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In a representative sample of 1,000 adult Americans, only 430 could name at least one justice who was currently serving on the U.S. Supreme Court (Ipsos, January 10,2006 ). Using a significance level of \(0.01,\) determine if there is convincing evidence in support of the claim that less than half of adult Americans can name at least one justice currently serving on the Supreme Court.

Short Answer

Expert verified
Yes, there is convincing evidence to support the claim that less than half of adult Americans can name at least one justice currently serving on the Supreme Court.

Step by step solution

01

Identify the Hypothesis

First, identify the null hypothesis \(H_0\) and alternative hypothesis \(H_a\). In this case:- Null hypothesis (\(H_0\)): Half of adult Americans can name at least one justice. This corresponds to a population proportion (\(p\)) of 0.5- Alternative hypothesis (\(H_a\)): Less than half of adult Americans can name at least one justice. This is \(\(p < 0.5\)\)
02

Calculate Sample Proportion and Standard Deviation

The sample proportion (\(\hat{p}\)) is the ratio of the number of positive outcomes (430) to the size of the sample (1,000). So, \(\hat{p} = 430/1000 = 0.43\).\nNext, to determine the standard deviation of the sample proportion, use the formula \(\sqrt{p(1 - p) / n}\), where \(p\) is the hypothesized population proportion, \(n\) is the size of the sample. Thus, standard deviation equals \(\sqrt{0.5 * (1 - 0.5) / 1000} = 0.0158\)
03

Calculate the Test Statistic (Z-score)

To calculate the Z-score, use the formula \((\hat{p} - p) / standard deviation\). So, the Z-score should be \((0.43 - 0.5) / 0.0158 = -4.43\).
04

Determine the P-value

A Z-score of -4.43 corresponds to an extremely low P-value (less than 0.0001). Since it's a left-tail test, the P-value can be found in the z-table or calculated using a statistical tool.
05

Conclusion

The P-value is less than the significance level (\(0.01\)), this means rejecting the null hypothesis in favor of the alternative. Therefore, there's convincing evidence to support the claim that less than half of adult Americans can name at least one justice currently serving on the Supreme Court.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, represented as \(H_0\), is a statement of no effect or no difference used as a starting point for statistical testing. In the context of our example, the null hypothesis claims that half of adult Americans, or 50%, can name at least one currently serving Supreme Court justice, corresponding to a population proportion \((p)\) of 0.5. In essence, the null hypothesis is what researchers aim to test against and is assumed true until evidence suggests otherwise.

Understanding the null hypothesis is crucial because it sets the baseline for comparison in hypothesis testing. If data provides sufficient evidence to reject \(H_0\), then we look towards the alternative hypothesis for an explanation; otherwise, we do not move away from our null assumption.
Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis \(H_a\) represents what the researcher is trying to support with the data collected. It is a statement that indicates a new effect, difference, or relation. For the situation discussed, the alternative hypothesis is that less than half of adult Americans can name a justice, mathematically expressed as \(p < 0.5\).

When conducting a hypothesis test, the alternative hypothesis is what you are trying to provide evidence for. It stands as a challenger to the status quo represented by the null hypothesis and is considered only when there is significant evidence against \(H_0\).
Sample Proportion
The sample proportion \(\hat{p}\) is a statistic that estimates the population proportion within a sample. It is calculated by dividing the number of successful outcomes by the total number of observations in the sample. In our example, since 430 out of 1,000 surveyed individuals could name a justice, the sample proportion is \(\hat{p} = 0.43\).

This measure is vital as it helps to understand the proportion of a characteristic within a subset of the population, which then is used to infer conclusions about the entire population. It's a fundamental value in many statistical tests, including hypothesis testing.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion of a set of values. In the context of hypothesis testing, we often deal with the standard deviation of the sample proportion, which indicates how much we would expect the proportion to vary from sample to sample. In this scenario, the formula \(\sqrt{p(1 - p) / n}\) gives a standard deviation of 0.0158, providing insight into the variability of the sample proportion around the hypothesized population proportion (0.5).

Knowing the standard deviation is essential since it is used to calculate the Z-score, which subsequently helps us to determine how uncommon our sample result is, given that the null hypothesis is true.
Z-score
The Z-score is a statistic that measures the number of standard deviations a data point is from the population mean. For hypothesis testing, it is the test statistic used to decide whether to reject the null hypothesis. It's calculated using the formula \(Z = (\hat{p} - p) / \text{standard deviation}\). In our example, a Z-score of -4.43 indicates that the sample proportion of 0.43 is 4.43 standard deviations below the hypothesized proportion of 0.5.

The Z-score is pivotal in hypothesis testing because it helps determine how extreme the sample result is. The more extreme the Z-score, the less likely the sample result occurred by random chance, which might lead to rejecting the null hypothesis.
P-value
The P-value is the probability of obtaining test results at least as extreme as the ones observed, under the assumption that the null hypothesis is correct. In simpler terms, it tells us how likely our sample result would be if the null hypothesis were true. For our case, the P-value associated with a Z-score of -4.43 is less than 0.0001, which is extremely low.

This is significant in hypothesis testing as the P-value is used to weigh the strength of the evidence against the null hypothesis. A low P-value suggests that the observed data is unusual under the assumption of the null hypothesis being true, hence supporting the alternative hypothesis.
Significance Level
The significance level, denoted by \(\alpha\), is a threshold chosen by the researcher to decide whether to reject the null hypothesis. It is the probability of making the mistake of rejecting the null hypothesis when it is actually true (Type I error). In the example, a significance level of 0.01 means we'd expect to make such a mistake 1% of the time if we repeated our study many times.

Selecting an appropriate significance level is a key decision in hypothesis testing because it reflects the degree of certainty the researcher requires to reject the null hypothesis. When the P-value is less than the chosen significance level, as it is here, it suggests the evidence is strong enough to reject the null hypothesis in favor of the alternative.

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Most popular questions from this chapter

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