suggests a direct relationship. Still, we must consider that a considerable part of final scores' variability remains unexplained by midterm scores alone.
Decoding the Regression Equation
In this exercise, the regression equation \( \hat{y} = 30 + 0.60x \) serves as a predictive formula. It's a simple yet valuable tool for making predictions based on a linear relationship.

The equation consists of two main parts: the intercept (30) and the slope (0.60). The intercept represents the point where the regression line crosses the y-axis. In practical terms, it indicates the predicted final exam score for a student who scores zero on the midterm, although this scenario may not be realistic here.
The slope of 0.60 tells us the expected increase in the final exam score for each additional point scored on the midterm. If a student improved their midterm score by 1 point, their final exam score would be predicted to increase by 0.60 points.
This equation thus helps in drawing meaningful conclusions and predictions about student performance, showing the significance of understanding the parameters within a regression equation.
The Role of Predictive Modeling
Predictive modeling, a key concept in statistics, uses mathematical and statistical techniques to predict future outcomes. In our scenario, the regression equation acts as a predictive model to forecast final exam scores based on midterm scores.

Such models are crucial in various fields beyond education. They help businesses project sales, meteorologists predict weather conditions, and economists foresee market trends.
Here, by inputting a known midterm score into the equation, we can predict the final score. The consistency and accuracy of such predictions depend on the data quality and relationship strength, reflected by the correlation coefficient.
Effective predictive modeling aids in decision-making and planning, offering insights and expectations for future outcomes based on existing data. However, it's important to note that predictions are not guarantees, as they are influenced by many factors. Thus, while useful, predictions should be viewed with an understanding of their limitations.
Exploring Regression toward the Mean
Regression toward the mean is a phenomenon that occurs in statistics when extreme values tend to drift towards the average in subsequent measurements. In the context of our exercise, this means students with extremely high or low midterm scores will likely have final scores closer to the mean.

This concept explains why the predicted final scores for students with midterm scores of 100 and 50 regress toward the mean of 75. The score of 100 predicts a final score of 90, while 50 predicts 60. Both are nearer to the average than the original scores, illustrating regression toward the mean.
This property is crucial in understanding how predictions behave in the presence of outliers or extreme values. It indicates that extreme performances often normalize over time or subsequent evaluations.
Regression toward the mean highlights the stabilizing nature of averages and is key in many fields, explaining occurrences from sports performances to scientific measurements.

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Most popular questions from this chapter

In 2015, eighth-grade math scores on the National Assessment of Educational Progress had a mean of 283.56 in Maryland compared to a mean of 284.37 in Connecticut (Source: http://nces.ed.gov/nationsreportcard/ naepdata/dataset.aspx). a. Identify the response variable and the explanatory variable. b. The means in Maryland were respectively \(274,284,285,\) 291 and 294 for people who reported the number of pages read in school and for homework, respectively as \(0-5,6-10,11-15,15-20\) and 20 or more. These means were 270,281,284,289 and 293 in Connecticut. Identify the third variable given here. Explain how it is possible for Maryland to have the higher mean for each class, yet for Connecticut to have the higher mean when the data are combined. (This is a case of Simpson's paradox for a quantitative response.)

Each month, the owner of Fay's Tanning Salon records in a data file the monthly total sales receipts and the amount spent that month on advertising. a. Identify the two variables. b. For each variable, indicate whether it is quantitative or categorical. c. Identify the response variable and the explanatory variable.

Zagat restaurant guides publish ratings of restaurants for many large cities around the world (see www.zagat.com). The review for each restaurant gives a verbal summary as well as a 0 - to 30 -point rating of the quality of food, décor, service, and the cost of a dinner with one drink and tip. For 31 French restaurants in Boston in \(2014,\) the food quality ratings had a mean of 24.55 and standard deviation of 2.08 points. The cost of a dinner (in U.S. dollars) had a mean of \(\$ 50.35\) and standard deviation of \(\$ 14.92\). The equation that predicts the cost of a dinner using the rating for the quality of food is \(\hat{y}=-70+4.9 x\). The correlation between these two variables is 0.68 . (Data available in the Zagat_Boston file.) a. Predict the cost of a dinner in a restaurant that gets the (i) lowest observed food quality rating of \(21,\) (ii) highest observed food quality rating of 28 . b. Interpret the slope in context. c. Interpret the correlation. d. Show how the slope can be obtained from the correlation and other information given.

In \(2014,\) the statistical summary of a weight loss survey was created and published on www.statcrunch.com. a. In this study, it seemed that the desired weight loss (in pounds) was a good predictor of the expected time (in weeks) to achieve the desired weight loss. Do you expect \(r^{2}\) to be large or small? Why? b. For this data, \(r=0.607\). Interpret \(r^{2}\). c. Show the algebraic relationship between the correlation of 0.607 and the slope of the regression equation \(b=0.437,\) using the fact that the standard deviations are 20.005 for pounds and 14.393 for weeks. (Hint: Recall that \(\left.=r \frac{s_{y}}{s_{x}} .\right)\)

Is there a relationship between how many sit-ups you can do and how fast you can run 40 yards? The EXCEL output shows the relationship between these variables for a study of female athletes to be discussed in Chapter 12 .a. The regression equation is \(\hat{y}=6.71-0.024 x .\) Find the predicted time in the 40 -yard dash for a subject who can do (i) 10 sit-ups, (ii) 40 sit-ups. Based on these times, explain how to sketch the regression line over this scatterplot. b. Interpret the \(y\) -intercept and slope of the equation in part a, in the context of the number of sit-ups and time for the 40 -yard dash. c. Based on the slope in part a, is the correlation positive or negative? Explain.

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