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Ken and Dorothy like to fly to Colorado for ski vacations. Sometimes, however, they are late for their flight. On the air carrier they prefer to fly, the probability that luggage gets lost is 0.012 for luggage checked at least one hour prior to departure. However, the probability luggage gets lost is 0.043 for luggage checked within one hour of departure. Are the events "luggage check time" and "lost luggage" independent? Explain.

Short Answer

Expert verified
No, they are not independent because P(B | A) ≠ P(B).

Step by step solution

01

- Understand Independence

Two events, A and B, are independent if the occurrence of one does not affect the probability of the occurrence of the other. Mathematically, events A and B are independent if and only if P(A ∩ B) = P(A) * P(B)
02

- Define Events

Let A be the event that the luggage is checked at least one hour prior to departure, and B be the event that the luggage is lost.
03

- Assign Probabilities

P(B | A) = 0.012 (probability luggage is lost given it was checked ≥ 1 hour prior) P(B | A^c) = 0.043 (probability luggage is lost given it was checked < 1 hour prior)P(A^c) = 1 - P(A)
04

- Check Independence

For events A and B to be independent, P(B | A) = P(B)From the information given, since P(B | A) ≠ P(B | A^c), we conclude that P(B) is influenced by whether A occurs or not.
05

- Conclude

Since P(B | A) ≠ P(B), we conclude that the events 'luggage check time' and 'lost luggage' are not independent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Conditional Probability
Conditional probability helps us understand how likely an event is, given that another related event has happened. It’s denoted as \( P(A | B) \), meaning the probability of event A occurring given that event B has already occurred. For example, the problem mentions the probability of luggage getting lost if it was checked within one hour of departure. This is different from checking luggage earlier. Knowing these specific conditions allows us to make more accurate predictions based on known circumstances.

Think of it this way: If you bring an umbrella because it’s likely to rain (given dark clouds), you're using conditional probability. This principle helps in making decisions and predictions based on additional information.
  • Formula: \(P(A | B) = \frac{P(A \text{ and } B)}{P(B)}\)
  • Example: Probability luggage is lost given early check-in: 0.012.
Understanding Independence of Events
Events are independent if the occurrence of one event does not impact the likelihood of the other. This is an essential aspect of probability. Mathematically, events A and B are independent if:
\( P(A \text{ and } B) = P(A) \times P(B) \).
In simpler terms, knowing that event A happened does nothing to change the probability of event B happening.

In our problem, independence means that checking luggage later should not change the probability of it being lost. However, the solution shows that the luggage's check time does impact the probability of it getting lost. If the probabilities change based on check-in time, the events are not independent.
  • Formula: \(P(B | A) = P(B)\)
  • Example: Probability of lost luggage is affected by check-in time, thus not independent.
Probability Rules You Need to Know
Probability rules are the backbone of calculating and understanding probabilities. They help us determine the likelihood of single events and combinations of events. Some key rules are:

  • Product Rule (Multiplication Rule): For independent events, the probability of both occurring is the product of their individual probabilities: \(P(A \text{ and } B) = P(A) \times P(B)\).
  • Sum Rule (Addition Rule): For mutually exclusive events, the probability of either occurring is the sum of their probabilities: \(P(A \text{ or } B) = P(A) + P(B)\).
  • Complement Rule: The probability of an event not occurring is 1 minus the probability of it occurring: \(P(A^c) = 1 - P(A)\).

These rules help build the framework for more complicated probability questions. In our specific problem, understanding these rules helps prove that luggage check time affects the likelihood of losing it, showing dependence between these events.

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