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Suppose that a random sample of 50 bottles of a particular brand of cough medicine is selected, and the alcohol content of each bottle is determined. Let \(\mu\) denote the mean alcohol content for the population of all bottles of this brand. Suppose that this sample of 50 results in a \(95 \%\) confidence interval for \(\mu\) of (7.8,9.4) a. Would a \(90 \%\) confidence interval have been narrower or wider than the given interval? Explain your answer. b. Consider the following statement: There is a \(95 \%\) chance that \(\mu\) is between 7.8 and 9.4 . Is this statement correct? Why or why not? c. Consider the following statement: If the process of selecting a random sample of size 50 and then calculating the corresponding \(95 \%\) confidence interval is repeated 100 times, exactly 95 of the resulting intervals will include \(\mu .\) Is this statement correct? Why or why not?

Short Answer

Expert verified
a. A \(90%\) confidence interval would have been narrower. b. No, the interpretation of the confidence interval is incorrect. It should be: We are \(95%\) confident that the interval (7.8, 9.4) contains the true mean alcohol content \(\mu\). c. No, the statement is incorrect. Confidence level means that \(95%\) of the intervals from repeated sampling would contain the population mean. However it doesn't provide any guarantee about exact number out of 100.

Step by step solution

01

Understanding Confidence Level Impact on Interval Width

When you decrease the confidence level, from \(95%\) to \(90%\) for instance, the width of the confidence interval decreases as well. The confidence level is a measure of certainty. If we are less certain (\(90%\) compared to \(95%)\), we need less precision, hence a narrower confidence interval.
02

Identifying Errors in Confidence Interval Interpretation

The statement 'There is a \(95%\) chance that the mean alcohol content \(\mu\) is between 7.8 and 9.4' is incorrect. Confidence intervals do not work that way. The correct interpretation should be: We are \(95%\) confident that the interval (7.8, 9.4) contains the true mean alcohol content \(\mu\). It is not about probability of \(\mu\), but about the level of confidence in our method.
03

Understanding Probabilistic Interpretation of Confidence Intervals

Similarly, the statement 'If the process is repeated 100 times, exactly 95 of the intervals will include \(\mu\)' is incorrect as well. This is a common misunderstanding. What the \(95%\) confidence level means is that \(95%\) of random samples of the same size from the same population will result in confidence intervals that contain the population parameter. However, it does not state any guarantee about the exact number out of 100.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
When you hear about the "confidence level," think of it as the degree of certainty or assurance we have in our statistical method. In the context of confidence intervals, a common measure of confidence is expressed as a percentage, such as 90%, 95%, or 99%. These percentages represent how sure we are that the method used to create our interval will capture the true population parameter, like a mean.

For instance, a 95% confidence level suggests that if we repeatedly took random samples and calculated the confidence intervals, approximately 95% of these intervals would successfully contain the true parameter we are trying to estimate. Thus, the confidence level is not about a single interval being correct or not, but rather reflects the reliability of the process used to create those intervals.
Population Mean
In statistics, the population mean (\(\mu\),) is a crucial concept. It represents the average value of a given attribute for an entire population. Unlike the sample mean, which is computed from a subset, the population mean is about the entire group we're analyzing or interested in.

For example, in our exercise, \(\mu\) could stand for the average alcohol content in all bottles of a specific brand of cough medicine. Knowing the population mean helps us understand the overall characteristic of the population, even if it's not always directly observable.

Estimation techniques, like confidence intervals, are designed to help us infer or predict the population mean based on data from a limited sample, which leads us to a better understanding of the entire population.
Random Sample
A random sample is a fundamental idea in statistics that involves selecting a subset of individuals from a population in such a way that each subset has an equally likely chance of being chosen. This is important because it helps ensure that the sample truly represents the population, free from biases.

In our scenario, taking a random sample of 50 bottles of cough medicine means that every group of 50 bottles from all possible bottles has the same chance of being selected. This randomness is critical because it provides the foundation for making valid statistical inferences, like calculating confidence intervals which can estimate the population mean from the subset data.
Interval Width
The concept of interval width deals with how broad or narrow a confidence interval is. This width indicates the range of values we can be confident contains the true population parameter. Several factors influence the interval's width, including the sample size and the confidence level.

Generally speaking, if we decrease our confidence level (say from 95% to 90%), the interval will get narrower because we are essentially accepting more uncertainty about whether the interval contains the true population mean. Conversely, to be more confident (e.g., 99%), we widen the interval to increase the likelihood it holds the true parameter.

In addition, a larger sample size tends to make intervals narrower because it provides more information and thus greater precision about what the population is truly like.
Statistical Inference
Statistical inference is about drawing conclusions from data. At its heart, it involves determining how likely it is that a pattern or effect observed in a sample also exists in the overall population. This process relies heavily on concepts like random sampling and constructing confidence intervals.

