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The authors of the paper "Short-Term Health and Economic Benefits of Smoking Cessation: Low Birth Weight" (Pediatrics [1999]:1312-1320) investigated the medical cost associated with babies born to mothers who smoke. The paper included estimates of mean medical cost for low-birth-weight babies for different ethnic groups. For a sample of 654 Hispanic low-birth-weight babies, the mean medical cost was \(\$ 55,007\) and the standard error \((s / \sqrt{n})\) was \(\$ 3011\). For a sample of 13 Native American low-birth-weight babies, the mean and standard error were \(\$ 73,418\) and \(\$ 29,577,\) respectively. Explain why the two standard errors are so different.

Short Answer

Expert verified
The standard errors of the Hispanic and Native American samples are vastly different due to the difference in their respective sample sizes and potentially the variability within each group. The larger sample size of the Hispanic group gives it a smaller standard error due to a more accurate estimation of the population mean, while the Native American sample has a smaller size and potentially more variability, which contribute to its larger standard error.

Step by step solution

01

Understanding Standard Error

Standard error is a measure of how much a sample mean estimates the population mean. A smaller standard error indicates the sample mean is a more accurate reflection of the actual population mean. The formula for standard error is SE = s / sqrt(n), where s is the standard deviation of the sample and n is the number of observations in the sample. As such, the standard error relies heavily on the sample size and the variability within the sample.
02

Comparing the Samples

In this exercise, two different samples are taken: one sample of 654 Hispanic low-birth-weight babies and one sample of 13 Native American low-birth-weight babies. The larger the sample size, the smaller the standard error, because the estimate becomes closer to the population mean. Thus, we would expect the Hispanic sample to have a smaller standard error due to its larger size. However, the standard error also depends on the variability within the sample. A higher variability within the sample would mean a larger standard deviation and thus a larger standard error.
03

Analyzing the Difference in Standard Errors

The standard error for the Hispanic sample is $3011, while it is noticeably higher for the Native American sample at $29577. Even though the Hispanic sample is much larger, the standard error is much smaller. This discrepancy can be explained by the much smaller sample size of the Native American group and possibly a greater variability within the Native American sample compared to the Hispanic sample. Thus, the smaller sample size and the potentially higher variability within the Native American sample can explain the larger standard error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean Estimation
The process of sample mean estimation is at the core of statistical analysis. It involves using the average value from a smaller, selected group, known as a sample, to estimate the average value for a larger group or population. In our exercise, the mean medical costs for two samples of low-birth-weight babies were estimated to: \(\$55,007\) for Hispanic babies, based on a sample of 654, and \(\$73,418\) for Native American babies, from a much smaller sample of 13.

Why is the estimate significant? Well, when researchers cannot measure every individual in an entire population due to resource constraints, they take a manageable number of observations from a subset. This sample mean serves as a point estimate of the population mean鈥攖he true average we鈥檙e trying to estimate. The accuracy of this estimate, inferred from the sample data, is reflected in its standard error, which brings us to the importance of understanding sample size and variability.
Population Mean
The population mean is the average of all measurements or values in a population. It represents the expected value that you would obtain if you could measure every single member of the entire group without error or bias. When we mention the term 'population', we're talking about the full set of data from which a sample is drawn. In statistical terminology, 'population' does not only refer to people but to any collection of observations for which we wish to make inferences.

In the medical cost study, we're looking to estimate the mean cost associated with low-birth-weight babies for different ethnic groups, with the ultimate goal of arriving at the population mean. However, since we鈥檝e only sampled parts of the population, our estimates might not perfectly match the true population mean. This is where understanding standard error and its relationship to sample size and variability becomes crucial.
Sample Size
Sample size, denoted by \(n\), is the number of observations included in the statistical sample. It's a pillar in producing a reliable estimate of the population mean. The larger the sample size, the less variability there is likely to be in the estimate of the population mean, thus the more confidence we can have in our sample mean estimation.

In the provided exercise, there鈥檚 a notable contrast between the sample sizes: 654 Hispanic babies versus only 13 Native American babies. The standard error of the Hispanic sample is significantly lower due to the sample's size. The law of large numbers tells us that as a sample size increases, the sample mean gets closer to the population mean, resulting in a smaller standard error, assuming the sample is random and representative. This is precisely why large-scale studies are often favored in research: they are more likely to produce results that accurately reflect the true attributes of the population.
Sample Variability
Sample variability refers to the range of different values, or variance, within a sample. High variability indicates that the sample values are spread out widely from each other and from the sample mean. Conversely, low variability means that the data points are closer to each other and the sample mean. Variability is measured using standard deviation (\(s\)).

