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91Ó°ÊÓ

In response to the Great Depression, Franklin D. Roosevelt enacted many New Deal policies. One such policy was the enactment of the National Recovery Administration (NRA), which required business to agree to wages and prices within their particular industry. The thought was that this would encourage higher wages among the working class, thereby spurring consumption. In a Gallup survey conducted in 1933 of 2025 adult Americans, \(55 \%\) thought that wages paid to workers in industry were too low. The margin of error was 3 percentage points with \(95 \%\) confidence. Which of the following represents a reasonable interpretation of the survey results? For those that are not reasonable, explain the flaw. (a) We are \(95 \%\) confident \(55 \%\) of adult Americans during the Great Depression felt wages paid to workers in industry were too low. (b) We are \(92 \%\) to \(98 \%\) confident \(55 \%\) of adult Americans during the Great Depression felt wages paid to workers in industry were too low. (c) We are \(95 \%\) confident the proportion of adult Americans during the Great Depression who believed wages paid to workers in industry were too low was between 0.52 and 0.58 . (d) In \(95 \%\) of samples of adult Americans during the Great Depression, the proportion who believed wages paid to workers in industry were too low is between 0.52 and 0.58 ,

Short Answer

Expert verified
(c) and (d) represent reasonable interpretations of the survey results.

Step by step solution

01

Title - Understand the Margin of Error

The margin of error for the survey is given as 3 percentage points. This means the actual proportion is within 3 percentage points of the reported percentage, which is 55%.
02

Title - Calculate the Confidence Interval

To find the range of the confidence interval, subtract and add the margin of error to the sample proportion (0.55): Confidence interval = 0.55 - 0.03 = 0.52 (52%) 0.55 + 0.03 = 0.58 (58%) So, the confidence interval is between 0.52 and 0.58.
03

Title - Evaluate Option A

Option (a) says: 'We are 95% confident 55% of adult Americans during the Great Depression felt wages paid to workers in industry were too low.'This is incorrect because it does not account for the margin of error around 55%.
04

Title - Evaluate Option B

Option (b) says: 'We are 92% to 98% confident 55% of adult Americans during the Great Depression felt wages paid to workers in industry were too low.'This is incorrect because the confidence level should be precisely 95%, not a range of percentages.
05

Title - Evaluate Option C

Option (c) says: 'We are 95% confident the proportion of adult Americans during the Great Depression who believed wages paid to workers in industry were too low was between 0.52 and 0.58.'This is correct as it accurately reflects the confidence interval.
06

Title - Evaluate Option D

Option (d) says: 'In 95% of samples of adult Americans during the Great Depression, the proportion who believed wages paid to workers in industry were too low is between 0.52 and 0.58.'This is a correct interpretation of the confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

margin of error
The margin of error is a crucial concept when interpreting survey results. It represents the range within which we expect the true population parameter to lie. In the given exercise, the margin of error is 3 percentage points. This means that the reported 55% opinion could actually vary from 52% to 58%.
To find this range, you subtract and add the margin of error to the sample proportion.
For this example:
  • Lower bound: 55% - 3% = 52%
  • Upper bound: 55% + 3% = 58%
So, the confidence interval ranges from 0.52 to 0.58.
This range helps account for sampling variability and provides a buffer to show where the true proportion likely falls.
sample proportion
The sample proportion is the percentage of survey respondents who gave a particular response. In our case, the sample proportion is 55%. This means that out of the 2025 surveyed adult Americans in 1933, 55% felt that wages in industry were too low.
Sample proportion is a point estimate which means it is an estimate of the population proportion. It’s important to remember that the sample proportion alone does not tell the full story. This is where the margin of error and confidence interval come in, providing a more complete picture.
confidence level
Confidence level indicates the probability that the confidence interval contains the true population parameter. In our example, the confidence level is 95%. This means that if we were to take 100 different samples and build confidence intervals for each of them, we would expect about 95 of those intervals to contain the true proportion of the population.
Some important points about the 95% confidence level:
  • It shows a high level of certainty, making it a robust measure.
  • It does not mean there is a 95% chance that the true parameter is within the interval for any single sample—it’s about long-run performance over multiple samples.
By understanding these concepts, you can more accurately interpret survey results and the likelihood that they reflect the broader population’s views.

