/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Assume that the random variable ... [FREE SOLUTION] | 91Ó°ÊÓ

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Assume that the random variable \(X\) is normally distributed, with mean \(\mu=50\) and standard deviation \(\sigma=7\). Find each indicated percentile for \(X\) The 9 th percentile

Short Answer

Expert verified
The 9th percentile for X is approximately 40.62.

Step by step solution

01

Understand the Percentile Concept

Percentiles indicate the value below which a given percentage of observations in a group of observations fall. The 9th percentile means we are looking for the value of X below which 9% of the data lies.
02

Standardize the Percentile

Convert the percentile into its corresponding Z-score using a Z-table. For the 9th percentile, find the Z-score that corresponds to a cumulative probability of 0.09. Looking at the Z-table, the Z-score is approximately -1.34.
03

Use the Z-score Formula

Use the Z-score formula to find the value of X. The Z-score formula is given by: \[ Z = \frac{X - \mu}{\sigma} \] Rearrange to solve for X: \[ X = Z \cdot \sigma + \mu \]
04

Substitute the Values

Substitute for the Z-score, mean (\(\mu\)), and standard deviation (\(\sigma\)): \[ X = (-1.34) \cdot 7 + 50 \]
05

Calculate the Value of X

\[ X = -1.34 \times 7 + 50 = -9.38 + 50 = 40.62 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

normal distribution
A normal distribution, also known as a Gaussian distribution, describes how the values of a variable are distributed. It is symmetric, with most values clustering around a central mean, and fewer values appearing as you move away from the mean. This type of distribution graphically forms a bell curve. In our exercise, the random variable X follows a normal distribution with a mean (\(\mu\)) of 50 and a standard deviation (\(\sigma\)) of 7. These values tell us that the average value of X is 50 and the data tends to spread out around this mean by an average of 7 units.
percentile
Percentiles are a measure in statistics that indicate the relative standing of a value within a dataset. A specific percentile tells you what percentage of the data falls below a certain value. For instance, if you are looking for the 9th percentile, you are seeking the value below which 9% of your data lies. This is crucial for understanding how values compare within a distribution. Our problem asks us to find the 9th percentile of the normal distribution for X, meaning we need to determine the value below which 9% of X values fall.
Z-score
The Z-score is a statistical tool that measures how many standard deviations a data point is from the mean. To find the percentile of a normally distributed variable X, we first convert the percentile into a Z-score. This involves finding a Z-score that corresponds to a given cumulative probability using a Z-table. In our problem, we need the Z-score that corresponds to 0.09 (the 9th percentile). From the Z-table, this Z-score is approximately -1.34. Using the Z-score formula: \[ Z = \frac{X - \mu}{\sigma} \] we can solve for X: \[ X = Z \cdot \sigma + \mu \] Plugging in our values: \(-1.34 \cdot 7 + 50 \), we find that X equals approximately 40.62.
statistics education
Understanding key statistical concepts like normal distribution, percentiles, and Z-scores equips students with essential tools for analyzing data. These concepts are foundational in statistics education because they enable students to interpret data distributions and their respective probabilities accurately. Calculating percentiles, as demonstrated in our exercise, is a practical application that showcases how these principles work together. This knowledge can be applied in various fields, including social sciences, business, and natural sciences, making it a valuable addition to any educational curriculum. By mastering these concepts, students enhance their analytical skills and are better prepared for more advanced statistical studies.

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Most popular questions from this chapter

Explain why \(P(X \leq 220)\) should be reported as \(>0.9999\) if \(X\) is a normal random variable with mean 100 and standard deviation \(15 .\)

Researchers conducted a prospective cohort study in which male patients who had an out-of-hospital cardiac arrest were submitted to therapeutic hypothermia (intravenous infusion of cold saline followed by surface cooling with the goal of maintaining body temperature of 33 degrees Celsius for 24 hours. Note that normal body temperature is 37 degrees Celsius). The survival status, length of stay in the intensive care unit (ICU), and time spent on a ventilator were measured. Each of these variables was compared to a historical cohort of patients who were treated prior to the availability of therapeutic hypothermia. Of the 52 hypothermia patients, 37 survived; of the 74 patients in the control group, 43 survived. The median length of stay among survivors for the hypothermia patients was 14 days versus 21 days for the control group. The time on the ventilator among survivors for the hypothermia group was 219 hours versus 328 hours for the control group. (a) What does it mean to say this is a prospective cohort study? (b) What is the explanatory variable in the study? Is it qualitative or quantitative? (c) What are the three response variables in the study? For each, state whether the variable is qualitative or quantitative. (d) Is time on the ventilator a statistic or parameter? Explain. (e) To what population does this study apply? (f) Based on the results of this study, what is the probability a randomly selected male who has an out-of-hospital cardiac arrest and submits to therapeutic hypothermia wil survive? What about those who do not submit to therapeutic hypothermia?

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