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A particular professor never dismisses class early. Let \(x\) denote the amount of additional time (in minutes) that elapses before the professor dismisses class. Suppose that \(x\) has a uniform distribution on the interval from 0 to 10 minutes. The density curve is shown in the following figure: a. What is the probability that at most 5 minutes elapse before dismissal? b. What is the probability that between 3 and 5 minutes elapse before dismissal?

Short Answer

Expert verified
The probability density function (pdf) for the uniform distribution in this case is \(f(x) = \frac{1}{10}\). Calculating the area under the pdf curve, we find that there is a 50% (\(\frac{1}{2}\)) probability that at most 5 minutes elapse before dismissal, and a 20% (\(\frac{1}{5}\)) probability that between 3 and 5 minutes elapse before dismissal.

Step by step solution

01

Understand the uniform distribution

A uniform distribution is a type of continuous probability distribution where all outcomes are equally likely within a given interval. In this case, the interval is from 0 to 10 minutes. For a uniform distribution, the probability density function (pdf) is given by: \[f(x) = \frac{1}{b - a}\] Where \(a\) and \(b\) are the endpoints of the interval, in this case, \(a = 0\) and \(b = 10\). Let's find the value of the pdf.
02

Calculate the probability density function (pdf)

Using the formula for the uniform distribution, we can calculate the pdf for the given interval: \[f(x) = \frac{1}{b - a} = \frac{1}{10 - 0} = \frac{1}{10}\]
03

Calculate the probability that at most 5 minutes elapse before dismissal

To find the probability that at most 5 minutes elapse before dismissal, we need to calculate the integral of the pdf from \(x = 0\) to \(x = 5\). For a uniform distribution, the integral of the pdf is equal to the area of the rectangle formed under the pdf curve from \(x = 0\) to \(x = 5\). The area of a rectangle is given by multiplying its width and height, so: \[P(x \le 5) = f(x) \cdot (5 - 0) = \frac{1}{10} \cdot 5 = \frac{1}{2}\] Thus, there is a 50% probability that at most 5 minutes elapse before dismissal.
04

Calculate the probability that between 3 and 5 minutes elapse before dismissal

To find the probability that between 3 and 5 minutes elapse before dismissal, we need to calculate the integral of the pdf from \(x = 3\) to \(x = 5\). For a uniform distribution, the integral of the pdf is equal to the area of the rectangle formed under the pdf curve from \(x = 3\) to \(x = 5\). The area of a rectangle is given by multiplying its width and height, so: \[P(3 \le x \le 5) = f(x) \cdot (5 - 3) = \frac{1}{10} \cdot 2 = \frac{1}{5}\] Thus, there is a 20% probability that between 3 and 5 minutes elapse before dismissal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
The probability density function (pdf) is a key concept when dealing with continuous probability distributions. A pdf helps to specify the likelihood of a random variable falling within a particular range of values, as opposed to taking on any one specific value. This is because, in a continuous distribution, the probability of the random variable exactly equaling any one particular value is zero. Instead, we look at intervals and the probability that a random variable falls within an interval.

The pdf is represented as a curve on a graph, and the area under the curve within a specified interval represents the probability of the variable falling within that interval. For a uniform distribution, like the one in the exercise where additional class time can be any value from 0 to 10 minutes, the pdf is a horizontal line since the probability is constant across the interval. Mathematically, a pdf must satisfy two conditions: the probability is always non-negative, and the total area under the curve must be equal to 1, indicating that the sum of all possible outcomes' probabilities is certain.
Continuous Probability Distribution
A continuous probability distribution differs significantly from a discrete probability distribution in that it deals with outcomes that can take on any value within an interval or collection of intervals. With continuous distributions, probabilities are assigned to ranges of values rather than specific outcomes. The uniform distribution described in the exercise is a classic example of a continuous distribution.

Continuous distributions are described by their probability density functions, such as the uniform probability density function in the exercise. The uniform distribution is quite straightforward since every outcome in the interval is equally likely, making it a useful starting point for understanding more complex distribution types. Continuity implies that between any two points within the distribution's range, no matter how close, there are infinitely many potential values the random variable might assume.
Integrating Probability Density Functions
Integrating the probability density function is the process of finding the total probability that a random variable falls within a certain range. This method is the continuous counterpart to summing probabilities in discrete distributions. The integral of the pdf over the entire range of possible values is 1, which corresponds to the certain event of the random variable taking on some value within that range.

To find the probability corresponding to a specific interval, as in the exercise scenarios for 0 to 5 minutes and 3 to 5 minutes, you calculate the integral over that interval. In certain cases, such as the uniform distribution seen here, integrating the pdf simplifies to calculating the area of a rectangle. However, with more complex distributions, integration might require applying more advanced calculus techniques. Understanding this process is crucial, for it allows us to make predictions and understand the likely outcomes of a continuous random variable.

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