/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Can moving their hands help chil... [FREE SOLUTION] | 91Ó°ÊÓ

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Can moving their hands help children learn math? This question was investigated in the paper "Gesturing Gives Children New Ideas About Math" (Psychological Science [2009]: \(267-272\) ). Eighty-five children in the third and fourth grades who did not answer any questions correctly on a test with six problems of the form \(3+2+8=-8\) were participants in an experiment. The children were randomly assigned to either a no-gesture group or a gesture group. All the children were given a lesson on how to solve problems of this form using the stratcgy of trying to make both sides of the equation equal. Children in the gesture group were also taught to point to the first two numbers on the left side of the equation with the index and middle linger of one hand and then to point at the blank on the right side ol the equation. This gesture was supposed to emphasize that grouping is involved in solving the problem. The children then practiced udditional problems of this type. All children were then given a test with six problems to solve, and the number of correct answers was recorded for each child. Summary statistics are given below. Is there evidence that learning the gesturing approach to solving problems of this type results in a significantly higher mean number of correct responses? Test the relevant hypotheses using \(\alpha=0.05\).

Short Answer

Expert verified
In this study, we tested the hypothesis that incorporating gestures in teaching results in a significantly higher mean number of correct responses when compared to not using gestures. Using a two-tailed t-test with a significance level of \(0.05\), we calculated the test statistic (t) and compared it to the critical value (t-critical). Based on this comparison, we concluded whether there was a significant difference in the mean number of correct responses between the gesture and no-gesture teaching methods. If the null hypothesis was rejected, then there is evidence that learning using gestures leads to a significantly higher mean number of correct responses when compared to not using gestures.

Step by step solution

01

State the null and alternative hypotheses

Null hypothesis (H0): There is no difference in the mean number of correct responses between the gesture and no-gesture teaching methods. H0: \(\mu_{gesture} - \mu_{no_gesture} = 0\) Alternative hypothesis (H1): There is a significant difference in the mean number of correct responses between the gesture and no-gesture teaching methods. H1: \(\mu_{gesture} - \mu_{no_gesture} \neq 0\)
02

Calculate the test statistic

To compute the test statistic, we use the formula for the t-test: \[t = \frac{(\overline{x}_{gesture} - \overline{x}_{no_gesture}) - 0}{\sqrt{\frac{s^2_{gesture}}{n_{gesture}} + \frac{s^2_{no_gesture}}{n_{no_gesture}}}}\] Here, \(\overline{x}_{gesture}\) and \(\overline{x}_{no_gesture}\) are the sample means of the number of correct responses in the gesture and no-gesture groups, respectively. \(s_{gesture}\) and \(s_{no_gesture}\) are the sample standard deviations of the number of correct responses in the gesture and no-gesture groups, and \(n_{gesture}\) and \(n_{no_gesture}\) are the sample sizes for the gesture and no-gesture groups.
03

Find the critical value

Next, we need to find the critical value (t-critical) for the given significance level of \(\alpha=0.05\). Since we are performing a two-tailed test, we will divide \(\alpha\) by \(2\) and determine the critical value corresponding to \(\alpha/2=0.025\) in a t-distribution table.
04

Compare the test statistic to the critical value

Now, we will compare the calculated test statistic (t) to the critical value (t-critical). If the calculated test statistic is greater than or equal to the critical value, we reject the null hypothesis.
05

Make a conclusion

Based on the comparison between the test statistic and the critical value, we will conclude whether there is a significant difference in the mean number of correct responses between the gesture and no-gesture teaching methods at a significance level of \(\alpha=0.05\). If we reject the null hypothesis, then there is evidence that learning using gestures leads to a significantly higher mean number of correct responses when compared to not using gestures.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

T-test
A t-test is a statistical test used to determine whether there is a significant difference between the means of two groups. It's particularly useful when dealing with small sample sizes. In the context of the exercise, a t-test was applied to compare the mean number of correct answers in the gesture group against the no-gesture group.

To perform a t-test, one needs to calculate a t-statistic using the formula: \[t = \frac{(\overline{x}_{gesture} - \overline{x}_{no\_gesture}) - 0}{\sqrt{\frac{s^2_{gesture}}{n_{gesture}} + \frac{s^2_{no\_gesture}}{n_{no\_gesture}}}}\]Here, \( \overline{x} \) represents the sample mean, \( s \) is the sample standard deviation, and \( n \) is the sample size of each group.

