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Suppose that a particular candidate for public office is favored by \(48 \%\) of all registered voters in the district. A polling organization will take a random sample of 500 of these voters and will use \(\hat{p}\), the sample proportion, to estimate \(p\). a. Show that \(\sigma_{p}\), the standard deviation of \(\hat{p}\), is equal to \(0.0223 .\) b. If for a different sample size, \(\sigma_{p}=0.0500\), would you expect more or less sample-to-sample variability in the sample proportions than when \(n=500 ?\) c. Is the sample size that resulted in \(\sigma_{\rho}=0.0500\) larger than 500 or smaller than \(500 ?\) Explain your reasoning.

Short Answer

Expert verified
a. The standard deviation of \(\hat{p}\) is 0.0223. b. For \(\sigma_p = 0.0500\), there would be more sample-to-sample variability in the sample proportions than when \(n = 500\). c. The sample size that resulted in \(\sigma_p=0.0500\) is smaller than 500.

Step by step solution

01

Calculate the standard deviation

The standard deviation of \(\hat{p}\) is calculated using the formula \(\sigma_p = \sqrt{\frac{p(1 - p)}{n}}\), where \(p\) is the proportion, and \(n\) is the size of the population. In this case, \(p = 0.48\) (from the 48% favor for the candidate) and \(n = 500\) (the sample size). Substituting these values into the formula gives \(\sigma_p = \sqrt{\frac{0.48 \times (1 - 0.48)}{500}} = 0.0223.\)
02

Evaluate the effect of \(\sigma_p\) on sample-to-sample variability

With a larger standard deviation, the sample-to-sample variability is expected to be higher. This means that if \(\sigma_p = 0.0500\), one would expect more sample-to-sample variability in the sample proportions compared to when \(n = 500\). This is because a larger standard deviation indicates a greater dispersion of data values.
03

Determine if the sample size is larger or smaller

To get a larger standard deviation, the size of the sample would have to be smaller than 500. This is because standard deviation and sample size have an inversely proportional relationship. When the sample size decreases, the standard deviation increases. Conversely, when the sample size increases, the standard deviation decreases. As such, the sample size which resulted in a larger \(\sigma_p=0.0500\) is smaller than 500.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
The standard deviation in sampling distribution refers to how much the measured values deviate from the average value, providing a measure of variability or spread in the data. In the context of the sample proportion, this measures the extent to which sample proportions may differ from the true population proportion.For our example, where 48% of voters favor a particular candidate, and a sample size of 500 is considered, the standard deviation (\(\sigma_p\),) of the sample proportion can be calculated using the formula: \[ \sigma_p = \sqrt{\frac{p(1 - p)}{n}} \] where \( p = 0.48 \) and \( n = 500 \). Implementing these values, we calculate \( \sigma_p = \sqrt{\frac{0.48 \times (1 - 0.48)}{500}} = 0.0223 \). This value gives us the spread of sampling distribution, telling us how consistently different samples might reflect the true population proportion of 48%. A lower standard deviation suggests that the sample proportions are closer to the true proportion, indicating less variability among different samples.
Sample Proportion
The sample proportion, \(\hat{p}\), is an essential concept when estimating population parameters. It is the fraction of the sample with a particular attribute and serves as an estimator for the true population proportion, \(p\). In this example, \(\hat{p}\) is used to estimate the preference percentage for a candidate. When we select a sample of voters, \(\hat{p}\) represents the proportion of that sample who favor the candidate.Calculating the sample proportion involves simply dividing the number of favorable outcomes by the number of total observations. Here, if researchers observed 240 out of 500 sampled voters with a preference for the candidate, the sample proportion \(\hat{p}\) would be \(\frac{240}{500} = 0.48\).In practice, the sample proportion provides a direct, easy-to-interpret estimate but includes variability that's quantified by the standard deviation. With a larger sample size or less standard deviation, \(\hat{p}\) is closer to \(p\), the true population proportion.
Sample Size
The sample size, typically denoted as \(n\), refers to the number of observations or data points selected from a larger population for statistical analysis. It's a critical factor influencing the accuracy and reliability of your study findings. In this problem, a sample size of 500 voters was used to gauge public opinion.The sample size affects the precision of estimated parameters like our sample proportion \(\hat{p}\). Larger samples generally lead to more precise (less variable) estimates, enhancing the representativeness of the sample proportion to the actual population proportion. This relationship is mathematically observed as \(\sigma_p = \sqrt{\frac{p(1 - p)}{n}}\). Thus, for a larger standard deviation (e.g., 0.0500 in another scenario), the sample size would, conversely, be smaller because standard deviation and sample size are inversely related.In summary, knowing how to determine and adjust the sample size is crucial because it directly impacts the stability and reliability of statistical inferences made about the population.

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Most popular questions from this chapter

The article "Thrillers" (Newsweek, April 22,1985 ) stated, "Surveys tell us that more than half of America's college graduates are avid readers of mystery novels." Let \(p\) denote the actual proportion of college graduates who are avid readers of mystery novels. Consider a sample proportion \(\hat{p}\) that is based on a random sample of 225 college graduates. If \(p=0.5,\) what are the mean value and standard deviation of the sampling distribution of \(\hat{p}\) ? Answer this question for \(p=0.6 .\) Is the sampling distribution of \(\hat{p}\) approximately normal in both cases? Explain.

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