/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 The paper referenced in the prev... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The paper referenced in the previous exercise also reported that when each of the 1,178 students who participated in the study was asked if he or she played video games at least once a day, 271 responded yes. The researchers were interested in using this information to decide if there is convincing evidence that more than \(20 \%\) of students ages 8 to 18 play video games at least once a day.

Short Answer

Expert verified
There is convincing evidence to suggest that more than 20% of students ages 8 to 18 play video games at least once a day.

Step by step solution

01

Define the Hypotheses

The null hypothesis (\(H_0\)) is that the proportion of students who play video games at least once a day is equal to 20% (or 0.2). The alternative hypothesis (\(H_1\)) is that the proportion of students who play video games at least once a day is greater than 20% (or 0.2). Mathematically, this can be expressed as follows: \(H_0: p = 0.2\), \(H_1: p > 0.2\)
02

Perform Calculations

Now, calculate the sample proportion (\(p̂\)) by dividing the number of 'yes' responses by the total number of students. \(p̂ = 271/1178 = 0.23\). To conduct the hypothesis test, we need to calculate the test statistic (z) which is given by \(z = (p̂ - p)/(sqrt((p * (1 - p))/n))\) where \(p\) is the proportion under null hypothesis, \(p̂\) is the sample proportion and \(n\) is the sample size. Substituting the given values, we get \(z = (0.23 - 0.2) / (sqrt((0.2 * (1 - 0.2))/1178)) \approx 2.6\).
03

Interpret the Result

The z-score tells us how many standard deviations away our sample proportion is from the null hypothesis proportion. The z-value obtained is 2.6 which is quite significantly larger than 1.96 (the critical z-value for a 5% level of significance for a one-tailed test). Therefore, we reject the null hypothesis and conclude that there is convincing evidence that more than 20% of students ages 8 to 18 play video games at least once a day.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
When conducting a hypothesis test, the first step is to establish the null hypothesis. This is a statement that assumes there is no effect or no difference between groups or conditions, often signifying the status quo. For instance, in the context of the provided exercise, the null hypothesis (\(H_0\)) posits that the proportion of students who play video games daily is 20%. Mathematically, this is expressed as \(H_0: p = 0.2\), where \(p\) represents the population proportion.
The beauty of the null hypothesis is that it sets a baseline for our test, allowing us to measure whether any observed effect is due to chance. Rejecting or failing to reject the null hypothesis depends on the evidence against it, calculated statistically through the hypothesis testing process. If our data provides strong evidence, we might conclude that the null hypothesis is unlikely to be true, leading us to explore other possibilities.
Alternative Hypothesis
The alternative hypothesis, often denoted as \(H_1\) or \(H_a\), suggests that there is an effect, a difference, or in this case, that the status quo is not accurate. When a researcher suspects that more than 20% of students play video games daily, this forms the basis for the alternative hypothesis. Thus, in this example, the alternative hypothesis is stated as \(H_1: p > 0.2\).
This hypothesis acts as the research hypothesis, suggesting that the observed data reflects a true effect or difference. It's essential to note that the alternative hypothesis is what researchers generally want to prove; hence they collect data and conduct statistical tests to gain evidence supporting \(H_1\). When the null hypothesis is rejected, we often accept the alternative hypothesis, hinting that the observed data is significant enough not to be solely due to chance.
Proportion Test
A proportion test is used when we want to compare a sample proportion to a known population proportion. This is a common method in statistics used to determine if the observed proportion in a sample is significantly different from a theoretical or expected proportion. In this exercise, we're interested in whether the proportion of daily video gamers in a sample of students differs from the proposed 20% in the population.
  • First, we calculate the sample proportion \( \hat{p} \), which is the ratio of students who play games daily to the total number of respondents. In this scenario, \( \hat{p} = 271/1178 = 0.23 \).
  • Next, we derive the test statistic, typically a z-score in proportion tests. The formula for the z-score is \( z = (\hat{p} - p) / \sqrt{(p (1 - p) / n)} \), where \(p\) is the population proportion under the null hypothesis, \(\hat{p}\) is the sample proportion, and \(n\) is the sample size.
  • In this case, substituting the numbers gives us a z-value of approximately 2.6. This value indicates how many standard deviations the sample proportion is from the null hypothesis proportion.
  • If the z-score is greater than a critical value from the z-distribution (for a one-tailed test, typically 1.96 for a 5% significance level), we reject the null hypothesis.
Ultimately, a proportion test allows for decision-making regarding a population parameter based on sample data, providing insights into the studied phenomenon.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a survey of 1,005 adult Americans, \(46 \%\) indicated that they were somewhat interested or very interested in having Web access in their cars (USA Today, May 1,2009 ). Suppose that the marketing manager of a car manufacturer claims that the \(46 \%\) is based only on a sample and that \(46 \%\) is close to half, so there is no reason to believe that the proportion of all adult Americans who want car Web access is less than \(0.50 .\) Is the marketing manager correct in his claim? Provide statistical evidence to support your answer. For purposes of this exercise, assume that the sample can be considered representative ofp adult Americans.

In an AP-AOL sports poll (Associated Press, December 18 , 2005), 272 of 394 randomly selected baseball fans stated that they thought the designated hitter rule should either be expanded to both baseball leagues or eliminated. Based on the given information, is there sufficient evidence to conclude that a majority of baseball fans feel this way?

The report "How Teens Use Media" (Nielsen, June 2009) says that \(37 \%\) of U.S. teens access the Internet from a mobile phone. Suppose you plan to select a random sample of students at the local high school and will ask each student in the sample if he or she accesses the Internet from a mobile phone. You want to determine if there is evidence that the proportion of students at the high school who access the Internet using a mobile phone differs from the national figure of 0.37 given in the Nielsen report. What hypotheses should you test?

Researchers at the University of Washington and Harvard University analyzed records of breast cancer screening and diagnostic evaluations ("Mammogram Cancer Scares More Frequent Than Thought," USA Today, April 16,1998\()\). Discussing the benefits and downsides of the screening process, the article states that although the rate of falsepositives is higher than previously thought, if radiologists were less aggressive in following up on suspicious tests, the rate of false-positives would fall, but the rate of missed cancers would rise. Suppose that such a screening test is used to decide between a null hypothesis of \(H_{0}:\) no cancer is present and an alternative hypothesis of \(H_{a}:\) cancer is present. (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) a. Would a false-positive (thinking that cancer is present when in fact it is not) be a Type I error or a Type II error? b. Describe a Type I error in the context of this problem, and discuss the consequences of making a Type I error. c. Describe a Type II error in the context of this problem, and discuss the consequences of making a Type II error. d. Recall the statement in the article that if radiologists were less aggressive in following up on suspicious tests, the rate of false-positives would fall but the rate of missed cancers would rise. What aspect of the relationship between the probability of a Type I error and the probability of a Type II error is being described here?

In a representative sample of 2,013 American adults, 1,590 indicated that lack of respect and courtesy in American society is a serious problem (Associated Press, April 3,2002 ). Is there convincing evidence that more than three- quarters of American adults believe that lack of respect and courtesy is a serious problem? Test the relevant hypotheses using a significance level of 0.05 .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.