/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 A random sample of 1,000 student... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A random sample of 1,000 students at a large college included 428 who had one or more credit cards. For this sample, \(\hat{p}=\frac{428}{1,000}=0.428 .\) If another random sample of 1,000 students from this university were selected, would you expect that \(\hat{p}\) for that sample would also be 0.428 ? Explain why or why not.

Short Answer

Expert verified
No, we would not necessarily expect the proportion \(\hat{p}\) to be exactly 0.428 in a new sample, though the new \(\hat{p}\) would likely be close to 0.428. This variation is due to sampling variability and the nature of random sampling, where each sample is independent and hence may yield a slightly different \(\hat{p}\).

Step by step solution

01

Understanding the nature of random sampling

Random sampling is based on the principle that each sample drawn from the same population should be independent and not influenced by the previous samples. Therefore, a new sample of 1,000 students may or may not result in the proportion \(\hat{p}=0.428\). It could be slightly different due to the randomness of the selection.
02

Understanding sample proportions

The sample proportion \(\hat{p}=0.428\) is an estimate of the actual population proportion. While the same sample proportion could be obtained in a subsequent sample, it is not guaranteed. It could be slightly more or less than 0.428, depending on the sample selected.
03

Using probability theory

According to probability theory, the expected value is the same as the population parameters when dealing with proportions. Therefore, if the actual proportion of students with credit cards in the entire college is 0.428, then we expect that the proportion from another sample would be close to 0.428. However, due to sampling variability, we cannot say with absolute certainty that it would be exactly 0.428.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Variability
When we pull a random sample from a population, like selecting 1,000 students from a college to find out how many have credit cards, each sample can yield different results. This is a fundamental concept known as sampling variability. It refers to the natural fluctuations that occur in statistics, such as a sample proportion, from one sample to another.

These differences are due to the random nature of sampling. Each student has a certain likelihood of holding a credit card, but until they’re actually selected and observed, we can’t know for sure if they will increase or decrease the sample proportion of cardholders, \( \hat{p} \). In practice, this means that if we repeated the sample process multiple times, we'd likely see different values of \( \hat{p} \) each time, even if the underlying proportion in the population remains unchanged.

While we might hope to get the same result of 0.428 each time, sampling variability tells us that this will not always be the case. The variability is influenced by the sample size, the variance in the population, and the sampling method. For educational purposes, it's critical to grasp that \( \hat{p} \) is an estimate of the true population proportion and it's normal for it to vary from sample to sample.
Sample Proportion
The sample proportion, denoted as \( \hat{p} \), is a statistic that estimates the proportion of individuals in a population who have a certain characteristic, based on a sample. In the context of our example, where we found that 428 out of 1,000 randomly sampled students have credit cards, our sample proportion is 0.428.

This number is a snapshot of the larger student body, aimed at giving us a sense of how common credit card ownership is among all students. It's important to understand that the sample proportion is just that—an estimate. It can vary from the true proportion due to the randomness inherent in sampling.

With this in mind, improving our understanding of the sample proportion involves acknowledging that it's a reflection of our specific sample at a specific time. A different random sample could lead to a slightly higher or lower proportion due to the different individuals who make up that sample. Therefore, while \( \hat{p} \) can serve as a useful estimate of the actual proportion, it's essential to consider it within the context of sampling error and respect its limitations as an estimate.
Probability Theory
Probability theory provides the mathematical foundation for understanding random processes, such as random sampling. According to probability theory, we can calculate expectations and make predictions about phenomena like sample proportions.

In the case of our college students and their credit card ownership, probability theory would say that if the true proportion of students with credit cards in the entire college is around 0.428, and we sample students randomly, then on average, our sample proportion should be close to the true proportion. However, 'on average' does not mean 'always.' Each individual sample might still vary due to chance alone.

Expected Value and Variance

Two key concepts from probability theory that help us with this include the expected value, which is what we predict to happen on average, and variance, which tells us how much the results are likely to differ from the expected value. These ideas from probability theory are essential as they allow us to quantify the uncertainty of our sample proportion, \(\hat{p}\), and give us tools to assess the reliability of our estimates.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the following statement: A county tax assessor reported that the proportion of property owners who paid 2012 property taxes on time was 0.93 . a. Is the number that appears in boldface in this statement a sample proportion or a population proportion? b. Which of the following use of notation is correct, \(p=0.93\) or \(p=0.93 ?\)

Explain why there is sample-to-sample variability in \(\hat{p}\) but not in \(p\).

A random sample of 100 employees of a large company included 37 who had worked for the company for more than one year. For this sample, \(\hat{p}=\frac{37}{100}=0.37\). If a different random sample of 100 employees were selected, would you expect that \(\hat{p}\) for that sample would also be \(0.37 ?\) Explain why or why not.

Suppose that a particular candidate for public office is favored by \(48 \%\) of all registered voters in the district. A polling organization will take a random sample of 500 of these voters and will use \(\hat{p}\), the sample proportion, to estimate \(p\). a. Show that \(\sigma_{p}\), the standard deviation of \(\hat{p}\), is equal to \(0.0223 .\) b. If for a different sample size, \(\sigma_{p}=0.0500\), would you expect more or less sample-to-sample variability in the sample proportions than when \(n=500 ?\) c. Is the sample size that resulted in \(\sigma_{\rho}=0.0500\) larger than 500 or smaller than \(500 ?\) Explain your reasoning.

A random sample of size 300 is to be selected from a population. Determine the mean and standard deviation of the sampling distribution of \(\hat{p}\) for each of the following population proportions. a. \(p=0.20\) b. \(p=0.45\) c. \(p=0.70\) d. \(p=0.90\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.