Through statistical inference, we use sample data to make educated statements or predictions about the larger population. For example, estimating the population mean from a sample through a confidence interval allows us to infer its value with a stated level of confidence.

Statistical inference helps turn raw data into meaningful insights, which is why it's a cornerstone of data analysis and decision-making in diverse fields, from medicine to market research.

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Most popular questions from this chapter

In June, 2009 , Harris Interactive conducted its Great Schools Survey. In this survey, the sample consisted of 1,086 adults who were parents of school-aged children. The sample was selected to be representative of the population of parents of school-aged children. One question on the survey asked respondents how much time per month (in hours) they spent volunteering at their children's school during the previous school year. The following summary statistics for time volunteered per month were given: \(n=1086 \quad \bar{x}=5.6 \quad\) median \(=1\) a. What does the fact that the mean is so much larger than the median tell you about the distribution of time spent volunteering at school per month? b. Based on your answer to Part (a), explain why it is not reasonable to assume that the population distribution of time spent volunteering is approximately normal. c. Explain why it is appropriate to use the one-sample \(t\) confidence interval to estimate the mean time spent volunteering for the population of parents of school-aged children even though the population distribution is not approximately normal. d. Suppose that the sample standard deviation was \(s=5.2\). Use the five-step process for estimation problems \(\left(\mathrm{EMC}^{3}\right)\) to calculate and interpret a \(98 \%\) confidence interval for \(\mu,\) the mean time spent volunteering for the population of parents of school-aged children. (Hint: See Example 12.7)

What percentage of the time will a variable that has a \(t\) distribution with the specified degrees of freedom fall in the indicated region? (Hint: See discussion on page 496 ) a. 10 df, between -1.81 and 1.81 b. 24 df, between -2.06 and 2.06 c. 24 df, outside the interval from -2.80 to 2.80 d. 10 df, to the left of -1.81

A study of fast-food intake is described in the paper "What People Buy From Fast-Food Restaurants" (Obesity [2009]:1369- 1374). Adult customers at three hamburger chains (McDonald's, Burger King, and Wendy's) in New York City were approached as they entered the restaurant at lunchtime and asked to provide their receipt when exiting. The receipts were then used to determine what was purchased and the number of calories consumed was determined. In all, 3,857 people participated in the study. The sample mean number of calories consumed was 857 and the sample standard deviation was 677 . a. The sample standard deviation is quite large. What does this tell you about number of calories consumed in a hamburgerchain lunchtime fast-food purchase in New York City? b. Given the values of the sample mean and standard deviation and the fact that the number of calories consumed can't be negative, explain why it is not reasonable to assume that the distribution of calories consumed is normal. c. Based on a recommended daily intake of 2,000 calories, the online Healthy Dining Finder (www.healthydiningfinder .com) recommends a target of 750 calories for lunch. Assuming that it is reasonable to regard the sample of 3,857 fast-food purchases as representative of all hamburger-chain lunchtime purchases in New York City, carry out a hypothesis test to determine if the sample provides convincing evidence that the mean number of calories in a New York City hamburger-chain lunchtime purchase is greater than the lunch recommendation of 750 calories. Use \(\alpha=0.01\). d. Would it be reasonable to generalize the conclusion of the test in Part (c) to the lunchtime fast-food purchases of all adult Americans? Explain why or why not. e. Explain why it is better to use the customer receipt to determine what was ordered rather than just asking a customer leaving the restaurant what he or she purchased.

A random sample is selected from a population with mean \(\mu=60\) and standard deviation \(\sigma=3\). Determine the mean and standard deviation of the \(\bar{x}\) sampling distribution for each of the following sample sizes: a. \(n=6\) d. \(n=75\) b. \(n=18\) e. \(n=200\) c. \(n=42\) f. \(n=400\)

12.56 Speed, size, and strength are thought to be important factors in football performance. The article "Physical and Performance Characteristics of NCAA Division I Football Players" (Research Quarterly for Exercise and Sport [1990]: \(395-401\) ) reported on physical characteristics of Division I starting football players in the 1988 football season. The mean weight of starters on top-20 teams was reported to be \(105 \mathrm{~kg} .\) A random sample of 33 starting players (various positions were represented) from Division I teams that were not ranked in the top 20 resulted in a sample mean weight of \(103.3 \mathrm{~kg}\) and a sample standard deviation of \(16.3 \mathrm{~kg} .\) Is there sufficient evidence to conclude that the mean weight for non-top-20 team starters is less than \(105,\) the known value for top-20 teams?

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