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Determine the following standard normal (z) curve areas: a. The area under the \(z\) curve to the left of 1.75 b. The area under the \(z\) curve to the left of -0.68 c. The area under the \(z\) curve to the right of 1.20 d. The area under the \(z\) curve to the right of -2.82 e. The area under the \(z\) curve between -2.22 and 0.53 f. The area under the \(z\) curve between -1 and 1 g. The area under the \(z\) curve between -4 and 4

Short Answer

Expert verified
The areas under the z curve for the given scenarios are: a. 0.9599 b. 0.2483 c. 0.1151 d. 0.9976 e. 0.6891 f. 0.6826 g. 1.0000 (approximately)

Step by step solution

01

Identify the given z-scores and the needed areas under the z curve

The given z-scores and the required areas under the curve are as follows: a. Left of 1.75 b. Left of -0.68 c. Right of 1.20 d. Right of -2.82 e. Between -2.22 and 0.53 f. Between -1 and 1 g. Between -4 and 4
02

Use standard normal table or calculator to find probabilities associated with z-scores

Using a standard normal table or a calculator with built-in z-table function, find the cumulative probabilities (areas to the left) up to the given z-scores. a. P(Z \(\le\) 1.75) = 0.9599 b. P(Z \(\le\) -0.68) = 0.2483 c. P(Z \(\le\) 1.20) = 0.8849 d. P(Z \(\le\) -2.82) = 0.0024 e1. P(Z \(\le\) -2.22) = 0.0132 e2. P(Z \(\le\) 0.53) = 0.7023 f1. P(Z \(\le\) -1) = 0.1587 f2. P(Z \(\le\) 1) = 0.8413 g1. P(Z \(\le\) -4) = 0.0000 (approximately) g2. P(Z \(\le\) 4) = 1.0000 (approximately)
03

Calculate the desired areas under the z curve

Use values from Step 2 to find the areas under the z curve for each scenario. a. Area left of 1.75 = 0.9599 b. Area left of -0.68 = 0.2483 c. Area right of 1.20 = 1 - 0.8849 = 0.1151 d. Area right of -2.82 = 1 - 0.0024 = 0.9976 e. Area between -2.22 and 0.53 = 0.7023 - 0.0132 = 0.6891 f. Area between -1 and 1 = 0.8413 - 0.1587 = 0.6826 g. Area between -4 and 4 = 1.0000 - 0.0000 = 1.0000 (approximately)
04

State the final results

The areas under the z curve for the given scenarios are: a. 0.9599 b. 0.2483 c. 0.1151 d. 0.9976 e. 0.6891 f. 0.6826 g. 1.0000 (approximately)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Scores
Understanding the concept of 'z-scores' is fundamental when working with the standard normal curve. Z-scores, also known as standard scores, are a way to describe the position of a raw score within a distribution. A z-score signifies how many standard deviations away a point is from the mean of the distribution. For example, a z-score of 1.75 means the raw score is 1.75 standard deviations above the mean. Conversely, a z-score of -0.68 indicates the score is 0.68 standard deviations below the mean.

To find the corresponding probability for a given z-score, you usually need to look it up in a z-table or use a statistical software or calculator. This probability tells us the portion of the data that falls to the left of this z-score under the standard normal curve. Essentially, z-scores allow us to translate individual scores into a standardized form where they can be easily compared and probabilities can be assigned.
Cumulative Probabilities
Cumulative probabilities are closely tied with the concept of z-scores and play a critical role in statistics. They represent the probability for a variable to take on a value less than or equal to a specific point in a distribution. To put it simply, if you have a z-score, the cumulative probability tells you the percentage of data points that lie to the left of that z-score on a standard normal curve.

