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Assume that the random variable \(X\) is normally distributed, with mean \(\mu=50\) and standard deviation \(\sigma=7\). Find each indicated percentile for \(X\) The 38 th percentile

Short Answer

Expert verified
The 38th percentile is approximately 47.83.

Step by step solution

01

- Identify the Z-score for the 38th percentile

The Z-score corresponding to the 38th percentile (or the 0.38 percentile) can be found using a standard normal distribution table. Locate the closest value in the table to 0.38 in the cumulative probability, which is approximately -0.31.
02

- Use the Z-score formula

The formula to convert a Z-score to an X value in a normally distributed dataset is given by: X = μ + Zσ where μ = 50 σ = 7 Z = -0.31
03

- Plug in the values

Substitute the values into the Z-score formula: X = 50 + (-0.31)(7) Calculate the result.
04

- Calculate the final value

Perform the arithmetic operations: X = 50 - 2.17 Therefore, X ≈ 47.83.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentile
A percentile measures the relative standing of a value within a dataset. It indicates the proportion of data points below a certain value. For instance, the 38th percentile means that 38% of the data falls below that value. Percentiles are very useful in understanding distributions in various fields like education, healthcare, and finance.
In our example, we find the value corresponding to the 38th percentile in a normally distributed dataset with a mean (\(\mu\)) of 50 and a standard deviation (\(\sigma\)) of 7. To do this, we convert the 38th percentile to a Z-score using the standard normal distribution.
Z-score
A Z-score, also known as a standard score, measures how many standard deviations an element is from the mean. The Z-score is a way to compare individual data points relative to the overall distribution. It is calculated using the formula:

Z = (X - \(\mu\))/\(\sigma\)

Here, we already have a pre-calculated Z-score for the 38th percentile, which is approximately -0.31. This negative value indicates that the 38th percentile is below the mean of the data. For our purposes, we need to convert this Z-score back into the original units of our distribution, which is done using the formula:

X = \(\mu\) + Z\(\sigma\)
Standard Normal Distribution
A standard normal distribution is a special case of the normal distribution where the mean is 0 and the standard deviation is 1. These values are represented by a Z-score. This distribution is useful because it allows for standardizing different datasets, making it easier to perform comparisons and calculations.
In our example, we use the standard normal distribution to find the Z-score corresponding to a given percentile. Once the Z-score is determined, it can be converted using the original distribution's mean and standard deviation to find the specific value within that dataset.

We saw that the Z-score for the 38th percentile is -0.31. Using the given mean (\(\mu = 50\)) and standard deviation (\(\sigma = 7\)), we find the exact value in our original normal distribution:

X = 50 + (-0.31)(7) = 50 - 2.17 = 47.83. So, the 38th percentile corresponds to approximately 47.83 in our dataset.

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