/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 The Sullivan Statistics Survey I... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Sullivan Statistics Survey I asks, "Would you be willing to pay higher taxes if the tax revenue went directly toward deficit reduction?" Treat the survey respondents as a random sample of adult Americans. Go to www.pearsonhighered.com/sullivanstats to obtain the data file SullivanSurveyI using the file format of your choice for the version of the text you are using. The column "Deficit" has survey responses. Construct and interpret a \(90 \%\) confidence interval for the proportion of adult Americans who would be willing to pay higher taxes if the revenue went directly toward deficit reduction.

Short Answer

Expert verified
90% CI for the proportion is p̂ ± 1.645 × SE.

Step by step solution

01

- Obtain the Data

Go to the provided website www.pearsonhighered.com/sullivanstats to download the data file SullivanSurveyI in the file format that corresponds to your version of the text. Locate the column labeled 'Deficit' which contains the survey responses.
02

- Identify the Sample Proportion

Count the number of 'Yes' responses in the 'Deficit' column and denote this number as X. Let n be the total number of responses in the 'Deficit' column. The sample proportion (p̂) is then given by the ratio \(\frac{X}{n}\).
03

- Determine the Confidence Level and z-Value

For a 90% confidence level, the corresponding z-value (critical value) is 1.645. This value is obtained from the standard normal distribution table.
04

- Compute the Standard Error

Calculate the standard error (SE) of the sample proportion using the formula: \(\text{SE} = \sqrt{\frac{p̂(1 - p̂)}{n}}\).
05

- Construct the Confidence Interval

Construct the 90% confidence interval using the formula: \(\text{CI} = p̂ \pm (z \times \text{SE})\). This will give you the lower and upper bounds of the confidence interval.
06

- Interpret the Confidence Interval

Interpret the interval: With 90% confidence, it can be stated that the true proportion of adult Americans who would be willing to pay higher taxes if the revenue went directly toward deficit reduction lies within the calculated confidence interval.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion is a fundamental concept in statistics. It represents the fraction of a sample that has a particular attribute. For this exercise, it’s the fraction of respondents who answered 'Yes' to the survey question about being willing to pay higher taxes for deficit reduction. First, you need the total number of 'Yes' responses, denoted as X. Then, divide X by the total number of responses, denoted as n. Mathematically, it’s represented as \(\hat{p} = \frac{X}{n} \). So, if 150 out of 500 respondents said 'Yes', the sample proportion \(\hat{p}\) would be \(\frac{150}{500} = 0.3\). This value gives you a first insight into what portion of the population might hold this view. Breaking it down into a step-by-step process makes it easier to understand:
  • Count the number of 'Yes' responses (X)
  • Count the total number of responses (n)
  • Divide X by n to get the sample proportion \(\hat{p}\)
Standard Error
Standard error measures the variability or the expected fluctuation in the sample proportion if we were to take multiple samples from the population. It provides insight into how much the sample proportion is likely to differ due to sampling variability. The formula for standard error (SE) is \( \text{SE} = \sqrt{ \frac{ \hat{p} ( 1 - \hat{p} )}{n} } \). For example, if the sample proportion \(\hat{p}\) is 0.3 and the sample size (n) is 500, the standard error would be \(\sqrt{ \frac{ 0.3 \times 0.7 }{ 500 } }\). Simplify the expression under the square root to get your final SE value. This step is essential because it helps in constructing confidence intervals:
  • Calculate \(\hat{p} \times ( 1 - \hat{p} ) \)
  • Divide by the total number of responses (n)
  • Take the square root of the result to get the standard error (SE)
z-value
The z-value is a critical value from the standard normal distribution corresponding to the desired confidence level. It tells how many standard deviations away from the mean our value sits. For a 90% confidence interval, the z-value is 1.645. This value comes from z-tables or statistical software. It is used in the final step of constructing the confidence interval, multiplying it by the standard error. Here’s a straightforward way to understand how it's applied:
  • Select the desired confidence level (e.g., 90%)
  • Refer to the z-table to find the corresponding z-value, here it’s 1.645
  • Use this z-value in calculating the confidence interval
In the formula for the confidence interval, \( \text{CI} = \hat{p} \pm ( z \times \text{SE})\), the z-value gives the range around the sample proportion within which we expect the true population proportion to lie with a specific level of confidence.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Find the \(t\) -value such that the area in the right tail is 0.10 with 25 degrees of freedom. (b) Find the \(t\) -value such that the area in the right tail is 0.05 with 30 degrees of freedom. (c) Find the \(t\) -value such that the area left of the \(t\) -value is 0.01 with 18 degrees of freedom. [Hint: Use symmetry.] (d) Find the critical \(t\) -value that corresponds to \(90 \%\) confidence. Assume 20 degrees of freedom.

A sociologist wishes to conduct a poll to estimate the percentage of Americans who favor affirmative action programs for women and minorities for admission to colleges and universities. What sample size should be obtained if she wishes the estimate to be within 4 percentage points with \(90 \%\) confidence if (a) she uses a 2003 estimate of \(55 \%\) obtained from a Gallup Youth Survey? (b) she does not use any prior estimates? (c) Why are the results from parts (a) and (b) so close?

A simple random sample of size \(n\) is drawn from a population that is normally distributed. The sample mean, \(\bar{x},\) is found to be \(50,\) and the sample standard deviation, \(s,\) is found to be \(8 .\) (a) Construct a \(98 \%\) confidence interval for \(\mu\) if the sample size, \(n,\) is 20 (b) Construct a \(98 \%\) confidence interval for \(\mu\) if the sample size, \(n\), is \(15 .\) How does decreasing the sample size affect the margin of error, \(E ?\) (c) Construct a \(95 \%\) confidence interval for \(\mu\) if the sample size, \(n\), is 20. Compare the results to those obtained in part (a). How does decreasing the level of confidence affect the margin of error, \(E\) ? (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Why?

The following data represent the \(\mathrm{pH}\) of rain for a random sample of 12 rain dates in Tucker County, West Virginia. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. $$ \begin{array}{llllll} \hline 4.58 & 5.19 & 5.05 & 4.80 & 4.77 & 4.77 \\ \hline 5.72 & 4.75 & 5.02 & 4.74 & 4.76 & 4.56 \\ \hline \end{array} $$ (a) Determine a point estimate for the population mean \(\mathrm{pH}\) of rainwater in Tucker County. (b) Construct and interpret a \(95 \%\) confidence interval for the mean \(\mathrm{pH}\) of rainwater in Tucker County, West Virginia. (c) Construct and interpret a \(99 \%\) confidence interval for the mean \(\mathrm{pH}\) of rainwater in Tucker County, West Virginia. (d) What happens to the interval as the level of confidence is increased? Explain why this is a logical result.

Determine the critical value \(z_{\alpha / 2}\) that corresponds to the given level of confidence. \(99 \%\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.