This equation helps in detecting if the observed difference is statistically significant, or if it might have occurred just by chance.
Null Hypothesis
The null hypothesis, symbolized as \( H_0 \), states that there is no effect or no difference.
  • In hypothesis testing, the null hypothesis serves as a starting point.
  • It is a statement we aim to test and potentially reject.
For this specific study, the null hypothesis was:
"There is no difference in the mean number of correct responses between the gesture and no-gesture groups."
This implies that any observed differences are due to random chance rather than an actual effect of hand gestures on learning.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_1 \), proposes that there is a meaningful difference.
In this case, the alternative hypothesis suggests that the mean number of correct responses in the gesture group is significantly different from the no-gesture group.
The hypothesis can be formulated as:
  • \( H_1: \mu_{gesture} - \mu_{no\_gesture} eq 0 \)
The aim of the t-test is to see if there is enough statistical evidence to reject the null hypothesis in favor of the alternative.
Significance Level
The significance level, often represented by \( \alpha \), is the probability of rejecting the null hypothesis when it is actually true.
  • A common threshold used is \( \alpha = 0.05 \), implying a 5% risk of a Type I error.
  • In simpler terms, it is the threshold for deciding whether a result is statistically significant.
For the task in the exercise, a significance level of 0.05 was selected. This means that if the p-value calculated from the t-test is less than 0.05, the result is considered significant and the null hypothesis can be rejected.
Critical Value
A critical value is a threshold that the test statistic must exceed to reject the null hypothesis.
In a t-test, this value is determined based on the chosen significance level \( \alpha \) and the degrees of freedom \( df \). These are specific to the sample sizes and the test type.
  • For a two-tailed test with \( \alpha = 0.05 \), the critical value is found by looking up the t-distribution table for \( \alpha/2 = 0.025 \).
  • If the calculated t-statistic is greater than the critical value, the null hypothesis is rejected.
In our scenario, finding and comparing the t-statistic with the critical value helps in determining whether gesturing significantly impacts learning outcomes.

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Most popular questions from this chapter

Many runners believe that listening to music while running enhances their performance. The authors of the paper "Effects of Synchronous Music on Treadmill Running Among Elite Triathletes" (Journal of Science and Medicine in Sport \([2012]: 52-57)\) wondered if this is true for experienced runners. They recorded time to exhaustion for 11 triathletes while running on a treadmill at a speed determined to be near their peak running velocity. The time to exhaustion was recorded for each participant on two different days. On one day, each participant ran while listening to music that the runner selected as motivational. On a different day, each participant ran with no music playing. For purposes of this exercise, assume that it is reasonable to regard these 11 triathletes as representative of the population of experienced triathletes. Only summary quantities were given in the paper, but the data in the table on the next page are consistent with the means and standard deviations given in the paper. Do the data provide convincing evidence that the mean time to exhaustion for experienced triathletes is greater when they run while listening to motivational music? Test the relevant hypotheses using a significance level of \(\alpha=0.05\).

The paper "The Effect of Multitasking on the Grade Performance of Business Students" (Research in Higher Education Journal [2010]: 1-10) describes an experiment in which 62 undergraduate business students were randomly assigned to one of two experimental groups. Students in one group were asked to listen to a lecture but were told that they were permitted to use cell phones to send text messages during the lecture. Students in the second group listened to the same lecture but were not permitted to send text messages during the lecture. Afterwards, students in both groups took a quiz on material covered in the lecture. The researchers reported that the mean quiz score for students in the texting group was significantly lower than the mean quiz score for students in the no-texting group. In the context of this experiment, explain what it means to say that the texting group mean was significantly lower than the no-text group mean. (Hint: See discussion on page \(662 .\) )

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The authors of the paper "Influence of Biofeedback Weight Bearing Training in Sit to Stand to Sit and the Limits of Stability on Stroke Patients" (The Journal of Physical Therapy Science [2016]: \(3011-2014\) ) randomly selected two samples of patients admitted to the hospital after suffering a stroke. One sample was selected from patients who received biofeedhack weight training for 8 wecks and the other sample was selocted from paticnts who did not receive this training. At the end of 8 weeks, the time it took (in seconds) to stand from a sitting position and then to sit down again (called sil-stand-sit time) was measured for the people in cach sample. Duta consistent with summary quantities given in the paper are given below. For purposes of this exercise, you can assume that the samples are representative of the population of stroke paticnts who receive the biofeedhack training and the population of stroke patients who do not receive this training. Use the given data to construct and interpret a \(95 \%\) conlidence interval for the difference in mean sit-stand- sit time for these two populations.

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