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Construct a confidence interval of the population proportion at the given level of confidence. \(x=540, n=900,96 \%\) confidence

Short Answer

Expert verified
The 96% confidence interval is \[0.5665, 0.6335\].

Step by step solution

01

Calculate the Sample Proportion

The sample proportion (\hat{p}) is found by dividing the number of successes (x) by the sample size (n). Use the formula \(\text{\hat{p}} = \frac{x}{n}\). In this case, \(\text{\hat{p}} = \frac{540}{900} = 0.6\).
02

Calculate the Standard Error

The standard error (SE) of the sample proportion is calculated using the formula \[ \text{SE} = \sqrt{\frac{\text{\hat{p}} (1 - \text{\hat{p}})}{n}} \]. Substituting the values: \[ \text{SE} = \sqrt{\frac{0.6 \times 0.4}{900}} = 0.01633 \].
03

Find the Z-Score for the Confidence Level

For a 96% confidence level, we need to find the critical value (Z-score). The Z-score corresponding to a 96% confidence level is approximately 2.05.
04

Calculate the Margin of Error

The margin of error (ME) is calculated using the formula \(\text{ME} = Z \times \text{SE} \). Substituting the Z-score and the standard error, we get: \(\text{ME} = 2.05 \times 0.01633 = 0.0335\).
05

Construct the Confidence Interval

The confidence interval for the population proportion is given by \(\text{\hat{p}} \pm \text{ME}\). Thus, the interval is \[ 0.6 \pm 0.0335 \]. Therefore, the confidence interval is \[ 0.5665 \text{ to } 0.6335 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sample proportion
Understanding the concept of sample proportion is essential for constructing confidence intervals. The sample proportion, denoted as \(\text{\hat{p}}\), represents the fraction of the sample that exhibits a certain characteristic or success. It is computed using the formula:
\[ \text{\hat{p}} = \frac{x}{n} \] where \(x\) is the number of successes in the sample, and \(n\) is the total sample size.
In our example, there are 540 successes out of 900 total observations, so the sample proportion is calculated as \[ \text{\hat{p}} = \frac{540}{900} = 0.6 \. \]
This tells us that 60% of the sample exhibits the characteristic of interest.
standard error
Next, let's delve into the standard error (SE) which is a crucial component in confidence interval calculations. The standard error provides a measure of how much the sample proportion is expected to vary from the true population proportion due to random sampling. The formula to compute standard error is:
\[ \text{SE} = \sqrt{\frac{\text{\hat{p}} (1 - \text{\hat{p}})}{n}} \. \]
Substituting in our values, with \( \text{\hat{p}} = 0.6 \) and \( n = 900 \), we get:
\[ \text{SE} = \sqrt{\frac{0.6 \times 0.4}{900}} = 0.01633 \. \]
So, the standard error here is approximately 0.01633. This helps us understand the accuracy of our sample proportion in estimating the true population proportion.
Z-score
Z-score, also known as the standard normal deviate, is another important concept. It represents the number of standard deviations a data point is from the mean in a standard normal distribution. For confidence interval calculations, the Z-score is used to determine the critical value corresponding to the desired confidence level.
Common confidence levels and their corresponding Z-scores include:
  • 90%: Z = 1.645
  • 95%: Z = 1.96
  • 96%: Z = 2.05
  • 99%: Z = 2.576
In our example, for a 96% confidence level, the Z-score is 2.05. This means that in a normal distribution, 96% of the area under the curve lies within 2.05 standard deviations of the mean.
margin of error
The margin of error (ME) combines the Z-score and the standard error to provide a range within which we can expect the true population proportion to lie. It is calculated using the formula:
\[ \text{ME} = Z \times \text{SE} \. \]
Using our values, \( Z = 2.05 \) and \( \text{SE} = 0.01633 \, \) we get:
\[ \text{ME} = 2.05 \times 0.01633 = 0.0335 \. \]
So, the margin of error is approximately 0.0335. Finally, we construct the confidence interval by adding and subtracting the margin of error from the sample proportion:
The confidence interval is \[ 0.6 \pm 0.0335, \] or equivalently \[ 0.5665 \text{ to } 0.6335 \. \]
This interval suggests that we are 96% confident that the true population proportion lies between 0.5665 and 0.6335.

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Most popular questions from this chapter

A simple random sample of size \(n\) is drawn from a population that is known to be normally distributed. The sample variance, \(s^{2},\) is determined to be 19.8 (a) Construct a \(95 \%\) confidence interval for \(\sigma^{2}\) if the sample size, \(n,\) is 10 (b) Construct a \(95 \%\) confidence interval for \(\sigma^{2}\) if the sample size, \(n\), is \(25 .\) How does increasing the sample size affect the width of the interval? (c) Construct a \(99 \%\) confidence interval for \(\sigma^{2}\) if the sample size, \(n\), is \(10 .\) Compare the results with those obtained in part (a). How does increasing the level of confidence affect the width of the confidence interval?

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In a survey conducted by the marketing agency 11 mark, 241 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom (confessions included texting and answering phone calls). (a) What is the sample in this study? What is the population of interest? (b) What is the variable of interest in this study? Is it qualitative or quantitative? (c) Based on the results of this survey, obtain a point estimate for the proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom. (d) Explain why the point estimate found in part (c) is a statistic. Explain why it is a random variable. What is the source of variability in the random variable? (e) Construct and interpret a \(95 \%\) confidence interval for the population proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom. (f) What ensures that the results of this study are representative of all adults 19 years of age or older?

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