/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Determine each of the following ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine each of the following areas under the standard normal (z) curve: a. To the left of -1.28 b. To the right of 1.28 c. Between -1 and 2 d. To the right of 0 e. To the right of -5 f. Between -1.6 and 2.5 g. To the left of 0.23

Short Answer

Expert verified
The areas under the standard normal curve for the given z-scores are: a. To the left of -1.28: \(0.1003\) b. To the right of 1.28: \(0.1003\) c. Between -1 and 2: \(0.8185\) d. To the right of 0: \(0.5\) e. To the right of -5: \(1\) f. Between -1.6 and 2.5: \(0.9390\) g. To the left of 0.23: \(0.5910\)

Step by step solution

01

Look up the z-score in the Z-table

Find the probability corresponding to z = -1.28 in a standard normal table. In this case, the value is approximately 0.1003.
02

Calculate the area to the left of -1.28

The value found in the Z-table represents the area to the left of z = -1.28. Thus, the desired area is 0.1003. #b. To the right of 1.28#
03

Look up the z-score in the Z-table

Find the probability corresponding to z = 1.28 in a standard normal table. In this case, the value is approximately 0.8997.
04

Calculate the area to the right of 1.28

Since the probability found represents the area to the left of z = 1.28, we need to find the complement by subtracting it from 1. Thus, the desired area is 1 - 0.8997 = 0.1003. #c. Between -1 and 2#
05

Look up the z-scores for -1 and 2 in the Z-table

Find the probabilities corresponding to z = -1 and z = 2 in a standard normal table. In this case, the values are approximately 0.1587 and 0.9772, respectively.
06

Calculate the area between -1 and 2

Since these probabilities represent the areas to the left of the z-scores, we subtract the smaller area from the larger one. Thus, the desired area is 0.9772 - 0.1587 = 0.8185. #d. To the right of 0#
07

Recall the properties of the standard normal curve

Since the curve is symmetric around the mean, which is 0, the area to the right of 0 is the same as the area to the left of 0.
08

Calculate the area to the right of 0

Since the area to the left of 0 is exactly 0.5 due to the symmetry, the area to the right of 0 is also 0.5. #e. To the right of -5#
09

Look up the z-score for -5

Find the probability corresponding to z = -5 in a standard normal table. In this case, the value is virtually 0, given that a z-score of -5 is extremely far to the left on the curve.
10

Calculate the area to the right of -5

Since the Z-table value represents the area to the left, we will find the complement by subtracting it from 1. Thus, the area to the right of -5 is approximately 1 - 0 = 1. #f. Between -1.6 and 2.5#
11

Look up the z-scores for -1.6 and 2.5 in the Z-table

Find the probabilities corresponding to z = -1.6 and z = 2.5 in a standard normal table. In this case, the values are approximately 0.0548 and 0.9938, respectively.
12

Calculate the area between -1.6 and 2.5

Subtract the smaller area from the larger one to get the desired area. Thus, the area between -1.6 and 2.5 is 0.9938 - 0.0548 = 0.9390. #g. To the left of 0.23#
13

Look up the z-score in the Z-table

Find the probability corresponding to z = 0.23 in a standard normal table. In this case, the value is approximately 0.5910.
14

Calculate the area to the left of 0.23

The value found in the Z-table represents the area to the left of z = 0.23. Thus, the desired area is 0.5910.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-score table
A z-score table, sometimes called a standard normal distribution table, is a tool commonly used in statistics to determine the probability that a standard normal variable (z) will be less than or equal to a certain value. The table shows the cumulative probability from the mean to any value on the standard normal curve.
Understanding how to read this table is crucial for solving many statistical problems. For a given z-score, the table provides the area under the curve to the left of that score.
To use the table:
  • Locate the row that matches the value of the z-score's first decimal place.
  • Find the column corresponding to the second decimal digit.
  • The intersection gives you the cumulative probability value from the mean to that z-score.

For example, a z-score of 1.28 corresponds to a cumulative probability of approximately 0.8997, indicating that the area to the left of 1.28 is 0.8997.
probability calculations
Probability calculations in the context of the standard normal distribution involve using z-scores to find the likelihood of a random variable falling within a specified range. Once you have these z-scores, you can look up their corresponding probabilities in the z-score table.
To calculate the probability of a specific range of z-scores:
  • Find the cumulative probability for each z-score at the ends of the range.
  • Subtract the smaller cumulative probability from the larger one.

