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Last month a random sample of 1000 subjects was interviewed and asked whether they thought the president was doing a good job. This month the same subjects were asked this again. The results are: 450 said yes each time, 450 said no each time, 60 said yes on the first survey and no on the second survey, and 40 said no on the first survey and yes on the second survey. a. Form a contingency table showing these results. b. Estimate the proportion giving a favorable rating (i) last month and (ii) this month. c. Show how each of the proportions in part b can be obtained as a sample mean. d. Find the test statistic and P-value for applying McNemar's test that the population proportion was the same each month. Interpret.

Short Answer

Expert verified
The proportions of favorable ratings were 0.51 last month and 0.49 this month, with a significant change indicated by McNemar's test at P = 0.0455.

Step by step solution

01

Organize Data into Contingency Table

We begin by formulating a 2x2 contingency table based on the given data. The rows will represent the first survey's results (Yes/No), and the columns will represent the second survey's results (Yes/No). The table should look like this: | | 2nd Survey: Yes | 2nd Survey: No | |------------------|-----------------|----------------| | 1st Survey: Yes | 450 | 60 | | 1st Survey: No | 40 | 450 | This table helps us visualize how subjects' opinions changed or remained the same over the two surveys.
02

Calculate Proportion of Favorable Ratings Last Month

To find the proportion of subjects who rated favorably last month, count the total number who said 'Yes' in the first survey and divide by the total number of subjects. From the contingency table:Number of 'Yes' last month = 450 (Yes both times) + 60 (Yes first, No second) = 510.The proportion is given by: \[ P_1 = \frac{510}{1000} = 0.51 \]
03

Calculate Proportion of Favorable Ratings This Month

Similarly, for this month, count the total number who said 'Yes' in the second survey and divide by the total number of subjects. From the contingency table:Number of 'Yes' this month = 450 (Yes both times) + 40 (No first, Yes second) = 490.The proportion is given by: \[ P_2 = \frac{490}{1000} = 0.49 \]
04

Express Proportions as Sample Means

The proportions calculated in Steps 2 and 3 can also be seen as sample means of an indicator variable that equals 1 if a subject favors and 0 otherwise. Therefore, the sample mean for last month and this month is effectively the same as the previously calculated proportions: For last month, the sample mean is 0.51, and for this month, it is 0.49.
05

Conduct McNemar's Test

McNemar's test is appropriate as it evaluates changes in responses over two paired observations. The test statistic is calculated using the formula:\[ \chi^2 = \frac{(b - c)^2}{b + c} \]where:\ b = 60 (Yes first, No second),\ c = 40 (No first, Yes second).Calculate \( \chi^2 \): \[ \chi^2 = \frac{(60 - 40)^2}{60 + 40} = \frac{400}{100} = 4 \]The P-value is determined using a chi-squared distribution with 1 degree of freedom. A \( \chi^2 \) of 4 gives a P-value of approximately 0.0455.
06