Returning to our exercise, while the sample size had a significant effect on the standard error (SE), sample variability is another aspect to be scrutinized. If the 13 Native American babies had a wide range of medical costs, this would lead to a high standard deviation, consequently inflating the standard error. When we pair a small sample size with high variability, we end up with a less precise estimate of the population mean, as witnessed by the larger standard error in the Native American sample.

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Most popular questions from this chapter

In June, 2009 , Harris Interactive conducted its Great Schools Survey. In this survey, the sample consisted of 1,086 adults who were parents of school-aged children. The sample was selected to be representative of the population of parents of school-aged children. One question on the survey asked respondents how much time per month (in hours) they spent volunteering at their children's school during the previous school year. The following summary statistics for time volunteered per month were given: \(n=1086 \quad \bar{x}=5.6 \quad\) median \(=1\) a. What does the fact that the mean is so much larger than the median tell you about the distribution of time spent volunteering at school per month? b. Based on your answer to Part (a), explain why it is not reasonable to assume that the population distribution of time spent volunteering is approximately normal. c. Explain why it is appropriate to use the one-sample \(t\) confidence interval to estimate the mean time spent volunteering for the population of parents of school-aged children even though the population distribution is not approximately normal. d. Suppose that the sample standard deviation was \(s=5.2\). Use the five-step process for estimation problems \(\left(\mathrm{EMC}^{3}\right)\) to calculate and interpret a \(98 \%\) confidence interval for \(\mu,\) the mean time spent volunteering for the population of parents of school-aged children. (Hint: See Example 12.7)

An article titled "Teen Boys Forget Whatever It Was" appeared in the Australian newspaper The Mercury (April 21, 1997). It described a study of academic performance and attention span and reported that the mean time to distraction for teenage boys working on an independent task was 4 minutes. Although the sample size was not given in the article, suppose that this mean was based on a random sample of 50 teenage boys and that the sample standard deviation was 1.4 minutes. Is there convincing evidence that the average attention span for teenage boys is less than 5 minutes? Test the relevant hypotheses using \(\alpha=0.01\).

The paper "Playing Active Video Games Increases Energy Expenditure in Children鈥 (Pediatrics [2009]: \(534-539\) ) describes a study of the possible cardiovascular benefits of active video games. Mean heart rate for healthy boys ages 10 to 13 after walking on a treadmill at \(2.6 \mathrm{~km} /\) hour for 6 minutes is known to be 98 beats per minute (bpm). For each of 14 boys, heart rate was measured after 15 minutes of playing Wii Bowling. The resulting sample mean and standard deviation were 101 bpm and 15 bpm, respectively. Assume that the sample of boys is representative of boys ages 10 to 13 and that the distribution of heart rates after 15 minutes of Wii Bowling is approximately normal. Does the sample provide convincing evidence that the mean heart rate after 15 minutes of Wii Bowling is different from the known mean heart rate after 6 minutes walking on the treadmill? Carry out a hypothesis test using \(\alpha=0.01\). (Hint: See Example 12.12\()\)

A credit bureau analysis of undergraduate students credit records found that the average number of credit cards in an undergraduate's wallet was 4.09 ("Undergraduate Students and Credit Cards in 2004," Nellie Mae, May 2005 ). It was also reported that in a random sample of 132 undergraduates, the sample mean number of credit cards that the students said they carried was 2.6 . The sample standard deviation was not reported, but for purposes of this exercise, suppose that it was 1.2 . Is there convincing evidence that the mean number of credit cards that undergraduates report carrying is less than the credit bureau's figure of \(4.09 ?\)

Suppose that a random sample of size 64 is to be selected from a population with mean 40 and standard deviation 5 . a. What are the mean and standard deviation of the \(\bar{x}\) sampling distribution? Describe the shape of the \(\bar{x}\) sampling distribution. b. What is the approximate probability that \(\bar{x}\) will be within 0.5 of the population mean \(\mu\) ? c. What is the approximate probability that \(\bar{x}\) will differ from \(\mu\) by more than \(0.7 ?\)

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