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The eating habits of 12 bats were examined in the article "Foraging Behavior of the Indian False Vampire Bat" (Biotropica [1991]: \(63-67)\). These bats consume insects and frogs. For these 12 bats, the mean time to consume a frog was \(\bar{x}=21.9\) minutes. Suppose that the standard deviation was \(s=7.7\) minutes. Is there convincing evidence that the mean supper time of a vampire bat whose meal consists of a frog is greater than 20 minutes? What assumptions must be reasonable for the one-sample \(t\) test to be appropriate?

Short Answer

Expert verified
First, calculate the test statistic from the sample mean, sample standard deviation and present hypotheses. Then, compute the P-value, keeping in mind that it is a one-tailed test. If the P-value is less than or equal to 0.05, there is convincing evidence that the mean supper time of a vampire bat is greater than 20 minutes. If the P-value is greater than 0.05, there is not enough evidence to reject the null hypothesis, and it may not be longer than 20 minutes. Values for the test statistic and P-value are not provided, but should be calculated based on the given steps and information.

Step by step solution

01

State the Hypotheses

The null hypothesis \(H_0\) is that the mean supper time of the bats is 20 minutes: \(H_0: \mu = 20\). The alternative hypothesis \(H_a\) is that the mean supper time is greater than 20 minutes: \(H_a: \mu > 20\).
02

Compute the Test Statistic

The test statistic for the one-sample \(t\) test is given by \(T = \dfrac{\bar{x} - \mu_0}{s/\sqrt{n}}\), where \(\bar{x}\) is the sample mean, \(s\) is the sample standard deviation, \(n\) is the number of observations and \(\mu_0\) is the presumed population mean under the null hypothesis. Here, \(\bar{x} = 21.9, s = 7.7, n = 12, \mu_0 = 20\). So, \(T = \dfrac{21.9 - 20}{7.7/\sqrt{12}}\).
03

Calculate the P-value

The \(P\)-value is the probability of observing a test statistic as extreme as the one calculated, under the null hypothesis. In this case, as the alternative hypothesis is that the mean supper time is greater than 20 minutes, the P-value is the probability of observing a \(t\) value as extreme as calculated or more, in the right tail of the t-distribution with \(n-1\) degrees of freedom. We calculate \(P(T > t)\) where \(t\) is the calculated test statistic value.
04

Interpret Results

If the \(P\)-value is less than or equal to a significance level (often 0.05), then we conclude that there is convincing evidence to reject the null hypothesis in favor of the alternative; thus concludes that the mean supper time of a vampire bat whose meal consists of a frog is greater than 20 minutes. If the \(P\)-value is greater than 0.05, there isn't enough evidence to reject the null hypothesis, hence we do not have convincing evidence that the mean supper time is over 20 minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions about a population based on sample data. It starts with an assumption, called the null hypothesis ( H_0 ), which in this exercise was that the mean time for bats to consume a frog is 20 minutes. We then test this against an alternative hypothesis ( H_a ), which claims that the mean time is greater than 20 minutes.

In hypothesis testing, we aim to determine if our sample provides enough evidence to reject the null hypothesis in favor of the alternative. If the evidence is strong enough, we conclude that the alternative hypothesis is more compatible with the observed data.

The test involves calculating a test statistic which helps to determine how far the sample mean is from the mean stated in the null hypothesis. A crucial part of this is understanding and interpreting the calculated test statistic with respect to the significance level set for the experiment (often 0.05). If our test statistic is sufficiently extreme, our null hypothesis may be rejected.
Sample Mean
The sample mean is a critical element in statistical analysis, representing the average of the given sample data. In our example with the bats, the sample mean \(\bar{x}\) was calculated to be 21.9 minutes. This was based on the data from observing 12 bats, each eating a frog.

The sample mean is essential because it serves as our best estimate of the population mean when we can't measure the entire population. It is a central value that can summarize the entire sample data into a single number, providing an indication of the central tendency of that data.

This serve as a foundation for further calculations, like determining the test statistic in hypothesis testing. It is often used in conjunction with other statistics, like the standard deviation and sample size, to draw conclusions about the entire population.
P-value
The P-value is a probability value that helps to determine the significance of your test results in hypothesis testing. It tells us how likely we are to observe a result as extreme as the computed test statistic, under the assumption that the null hypothesis is true.

In our example, we calculated a P-value for the scenario where the mean time for bats to finish eating zis above 20 minutes. When we have only the sample data, the P-value gives us an objective way to decide whether there is enough evidence to reject the null hypothesis.

If the P-value is less than or equal to a predefined significance level (commonly 0.05), it suggests that the observed data is quite rare under the null hypothesis. Thus, allowing us to reject the null hypothesis in favor of the alternative. However, if the P-value is greater than this significance level, we lack sufficient evidence to reject the null hypothesis and must conclude that the data do not indicate a significant difference.

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Most popular questions from this chapter

The authors of the paper "Short-Term Health and Economic Benefits of Smoking Cessation: Low Birth Weight" (Pediatrics [1999]:1312-1320) investigated the medical cost associated with babies born to mothers who smoke. The paper included estimates of mean medical cost for low-birth-weight babies for different ethnic groups. For a sample of 654 Hispanic low-birth-weight babies, the mean medical cost was \(\$ 55,007\) and the standard error \((s / \sqrt{n})\) was \(\$ 3011\). For a sample of 13 Native American low-birth-weight babies, the mean and standard error were \(\$ 73,418\) and \(\$ 29,577,\) respectively. Explain why the two standard errors are so different.

A random sample is selected from a population with mean \(\mu=200\) and standard deviation \(\sigma=15 .\) Determine the mean and standard deviation of the \(\bar{x}\) sampling distribution for each of the following sample sizes: a. \(n=12\) d. \(n=40\) b. \(n=20\) e. \(n=90\) c. \(n=25\) f. \(n=300\)

A manufacturing process is designed to produce bolts with a diameter of 0.5 inches. Once each day, a random sample of 36 bolts is selected and the bolt diameters are recorded. If the resulting sample mean is less than 0.49 inches or greater than 0.51 inches, the process is shut down for adjustment. The standard deviation of bolt diameters is 0.02 inches. What is the probability that the manufacturing line will be shut down unnecessarily? (Hint: Find the probability of observing an \(\bar{x}\) in the shutdown range when the actual process mean is 0.5 inches.)

The paper "Playing Active Video Games Increases Energy Expenditure in Children鈥 (Pediatrics [2009]: \(534-539\) ) describes a study of the possible cardiovascular benefits of active video games. Mean heart rate for healthy boys ages 10 to 13 after walking on a treadmill at \(2.6 \mathrm{~km} /\) hour for 6 minutes is known to be 98 beats per minute (bpm). For each of 14 boys, heart rate was measured after 15 minutes of playing Wii Bowling. The resulting sample mean and standard deviation were 101 bpm and 15 bpm, respectively. Assume that the sample of boys is representative of boys ages 10 to 13 and that the distribution of heart rates after 15 minutes of Wii Bowling is approximately normal. Does the sample provide convincing evidence that the mean heart rate after 15 minutes of Wii Bowling is different from the known mean heart rate after 6 minutes walking on the treadmill? Carry out a hypothesis test using \(\alpha=0.01\). (Hint: See Example 12.12\()\)

Give as much information as you can about the \(P\) -value of a \(t\) test in each of the following situations: a. Two-tailed test, \(\mathrm{df}=9, t=0.73\) b. Upper-tailed test, \(\mathrm{df}=10, t=0.5\) c. Lower-tailed test, \(n=20, t=-2.1\) d. Two-tailed test, \(n=40, t=1.7\)

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