/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Suppose you want to estimate the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose you want to estimate the probability that a patient will develop an infection while hospitalized at a particular hospital. In the past year, this hospital had 6450 patients, and 712 of them developed an infection. What is the estimated probability that a patient at this hospital will develop an infection?

Short Answer

Expert verified
The estimated probability that a patient at this hospital will develop an infection is approximately 0.11039, or 11.039%.

Step by step solution

01

Identify the total number of patients and the number of infected patients

We are given the following information: Total number of patients, N = 6450, Number of infected patients, n = 712.
02

Calculate the probability of a patient developing an infection

To calculate the probability of a patient developing an infection at this hospital, divide the number of infected patients (n) by the total number of patients (N): Probability = (number of infected patients) / (total number of patients) Let's plug in the values: Probability = 712 / 6450
03

Simplify the fraction

To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor (GCD) or just calculate the decimal value of the fraction: Probability ≈ 712 / 6450 ≈ 0.11039 The estimated probability that a patient at this hospital will develop an infection is approximately 0.11039, or 11.039%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infection Risk
Understanding infection risk is crucial when studying how likely patients are to develop an infection during their hospital stay. In hospitals, infections can be contracted through various means, such as surgical wounds or exposure in intensive care units. Calculating the infection risk helps in planning and improving healthcare services to minimize such occurrences.

To estimate this risk, we use historical data. In our exercise, we look at data from the past year. The probability of infection is defined as the ratio of the number of patients who developed infections to the total number of patients in the hospital.

Let's break it down further:
  • Total patients = 6450
  • Patients who developed an infection = 712
The probability is thus the number of infections divided by the total patients. This gives a direct estimate of what a new patient's risk would be based on past data.
Hospital Statistics
Statistics in a hospital setting provide a foundation for making informed decisions. They offer insights into how hospital resources are utilized, patient outcomes, and areas requiring improvement. In managing infection risk, hospital statistics become incredibly valuable tools.

By analyzing the number of patients and infections, hospitals can:
  • Identify trends and patterns in infections over time
  • Benchmark performance against other hospitals or historical periods
  • Allocate resources efficiently to areas with elevated infection risks
This statistical understanding enables hospitals to develop protocols to reduce infections, such as improving sterilization processes or boosting staff training. In the context of our exercise, understanding these statistical approaches better informs teamwork in fighting against infections.
Numerical Calculation
Numerical calculation is a key skill in estimating probabilities. Here, it involves processing numbers logically to arrive at meaningful insights. For infection risk, it starts by interpreting given data.

We calculate the probability by dividing the number of infections by the total number of patients. The formula used is:
\[\text{Probability} = \frac{\text{Number of infected patients}}{\text{Total number of patients}}\]
Applying this to our exercise:
\[\text{Probability} = \frac{712}{6450} \approx 0.11039\]
Which means there's an 11.039% chance any patient could develop an infection during their stay. This numerical estimate is key in hospital decision-making processes. Throughout the calculation, simplifying fractions or converting to decimals ensures clarity and accuracy, which are vital in all statistical estimations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Eighty-six countries won medals at the 2016 Olympics in Rio de Janeiro. Based on the results: 1 country won more than 100 medals 2 countries won between 51 and 100 medals 3 countries won between 31 and 50 medals 4 countries won between 21 and 30 medals 15 countries won between 11 and 20 medals 15 countries won between 6 and 10 medals 46 countries won between 1 and 5 medals Suppose one of the 86 countries winning medals at the 2016 Olympics is selected at random. a. What is the probability that the selected country won more than 50 medals? b. What is the probability that the selected country did not win more than 100 medals? c. What is the probability that the selected country won 10 or fewer medals? d. What is the probability that the selected country won between 11 and 50 medals?

A large cable TV company reports the following: \(80 \%\) of its customers subscribe to its cable TV service \(42 \%\) of its customers subscribe to its Internet service \(32 \%\) of its customers subscribe to its telephone service \(25 \%\) of its customers subscribe to both its cable TV and Internet service \(21 \%\) of its customers subscribe to both its cable TV and phone service \(23 \%\) of its customers subscribe to both its Internet and phone service \(15 \%\) of its customers subscribe to all three services Consider the chance experiment that consists of selecting one of the cable company customers at random. Find and interpret the following probabilities: a. \(P(\) cable TV only) b. \(P\) (Internet|cable TV) c. \(P(\) exactly two services \()\) d. \(P\) (Internet and cable TV only)

A large cable company reports that \(42 \%\) of its customers subscribe to its Internet service, \(32 \%\) subscribe to its phone service, and \(51 \%\) subscribe to its Internet service or its phone service (or both). a. Use the given probability information to set up a hypothetical 1000 table. b. Use the table to find the following: i. the probability that a randomly selected customer subscribes to both the Internet service and the phone service. ii. the probability that a randomly selected customer subscribes to exactly one of the two services.

The article "Obesity, Smoking Damage U.S. Economy," which appeared in the Gallup online Business Journal reported that based on a large representative sample of adult Americans, \(52.7 \%\) claimed that they exercised at least 30 minutes on three or more days per week during \(2015 .\) It also reported that the percentage for millennials (people age \(19-35\) ) was \(57.1 \%,\) and for those over 35 it was \(51.1 \% .\) If an adult American were to be selected at random, are the events selected adult exercises at least 30 minutes three times per week and selected adult is a millennial independent or dependent events? Justify your answer using the given information.

The report "Twitter in Higher Education: Usage Habits and Trends of Today's College Faculty" describes a survey of nearly 2000 college faculty. The report indicates the following: \(30.7 \%\) reported that they use Twitter, and \(69.3 \%\) said that they do not use Twitter. Of those who use Twitter, \(39.9 \%\) said they sometimes use Twitter to communicate with students. Of those who use Twitter, \(27.5 \%\) said that they sometimes use Twitter as a learning tool in the classroom. Consider the chance experiment that selects one of the study participants at random. a. Two of the percentages given in the problem specify unconditional probabilities, and the other two percentages specify conditional probabilities. Which are conditional probabilities? How can you tell? b. Suppose the following events are defined: \(T=\) event that selected faculty member uses Twitter \(C=\) event that selected faculty member sometimes uses Twitter to communicate with students \(L=\) event that selected faculty member sometimes uses Twitter as a learning tool in the classroom Use the given information to determine the following probabilities: i. \(P(T)\) iii. \(P(C \mid T)\) ii. \(P\left(T^{C}\right)\) iv. \(\quad P(L \mid T)\) c. Construct a hypothetical 1000 table using the given probabilities and use the information in the table to calculate \(P(C),\) the probability that the selected study participant sometimes uses Twitter to communicate with students. d. Construct a hypothetical 1000 table using the given probabilities and use the information in the table to calculate the probability that the selected study participant sometimes uses Twitter as a learning tool in the classroom.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.