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The authors of the paper "Driving Performance While Using a Mobile Phone: A Simulation Study of Greek Professional Drivers" (Transportation Research Part \(F\) [2016]: 164-170) describe a study to evaluate the effect of mobile phone use by taxi drivers in Greece. Fifty taxi drivers drove in a driving simulator where they were following a lead car. The drivers were asked to carry on a conversation on a mobile phone while driving, and the following distance (the distance between the taxi and the lead car) was recorded. The sample mean following distance was 3.20 meters and the sample standard deviation was 1.11 meters. a. Construct and interpret a \(95 \%\) confidence interval for \(\mu,\) the population mean following distance while talking on a mobile phone for the population of taxi drivers. b. What assumption must be made in order to generalize this confidence interval to the population of all taxi drivers in Greece?

Short Answer

Expert verified
The 95% confidence interval for the population mean following distance (μ) for taxi drivers in Greece while talking on a mobile phone is between 2.887 meters and 3.513 meters. To generalize this confidence interval to all taxi drivers in Greece, we must assume that the sample of 50 taxi drivers is representative of the entire population of taxi drivers in Greece, meaning the participants have been randomly selected and not biased in any way.

Step by step solution

01

Sample size, sample mean, and sample standard deviation

We know the sample size (n) is 50 taxi drivers, the sample mean (x̄) is 3.20 meters, and the sample standard deviation (s) is 1.11 meters. #Step 2: Calculate the margin of error#
02

Margin of error

To calculate the margin of error, we will use the formula: Margin of Error = \(t_{\frac{\alpha}{2}} \frac{s}{\sqrt{n}}\) For a 95% confidence interval, the critical value (t-score) can be found using a t-distribution table, or a calculator for the t-distribution. The degrees of freedom (df) are equal to n - 1, which is 49 in this case. \(t_{\frac{\alpha}{2}}\) = 2.010 Now we can compute the margin of error: Margin of Error = (2.010) \(\frac{1.11}{\sqrt{50}}\) ≈ 0.313 #Step 3: Construct the confidence interval#
03

Confidence interval

Now that we have the margin of error (0.313), we can construct the 95% confidence interval using the sample mean (3.20): Confidence Interval = (3.20 - 0.313, 3.20 + 0.313) = (2.887, 3.513) #Step 4: Interpret the confidence interval#
04

Interpretation

We are 95% confident that the true population mean following distance (μ) for taxi drivers in Greece while talking on a mobile phone is between 2.887 meters and 3.513 meters. #Step 5: Identify the assumption for generalization#
05

Assumption for generalization

In order to generalize this confidence interval to the population of all taxi drivers in Greece, we must assume that the sample of 50 taxi drivers is representative of the entire population of taxi drivers in Greece. That means, the participants must be randomly selected and not biased in any way.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, often represented by the symbol \( \bar{x} \), is the average value of a sample—a smaller, selected set of data from a population. In our exercise involving Greek taxi drivers, the sample mean following distance was found to be 3.20 meters. Understanding the sample mean is crucial because it serves as an estimator of the population mean, \( \mu \), which we are often interested in determining.

However, it's important to bear in mind that the sample mean is just an estimate and not an exact measure of the population mean. To enhance its credibility, the sample should be as representative of the population as possible, and the sample size should be sufficiently large to reduce the variability of the mean.
Sample Standard Deviation
The sample standard deviation, denoted as \( s \), is a measure of the amount of variation or dispersion in a set of values. In our example, the sample standard deviation of the following distance was 1.11 meters. This figure tells us about the degree to which individual measurements of following distance deviate from the sample mean.

A smaller standard deviation indicates that the data points tend to be closer to the sample mean, whereas a larger standard deviation indicates that the data points are spread out over a wider range of values. Knowing the standard deviation assists us in understanding the uncertainty inherent in our sample statistics, which is essential when constructing confidence intervals.
T-Distribution
The t-distribution, also known as Student's t-distribution, comes into play when estimating population parameters, like the mean, from a small sample size with an unknown population standard deviation. The t-distribution is similar to the normal distribution, but with fatter tails, which gives more leeway for extreme values.