Interpretation of McNemar's Test

Since the P-value of 0.0455 is less than a typical significance level of 0.05, we reject the null hypothesis that there is no change in population proportions between the two months. This result suggests that there is a significant change in the subjects' opinions about the president's job performance over the two periods.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Estimation
The concept of proportion estimation is fundamental in statistics, especially when dealing with survey data. In the given exercise regarding the president's job approval ratings, we use proportion estimation to understand the percentage of people who gave a favorable rating in each of the surveys.To estimate the proportion from a given sample, we use the formula: \ \[ P = \frac{X}{n} \]where:
  • \(X\) is the number of favorable responses.
  • \(n\) is the total number of respondents sampled.
Last month, 510 individuals out of 1000 gave a positive response, so the proportion was calculated as \( P_1 = 0.51 \). This value informs us that 51% of the sample thought the president was doing a good job last month. For this month, 490 out of 1000 gave a positive response, resulting in a proportion of \( P_2 = 0.49 \), indicating 49% approval.Proportion estimation helps us track changes over time and is crucial for making inferences about the population's overall opinion based on our sample results. It simplifies real-world changes into measurable figures, allowing for easier comparison between different time periods or conditions.
McNemar's Test
McNemar's Test is a statistical test used on paired nominal data to determine if there are differences between paired proportions. In simple terms, it helps us understand if there's a significant change in opinions or characteristics measured at two points in time.In our scenario, McNemar's Test evaluates whether the proportion of people who approve of the president's performance is similar in both surveys. The data involves changes in responses: some people changed their opinion from "yes" to "no" or vice versa.The decision rule for McNemar’s Test is based on the test statistic formula:\[ \chi^2 = \frac{(b - c)^2}{b + c} \]where:
  • \(b\) is the number of people who said "yes" initially and "no" later (60 individuals in this case).
  • \(c\) is the number who switched from "no" to "yes" (40 individuals here).
Plugging in these values gives us \( \chi^2 = 4 \). We compare this to a chi-squared distribution with 1 degree of freedom to obtain the p-value. A p-value of 0.0455 indicates that the probability of observing such a shift in opinions purely by chance is relatively low.Since this p-value is less than 0.05, we reject the null hypothesis, concluding that there indeed was a significant change in opinions between the time frames studied. McNemar's Test is an invaluable tool when analyzing paired data to catch these nuanced shifts.
Sample Means
Sample means serve as indicators of central tendency in a dataset, providing an average value that represents the data. They are particularly useful when calculating proportions or when transforming categorical data, such as survey responses, into numerical analysis.In the context of proportion estimation like in our survey, the proportion calculated is analogous to a sample mean. This happens when we treat favorable responses as 1 and unfavorable as 0. As such, the sample mean directly corresponds to the proportion of favorable ratings.To illustrate: if 510 out of 1000 respondents provided a favorable rating last month, the sample mean of this indicator variable is:\[ \overline{X}_1 = \frac{510 \times 1 + 490 \times 0}{1000} = 0.51 \]Similarly, for this month, with 490 out of 1000 saying "yes," the sample mean becomes:\[ \overline{X}_2 = \frac{490 \times 1 + 510 \times 0}{1000} = 0.49 \]Thus, sample means provide a convenient way to view and understand proportion data. They summarize the aggregate statistics in surveys providing insights into behavioral or opinion trends over time. By viewing proportions as sample means, we simplify the interpretation of the data, making it easier to communicate the central findings.

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Most popular questions from this chapter

Anna's project for her introductory statistics course was to compare the selling prices of textbooks at two Internet bookstores. She first took a random sample of 10 textbooks used that term in courses at her college, based on the list of texts compiled by the college bookstore. The prices of those textbooks at the two Internet sites were Site \(\mathrm{A}: \$ 115, \$ 79, \$ 43, \$ 140, \$ 99, \$ 30, \$ 80, \$ 99, \$ 119, \$ 69\) Site B: \(\$ 110, \$ 79, \$ 40, \$ 129, \$ 99, \$ 30, \$ 69, \$ 99, \$ 109, \$ 66\) a. Are these independent samples or dependent samples? Justify your answer. b. Find the mean for each sample. Find the mean of the difference scores. Compare, and interpret. c. Using software or a calculator, construct a \(90 \%\) confidence interval comparing the population mean prices of all textbooks used that term at her college. Interpret.

As part of a class exercise, an instructor at a major university asks her students how many hours per week they spend on social networks. She wants to investigate if time spent on social networks differs for male and female students at this university. The results for those age 21 or under were: \(\begin{array}{ll}\text { Males: } & 5,7,9,10,12,12,12,13,13,15,15,20 \\\ \text { Females: } & 5,7,7,8,10,10,11,12,12,14,14,14,16,18, \\ & 20,20,20,22,23,25,40\end{array}\) a. Using software or a calculator, find the sample mean and standard deviation for each group. Interpret. b. Find the standard error for the difference between the sample means. c. Find and interpret a \(90 \%\) confidence interval comparing the population means.

The methods of this section make the assumption of a normal population distribution. Why do you think this is more relevant for small samples than for large samples?

The National Health Interview Survey conducted of 27,603 adults by the U.S. National Center for Health Statistics in 2009 indicated that \(20.6 \%\) of adults were current smokers. A similar study conducted in 1991 of 42,000 adults indicated that \(25.6 \%\) were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1991 and the proportion of current smokers in 2009 . b. A \(99 \%\) confidence interval for the true difference is \((0.042,0.058) .\) Interpret. c. What assumptions must you make for the interval in part b to be valid?

Childhood obesity continues to be a leading public health concern that disproportionately affects low-income and minority children. According to the National Center for Health Statistics, obesity prevalence among low-income, preschool-aged children increased steadily from \(12.4 \%\) in 1998 to \(14.5 \%\) in \(2003,\) but subsequently remained essentially the same, with a \(14.6 \%\) prevalence in 2008 . Compare the percentages for 1998 and 2008 using a ratio, and interpret.

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