For example, if we have a z-score of 1.20, looking it up in the z-table or using a calculator would tell us the cumulative probability associated with that z-score, which is the area under the curve to the left of that z-score. If we need to find the area to the right, we subtract the cumulative probability from 1, as the total area under the normal distribution curve adds up to 1. Therefore, understanding and finding cumulative probabilities is crucial for interpreting z-scores and evaluating the relative standing of data points within a normal distribution.
Normal Distribution
The normal distribution is a bell-shaped curve that is symmetric about the mean and characterized by its mean (μ) and standard deviation (σ). It's a continuous probability distribution that describes many natural phenomena and is a cornerstone in the field of statistics. One of the exceptional aspects of the normal distribution is that it is fully described by the mean and standard deviation.

The standard normal distribution is a special case of the normal distribution with a mean of 0 and a standard deviation of 1. Any normal distribution can be transformed into the standard normal distribution using the z-score formula. The areas under the standard normal curve correspond to probabilities, and the total area under the curve is always equal to 1. We use this feature to find probabilities for ranges of values within the distribution, for example, the probability of a random variable falling between two values (e.g., between -1 and 1), which is a very common exercise in statistics education.

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Most popular questions from this chapter

Consider the random variable \(y=\) the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose the probability distribution of \(y\) is as follows: \(\begin{array}{cccccc}y & 0 & 1 & 2 & 3 & 4 \\ p(y) & 0.65 & 0.20 & 0.10 & 0.04 & ?\end{array}\) a. Only \(y\) values of \(0,1,2,3,\) and 4 have probabilities greater than \(0 .\) What is \(p(4) ?\) b. How would you interpret \(p(1)=0.20 ?\) c. Calculate \(P(y \leq 2)\), the probability that the carton contains at most two broken eggs, and interpret this probability. d. Calculate \(P(y<2),\) the probability that the carton contains fewer than two broken eggs. Why is this smaller than the probability in Part (c)? e. What is the probability that the carton contains exactly 10 unbroken eggs? f. What is the probability that at least 10 eggs are unbroken?

You are to take a multiple-choice exam consisting of 100 questions with five possible responses to each question. Suppose that you have not studied and so must guess (randomly select one of the five answers) on each question. Let \(x\) represent the number of correct responses on the test. a. What kind of probability distribution does \(x\) have? b. What is your expected score on the exam? (Hint: Your expected score is the mean value of the \(x\) distribution.) c. Calculate the variance and standard deviation of \(x\). d. Based on your answers to Parts \((\mathrm{b})\) and \((\mathrm{c}),\) is it likely that you would score over 50 on this exam? Explain the reasoning behind your answer.

A contractor is required by a county planning department to submit anywhere from one to five forms (depending on the nature of the project) when applying for a building permit. Let \(y\) be the number of forms required of the next applicant. Suppose the probability that \(y\) forms are required is known to be proportional to \(y ;\) that is, \(p(y)=\) \(k y\) for \(y=1, \ldots, 5\) a. What is the value of \(k ?\) (Hint: \(\Sigma p(y)=1 .)\) b. What is the probability that at most three forms are required? c. What is the probability that between two and four forms (inclusive) are required?

Industrial quality control programs often include inspection of incoming materials from suppliers. If parts are purchased in large lots, a typical plan might be to select 20 parts at random from a lot and inspect them. Suppose that a lot is judged acceptable if one or fewer of these 20 parts are defective. If more than one part is defective, the lot is rejected and returned to the supplier. Find the probability of accepting lots that have each of the following (Hint: Identify success with a defective part.): a. \(5 \%\) defective parts b. \(10 \%\) defective parts c. \(20 \%\) defective parts

A business has six customer service telephone lines. Consider the random variable \(x=\) number of lines in use at a randomly selected time. Suppose that the probability distribution of \(x\) is as follows: \(\begin{array}{lccccccc}x & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ p(x) & 0.10 & 0.15 & 0.20 & 0.25 & 0.20 & 0.06 & 0.04\end{array}\) a. Calculate the mean value and standard deviation of \(x\). b. What is the probability that the number of lines in use is farther than 3 standard deviations from the mean value?

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