/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 In a survey conducted by the mar... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a survey conducted by the marketing agency 11 mark, 241 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom (confessions included texting and answering phone calls). (a) What is the sample in this study? What is the population of interest? (b) What is the variable of interest in this study? Is it qualitative or quantitative? (c) Based on the results of this survey, obtain a point estimate for the proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom. (d) Explain why the point estimate found in part (c) is a statistic. Explain why it is a random variable. What is the source of variability in the random variable? (e) Construct and interpret a \(95 \%\) confidence interval for the population proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom. (f) What ensures that the results of this study are representative of all adults 19 years of age or older?

Short Answer

Expert verified
The sample is 1000 adults aged 19 or older. The population is all adults aged 19 or older. The variable is qualitative. The point estimate is 0.241. The 95% confidence interval is (0.214, 0.268). Representativeness is ensured by random sampling.

Step by step solution

01

Identifying the Sample and Population

The sample in this study consists of the 1000 adults aged 19 or older who participated in the survey. The population of interest is all adults aged 19 or older.
02

Determining the Variable of Interest

The variable of interest is whether an adult brings and uses their cell phone during every trip to the bathroom. This variable is qualitative because it categorizes individuals based on behavior rather than numerical measurements.
03

Point Estimate Calculation

To find the point estimate for the population proportion of adults who bring their cell phone to the bathroom, use the formula for sample proportion: \( \hat{p} = \frac{x}{n} \). Here, \(x = 241\ and \ n = 1000\): \( \hat{p} = \frac{241}{1000} = 0.241 \). Hence, the point estimate is 0.241.
04

Explanation of Point Estimate as Statistic and Random Variable

The point estimate \( \hat{p} = 0.241 \) is a statistic because it's calculated from sample data. It's a random variable because different samples could yield different sample proportions. The variability arises from sampling variation.
05

Constructing and Interpreting the Confidence Interval

First, determine the standard error for the proportion: \[ SE = \sqrt{ \frac{\hat{p}(1-\hat{p})}{n} } = \sqrt{ \frac{0.241(1-0.241)}{1000} } \.\] This yields \ SE \approx 0.0138. Next, use the Z-value for a 95% confidence interval, which is 1.96: \[ CI = \hat{p} \pm Z \cdot SE = 0.241 \pm 1.96 \cdot 0.0138.\] Calculating gives \ CI = (0.214, 0.268).\ Therefore, the 95% confidence interval is (0.214, 0.268). This means we are 95% confident that the true proportion of adults who bring their cell phones to the bathroom is between 21.4% and 26.8%.
06

Ensuring Representativeness

The results are representative of all adults aged 19 or older if the sample was randomly selected. Random sampling helps ensure that every individual in the population had an equal chance of being included in the survey, which minimizes bias.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample and Population
In any survey, understanding the distinctions between the sample and the population is crucial. The sample refers to the subset of individuals from the population who are actually surveyed. In this exercise, the sample consists of the 1000 adults aged 19 or older who participated in the survey. The population, on the other hand, includes all adults aged 19 years or older, encompassing a much broader group than just the surveyed sample. By studying the sample, we aim to make inferences about the entire population.
Knowing this difference helps us determine how representative our findings are relative to the whole group we are interested in.
Qualitative and Quantitative Variables
Variables in a survey can be either qualitative or quantitative. Qualitative variables categorize or describe attributes that do not have numerical values. In our exercise, the variable of interest is whether an adult brings and uses their cell phone on every trip to the bathroom. This is a qualitative variable because it classifies individuals based on behavior rather than measuring something numerically like age or income.
Understanding the type of variable is important as it dictates the type of analysis we can perform. Qualitative variables are usually summarized using proportions or percentages, while quantitative variables are often summarized using means or standard deviations.
Point Estimate
A point estimate provides a single value estimate for a population parameter based on sample data. To find the point estimate for the population proportion of adults who bring their cell phone to the bathroom, we use the formula for the sample proportion: \[ \hat{p} = \frac{x}{n} \]. Here, \x = 241\ and \ = 1000\, giving \hat{p} = 0.241\. Therefore, the point estimate is 0.241, meaning about 24.1% of the surveyed sample reported using their cell phone on every trip to the bathroom. This estimate helps us make an educated guess about the behavior across the broader population.
Confidence Interval
A confidence interval provides a range of values within which we expect the true population parameter to fall. For our survey, to construct a 95% confidence interval for the population proportion, we first determine the standard error: \[ SE = \sqrt{ \frac{\hat{p}(1-\hat{p})}{n} } \]. Using \hat{p} = 0.241\ and \ = 1000\, we get \SE \approx 0.0138\. Next, using the Z-value for a 95% confidence interval (1.96): \[ CI = \hat{p} \pm Z \cdot SE\]. Calculations yield \approx 0.241 \pm 1.96 \cdot 0.0138\, which equals approximately (0.214, 0.268). This means we're 95% confident that the true proportion of adults who bring their cell phones to the bathroom falls between 21.4% and 26.8%.
Random Sampling
Random sampling is a technique where each individual in the population has an equal chance of being included in the sample. It ensures that the sample is representative of the entire population, reducing the risk of bias. In the context of this survey, if the sample of 1000 adults was randomly selected, it enhances the reliability of our findings and increases the confidence that the sample proportion reflects the behavior of the broader population of adults aged 19 years or older.
Utilizing random sampling is fundamental in survey analysis because it supports the validity and generalizability of the results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Travelers pay taxes for flying, car rentals, and hotels. The following data represent the total travel tax for a 3 -day business trip in 8 randomly selected cities. Note: Chicago travel taxes are the highest in the country at \(\$ 101.27 .\) A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. $$ \begin{array}{llll} \hline 67.81 & 78.69 & 68.99 & 84.36 \\ \hline 80.24 & 86.14 & 101.27 & 99.29 \\ \hline \end{array} $$ (a) Determine a point estimate for the population mean travel \(\operatorname{tax}\) (b) Construct and interpret a \(95 \%\) confidence interval for the mean tax paid for a three-day business trip. (c) What would you recommend to a researcher who wants to increase the precision of the interval, but does not have access to additional data?

An urban economist wishes to estimate the proportion of Americans who own their homes. What size sample should be obtained if he wishes the estimate to be within 0.02 with \(90 \%\) confidence if (a) he uses a 2010 estimate of 0.669 obtained from the U.S. Census Bureau? (b) he does not use any prior estimates?

True or False: To construct a confidence interval about the mean, the population from which the sample is drawn must be approximately normal.

A researcher wishes to estimate the proportion of households that have broadband Internet access. What size sample should be obtained if she wishes the estimate to be within 0.03 with \(99 \%\) confidence if (a) she uses a 2009 estimate of 0.635 obtained from the National Telecommunications and Information Administration? (b) she does not use any prior estimates?

Suppose you have two populations: Population \(\mathrm{A}-\) All students at Illinois State University \((N=21,000)\) and Population \(\mathrm{B}-\) All residents of the city of Homer Glen, IL \((N=21,000)\). You want to estimate the mean age of each population using two separate samples each of size \(n=75\). If you construct a \(95 \%\) confidence interval for each population mean, will the margin of error for population A be larger, the same, or smaller than the margin of error for population \(\mathrm{B}\) ? Justify your reasoning.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.