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An automobile manufacturer decides to carry out a fuel efficiency test to determine if it can advertise that one of its models achieves \(30 \mathrm{mpg}\) (miles per gallon). Six people each drive a car from Phoenix to Los Angeles. The resulting fuel efficiencies (in miles per gallon) are: 27.2 \(\begin{array}{lllll}29.3 & 31.2 & 28.4 & 30.3 & 29.6\end{array}\) Assuming that fuel efficiency is normally distributed, do these data provide evidence against the claim that actual mean fuel efficiency for this model is (at least) \(30 \mathrm{mpg}\) ?

Short Answer

Expert verified
To complete this analysis, perform the calculations as described in steps 1-6. If the calculated t-value is less than the critical t-value, then there is not enough evidence to refute the claim that actual mean fuel efficiency for this model is at least 30 mpg. Otherwise, the claim is not supported by the data.

Step by step solution

01

Organize the Data

Firstly, list out the given fuel efficiencies for the six different people: 27.2, 29.3, 31.2, 28.4, 30.3, 29.6.
02

Calculate the Sample Mean

To find the sample mean, add up all these fuel efficiencies, and then divide by the number of observations, which in this case is 6. So, the sample mean is \(\frac{27.2+29.3+31.2+28.4+30.3+29.6}{6}\).
03

Calculate the Sample Standard Deviation

To find the sample standard deviation, first find the squared difference between each observation and the sample mean, add those squared differences, divide by the number of observations minus 1, and then take the square root of the result.
04

Calculate the t-value

Next, calculate the t-value. This is calculated as \(t = \frac{sample \ mean - µ0}{sample \ standard \ deviation / \sqrt{n}}\). Here, µ0 = 30 (the assumed population mean), n = 6 (the sample size).
05

Determine the critical t-value

Look up the critical value for a one-tailed test (since we're interested in whether the actual mean is less than 30 mpg) from a t-table. Use a significance level of 0.05 and degrees of freedom = 5 (n - 1). This will be the critical t-value.
06

Compare the t-values

If the calculated t-value is less than the critical t-value, then we would accept the null hypothesis. Otherwise, we reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-value calculation
In hypothesis testing, calculating the t-value is a critical step when determining whether to accept or reject the null hypothesis. The t-value measures the difference between the sample mean and the hypothesized population mean in terms of the standard deviation of the sample. This concept is particularly useful when the sample size is small or the population standard deviation is unknown.
To calculate the t-value, you follow this formula:
  • Subtract the hypothesized population mean (\(\mu_0\)) from the sample mean.
  • Divide this result by the standard deviation of the sample divided by the square root of the sample size (\(n\)).
So, the equation is written as:\[t = \frac{\text{sample mean} - \mu_0}{\text{sample standard deviation} / \sqrt{n}}\]
In the context of the fuel efficiency example, we assume a mean of 30 mpg as the null hypothesis. The calculated t-value will tell us whether the observed fuel efficiency data provides evidence against this assumption.
Remember that it's crucial to use the correct values for the sample mean and standard deviation, as these will affect the ratio and, consequently, the t-value.
sample mean
The sample mean, often symbolized as \(\bar{x}\), represents the average of a set of sample observations. It is used as an estimate of the population mean, providing a critical starting point for various statistics calculations, including hypothesis testing.
In the exercise, the sample mean is calculated by taking the sum of the measured fuel efficiencies and dividing by the number of observations. In formulaic terms:
  • Add all observed data points together.
  • Divide the total by the number of data points in the sample.
For the fuel efficiency data:\[\bar{x} = \frac{27.2 + 29.3 + 31.2 + 28.4 + 30.3 + 29.6}{6}\]
Calculating the sample mean is straightforward, yet it forms the foundation for more complex calculations. It provides a simplified single value that represents the data set as a whole, making it easier to compare against theoretical expectations or other data sets.
normal distribution
The concept of normal distribution is central to hypothesis testing and many areas of statistics. A normal distribution describes a pattern where data points tend to cluster around a central mean, creating a symmetrical bell-shaped curve.
This distribution assumes specific properties:
  • The mean, median, and mode of the distribution are equal.
  • It is symmetric around the mean.
  • It follows the empirical rule: approximately 68% of data falls within one standard deviation of the mean, 95% within two, and 99.7% within three.
In the fuel efficiency example, the problem states that fuel efficiency is normally distributed. This assumption allows us to use t-distribution for hypothesis testing, especially when dealing with small sample sizes. Understanding that the data behaves normally means we expect most observations to be around the mean mpg, with fewer deviations on either side.
Knowing the distribution is normal provides clarity and reliability to our hypothesis testing by allowing for the usage of critical values from statistical tables and making assumptions about the population mean.

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