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Most popular questions from this chapter

In March 2014, Harris Interactive conducted a poll of a random sample of 2234 adult Americans 18 years of age or older and asked, "Which is more annoying to you, tailgaters or slow drivers who stay in the passing lane?" Among those surveyed, 1184 were more annoyed by tailgaters. (a) Explain why the variable of interest is qualitative with two possible outcomes. What are the two outcomes? (b) Verify the requirements for constructing a \(90 \%\) confidence interval for the population proportion of all adult Americans who are more annoyed by tailgaters than slow drivers in the passing lane. (c) Construct a \(90 \%\) confidence interval for the population proportion of all adult Americans who are more annoyed by tailgaters than slow drivers in the passing lane.

The American Society for Microbiology (ASM) and the Soap and Detergent Association (SDA) jointly commissioned two separate studies, both of which were conducted by Harris Interactive. In one of the studies, 1001 adults were interviewed by telephone and asked about their handwashing habits. In the telephone interviews, 921 of the adults said they always wash their hands in public restrooms. In the other study, the hand-washing behavior of 6076 adults was inconspicuously observed within public restrooms in four U.S. cities and 4679 of the 6076 adults were observed washing their hands. (a) In the telephone survey, what is the variable of interest? Is it qualitative or quantitative? (b) What is the sample in the telephone survey? What is the population to which this study applies? (c) Verify that the requirements for constructing a confidence interval for the population proportion of adults who say they always wash their hands in public restrooms are satisfied. (d) Using the results from the telephone interviews, construct a \(95 \%\) confidence interval for the proportion of adults who say they always wash their hands in public restrooms. (e) In the study where hand-washing behavior was observed, what is the variable of interest? Is it qualitative or quantitative? (f) We are told that 6076 adults were inconspicuously observed, but were not told how these adults were selected. We know randomness is a key ingredient in statistical studies that allows us to generalize results from a sample to a population. Suggest some ways randomness might have been used to select the individuals in this study. (g) Verify the requirements for constructing a confidence interval for the population proportion of adults who actually washed their hands while in a public restroom. (h) Using the results from the observational study, construct a \(95 \%\) confidence interval for the proportion of adults who wash their hands in public restrooms. (i) Based on your findings in parts (a) through (h), what might you conclude about the proportion of adults who say they always wash their hands versus the proportion of adults who actually wash their hands in public restrooms? (j) Cite some sources of variability in both studies.

Alan wants to estimate the proportion of adults who walk to work. In a survey of 10 adults, he finds 1 who walk to work. Explain why a \(95 \%\) confidence interval using the normal model yields silly results. Then compute and interpret a \(95 \%\) confidence interval for the proportion of adults who walk to work using Agresti and Coull's method.

In a survey of 1008 adult Americans, the Gallup organization asked, "When you retire, do you think you will have enough money to live comfortably or not?" Of the 1008 surveyed, 526 stated that they were worried about having enough money to live comfortably in retirement. Construct a \(90 \%\) confidence interval for the proportion of adult Americans who are worried about having enough money to live comfortably in retirement.

The following small data set represents a simple random sample from a population whose mean is \(50 .\) $$ \begin{array}{llllll} \hline 43 & 63 & 53 & 50 & 58 & 44 \\ \hline 53 & 53 & 52 & 41 & 50 & 43 \\ \hline \end{array} $$ (a) A normal probability plot indicates that the data could come from a population that is normally distributed with no outliers. Compute a \(95 \%\) confidence interval for this data set. (b) Suppose that the observation, 41 , is inadvertently entered into the computer as 14 . Verify that this observation is an outlier (c) Construct a \(95 \%\) confidence interval on the data set with the outlier. What effect does the outlier have on the confidence interval? (d) Consider the following data set, which represents a simple random sample of size 36 from a population whose mean is 50\. Verify that the sample mean for the large data set is the same as the sample mean for the small data set from part (a). $$ \begin{array}{llllll} \hline 43 & 63 & 53 & 50 & 58 & 44 \\ \hline 53 & 53 & 52 & 41 & 50 & 43 \\ \hline 47 & 65 & 56 & 58 & 41 & 52 \\ \hline 49 & 56 & 57 & 50 & 38 & 42 \\ \hline 59 & 54 & 57 & 41 & 63 & 37 \\ \hline 46 & 54 & 42 & 48 & 53 & 41 \\ \hline \end{array} $$ (e) Compute a \(95 \%\) confidence interval for the large data set. Compare the results to part (a). What effect does increasing the sample size have on the confidence interval? (f) Suppose that the last observation, 41 , is inadvertently entered as 14 . Verify that this observation is an outlier. (g) Compute a \(95 \%\) confidence interval for the large data set with the outlier. Compare the results to part (e). What effect does an outlier have on a confidence interval when the data set is large?

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