For instance, to calculate the probability of z falling between -1 and 2, find probabilities for both z = -1 (approximately 0.1587) and z = 2 (approximately 0.9772). The probability of z being in that range is then 0.9772 - 0.1587 = 0.8185.
Such calculations help understand the likelihood of observed values occurring within a standard deviation range.
symmetry of normal curve
The symmetry of the normal curve is a fundamental property that simplifies many probability calculations. The normal distribution curve is symmetrical about its mean, which for a standard normal distribution is 0.
This symmetry implies:
  • The areas under the curve on either side of the mean are equal, each covering 50% of the total distribution.
  • If the probability of a z-score less than a certain value is known, the probability of a z-score greater than this value is the complement to 1.

For example, the area to the right of a z-score of 0 is 0.5, as is the area to the left, due to this symmetry. This feature is crucial when calculating probabilities for z-scores on either side of the mean.
areas under the curve
Calculating the areas under the normal curve is essential for understanding probabilities relating to the standard normal distribution. Each area corresponds to the probability that the variable falls within a certain range of z-scores.
To find these areas:
  • Use the z-score to calculate the respective cumulative probability from the table.
  • For areas above a certain z-score, subtract the cumulative probability from 1.

For example, finding the area to the right of z = -5 delivers almost 1.00 due to the majority of the curve lying above this point.
These areas are visually represented by the plot regions under the curve, corresponding directly with the numerical probabilities provided by the z-score table. Understanding these areas helps predict the behavior of datasets fitting the model of a standard normal distribution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Example 6.14 gave the probability distributions shown below for \(x=\) number of flaws in a randomly selected glass panel from Supplier 1 \(y=\) number of flaws in a randomly selected glass panel from Supplier 2 for two suppliers of glass used in the manufacture of flat screen TVs. If the manufacturer wanted to select a single supplier for glass panels, which of these two suppliers would you recommend? Justify your choice based on consideration of both center and variability. \(\begin{array}{lcccclcccc}\boldsymbol{x} & 0 & 1 & 2 & 3 & \boldsymbol{y} & 0 & 1 & 2 & 3 \\ \boldsymbol{p}(\boldsymbol{x}) & 0.4 & 0.3 & 0.2 & 0.1 & \boldsymbol{p}(\boldsymbol{y}) & 0.2 & 0.6 & 0.2 & 0\end{array}\)

Suppose a playlist on an MP3 music player consisting of 100 songs includes 8 by a particular artist. Suppose that songs are played by selecting a song at random (with replacement) from the playlist. The random variable \(x\) represents the number of songs until a song by this artist is played. a. Explain why the probability distribution of \(x\) is not binomial. b. Find the following probabilities. (Hint: See Example \(6.31 .\) ) i. \(p(4)\) ii. \(P(x \leq 4)\) iii. \(P(x>4)\) iv. \(P(x \geq 4)\) c. Interpret each of the probabilities in Part (b) and explain the difference between them.

Consider the population of all one-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a normal distribution with mean \(\mu=5 \mathrm{ml}\) and standard deviation \(\sigma=0.2 \mathrm{ml}\) is a reasonable model for the distribution of the variable \(x=\) amount of red dye in the paint mixture Use the normal distribution to calculate the following probabilities. (Hint: See Example \(6.21 .\) ) a. \(P(x<5.0)\) b. \(P(x<5.4)\) c. \(P(x \leq 5.4)\) d. \(P(4.64.5)\) f. \(P(x>4.0)\)

A company that manufactures mufflers for cars offers a lifetime warranty on its products, provided that ownership of the car does not change. Only \(20 \%\) of its mufflers are replaced under this warranty. a. In a random sample of 400 purchases, what is the approximate probability that between 75 and 100 (inclusive) mufflers are replaced under warranty? b. Among 400 randomly selected purchases, what is the approximate probability that at most 70 mufflers are replaced under warranty? c. If you were told that fewer than 50 among 400 randomly selected purchases were replaced under warranty, would you question the \(20 \%\) figure? Explain.

Let \(z\) denote a random variable having a normal distribution with \(\mu=0\) and \(\sigma=1\). Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50)\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.