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The paper "The Effect of Temperature and Humidity on Size of Segregated Traffic Exhaust Particle Emissions" (Atmospheric Environment [2008]: 2369-2382) gave the following summary quantities for a measure of traffic flow (vehicles/second) during peak traffic hours. Traffic flow was recorded daily at a particular location over a long sequence of days. Mean \(=0.41\) Standard Deviation \(=0.26\) Median \(=0.45\) 5th percentile \(=0.03 \quad\) Lower quartile \(=0.18\) \(\begin{array}{ll}\text { Upper quartile } & =0.57 & \text { 95th Percentile } & =0.86\end{array}\) Based on these summary quantities, do you think that the distribution of the measure of traffic flow is approximately normal? Explain your reasoning.

Short Answer

Expert verified
Based on these summary quantities, it is unlikely that the distribution of the traffic flow is approximately normal. While the mean and median are close to each other, suggesting possible symmetry, the quartiles and percentiles are not symmetric around the mean or median. This inconsistency with the known properties of a normal distribution suggests that the traffic flow data does not follow a normal distribution.

Step by step solution

01

- Compare Mean and Median

Check if the mean and median of the distribution are close to each other. In normal distributions, the mean and median are effectively the same. Here, the mean is \(0.41\) and the median is \(0.45\). They are quite close to each other, indicating the data may be symmetric around the mean value.
02

- Examine Lower and Upper Quartiles

Look at the lower and upper quartiles. In a normal distribution, the data is symmetric around the mean, so the lower and upper quartiles should be equidistant from the mean or median. The lower quartile is \(0.18\) and the upper quartile is \(0.57\). However, distance of lower quartile from median (\(0.45 - 0.18 = 0.27\)) is not equal to distance of upper quartile from median (\(0.57 - 0.45 = 0.12\))
03

- Evaluate Percentiles

Inspect the 5th and 95th percentiles. Again, if the distribution is normal, these should be roughly symmetric around the mean or median. The 5th percentile is \(0.03\), and the 95th percentile is \(0.86\). The distance of 5th percentile from median (\(0.45 - 0.03 = 0.42\)) is not equal to distance of 95th percentile from median (\(0.86 - 0.45 = 0.41\))

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Median Comparison
In statistical analysis, comparing the mean and median offers insights into the distribution of the data. Normally, for a dataset exhibiting a normal distribution, these two measures tend to be close or even identical.
In this situation, we observe the values given: mean is \(0.41\) and median is \(0.45\). The closeness of these values suggests that the distribution might be symmetric. This symmetry implies that the data isn't skewed significantly to the left or right.
However, the small gap between the mean and median still leaves room for minor asymmetry. It's important to couple this analysis with further techniques, like quartile analysis and percentile evaluation, to better understand the distribution's nature.
Quartile Analysis
Quartiles divide a dataset into four equal parts, and they help detail the spread and center of the data. A vital characteristic of a normal distribution is its symmetry around the median. For this to hold true, distances between quartiles and the median should be the same on both sides.
In our traffic flow data, the lower quartile (first quartile) is \(0.18\) and the upper quartile (third quartile) is \(0.57\). Calculating the distance from the median \(0.45\) gives us:
  • Distance from lower quartile to median: \(0.45 - 0.18 = 0.27\)
  • Distance from upper quartile to median: \(0.57 - 0.45 = 0.12\)
These distances are noticeably unequal.
This indicates a lack of symmetry, suggesting that the distribution may lean more to one side, thus differing from a typical normal distribution.
Percentile Evaluation
Percentiles provide additional information about a dataset's distribution by indicating the relative standing of a value within the dataset. For distributions that are normal, percentiles also show symmetry.
Key here is the 5th and 95th percentiles. They help in identifying whether the data is balanced around its center value.
According to the problem, we have:
  • 5th percentile at \(0.03\)
  • 95th percentile at \(0.86\)
Calculating the distance from the median \(0.45\) to these percentiles:
  • Distance from 5th percentile to median: \(0.45 - 0.03 = 0.42\)
  • Distance from 95th percentile to median: \(0.86 - 0.45 = 0.41\)
While these distances are quite similar, the previous inconsistency in quartile distances suggests a mild lack of normality.
Thus, while percentiles show a reasonably balanced spread, the data might not be perfectly normal, particularly when considering quartile findings.

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