In the case of the taxi drivers, since the sample size is 50—which is considered relatively small—the t-distribution is an appropriate model for constructing the confidence interval. T-distributions are characterized by degrees of freedom (df), calculated as the sample size minus one (\( n - 1 \)). Therefore, with 50 drivers, our degrees of freedom are 49. The t-distribution allows us to account for the extra uncertainty of using a sample standard deviation instead of the true population standard deviation when estimating the margin of error for our confidence interval.
Margin of Error
The margin of error reflects the range around the sample mean within which we can expect to find the population mean a certain percentage of the time. It is linked to the confidence level, which represents how sure we are that the parameter lies within this range. A 95% confidence level, for example, suggests that if we were to take many samples and construct confidence intervals for each, we would expect about 95% of them to contain the true population mean.

In the example of the taxi drivers, we calculated a margin of error of approximately 0.313 meters. This means that we can be 95% confident that the actual population mean of the following distance while talking on a mobile phone lies within 0.313 meters of our sample mean on either side. When we give the confidence interval, we are essentially saying that we are 95% confident that the true population mean falls within that interval.

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Most popular questions from this chapter

Students in a representative sample of 65 first-year students selected from a large university in England participated in a study of academic procrastination ("Study Goals and Procrastination Tendencies at Different Stages of the Undergraduate Degree," Studies in Higher Education [2016]: 2028-2043). Each student in the sample completed the Tuckman Procrastination Scale, which measures procrastination tendencies. Scores on this scale can range from 16 to \(64,\) with scores over 40 indicating higher levels of procrastination. For the 65 first-year students in this study, the mean score on the procrastination scale was 37.02 and the standard deviation was 6.44 . a. Construct a \(95 \%\) confidence interval estimate of \(\mu,\) the mean procrastination scale for first-year students at this college. (Hint: See Example 12.7.) b. Based on your interval, is 40 a plausible value for the population mean score? What does this imply about the population of first-year students?

What percentage of the time will a variable that has a distribution with the specified degrees of freedom fall in the indicated region? a. 5 df, between -2.02 and 2.02 b. 14 df, between -2.98 and 2.98 c. \(22 \mathrm{df}\), outside the interval from -1.72 to 1.72 d. \(26 \mathrm{df},\) to the left of -2.48

The paper "The Effects of Adolescent Volunteer Activities on the Perception of Local Society and Community Spirit Mediated by Self-Conception" (Advanced Science and Technology Letters [2016]: 19-23) describes a survey of a large representative sample of middle school children in South Korea. One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours. a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal. b. The sample size was not given in the paper, but the sample size was described as "large." Suppose that the sample size was 500 . Explain why it is reasonable to use a one-sample \(t\) confidence interval to estimate the population mean even though the population distribution is not approximately normal. c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children. (Hint: See Example 12.7.)

The formula used to calculate a confidence interval for the mean of a normal population is $$ \bar{x} \pm(t \text { critical value }) \frac{s}{\sqrt{n}} $$ What is the appropriate \(t\) critical value for each of the following confidence levels and sample sizes? a. \(95 \%\) confidence, \(n=17\) b. \(99 \%\) confidence, \(n=24\) c. \(90 \%\) confidence, \(n=13\)

USA TODAY (October 14,2016 ) reported that Americans spend 4.1 hours per weekday checking work e-mail. This was an estimate based on a survey of 1004 white-collar workers in the United States. a. Suppose that you would like to know if there is evidence that the mean time spent checking work e-mail for white-collar workers in the United States is more than half of the 8 -hour work day. What would you need to assume about the sample in order to use the given sample data to answer this question? b. Given that any concerns about the sample were satisfactorily addressed, carry out a test to decide if there is evidence that the mean time spent checking work e-mail for white-collar workers in the United States is more than half of the 8 -hour work day. Suppose that the sample standard deviation was \(s=1.3\) hours.

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