/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 According to the National Center... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

According to the National Center for Health Statistics, there is a \(20.3 \%\) probability that a randomly selected resident of the United States aged 18 years or older is a smoker. In addition, there is a \(44.5 \%\) probability that a randomly selected resident of the United States aged 18 years or older is female, given that he or she smokes. What is the probability that a randomly selected resident of the United States aged 18 years or older is female and smokes? Would it be unusual to randomly select a resident of the United States aged 18 years or older who is female and smokes?

Short Answer

Expert verified
The probability is 0.090335 and it would not be unusual.

Step by step solution

01

Identify Given Probabilities

Given probabilities are: 1. Probability that a resident is a smoker, \( P(S) = 0.203 \).2. Probability that a resident is a female given that the resident smokes, \( P(F|S) = 0.445 \).
02

Use Conditional Probability Formula

Use the conditional probability formula to find the joint probability that a resident is female and smokes. The formula is: \( P(F \cap S) = P(F|S) \times P(S) \).
03

Substitute Values into the Formula

Substitute the given probabilities into the formula:\[ P(F \cap S) = 0.445 \times 0.203 \approx 0.090335 \].
04

Compare to the Criterion for Unusual Events

An event is considered unusual if its probability is less than 0.05. Compare the calculated probability to this criterion.
05

Conclusion

Since \( P(F \cap S) \approx 0.090335 \) which is greater than 0.05, it would not be considered unusual for a randomly selected resident of the United States aged 18 years or older to be female and smoke.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

joint probability
Joint probability is the measure of two events happening at the same time. It helps us understand the likelihood of two or more events occurring together. In the given exercise, we want to find the probability that a randomly selected resident is both female and a smoker.

Remember the formula: \( P(A \cap B) \) which is the joint probability of events A and B. Here, we have A being 'female' and B being 'smoker'.

Using the conditional probability formula: \( P(F \cap S) = P(F|S) \times P(S) \)
The term \( P(F|S) \) represents the probability of being a female given that the person smokes. \( P(S) \) is the probability of being a smoker.

Substitute the given values:
  • Probability of being a smoker \( P(S) = 0.203 \)
  • Probability of being a female given that the person smokes \( P(F|S) = 0.445 \)
So, we calculate: \[ P(F \cap S) = 0.445 \times 0.203 \approx 0.090335 \]

This tells us there is approximately a 9.03% chance that a randomly selected resident is both female and a smoker.
probability of smoking
Understanding the likelihood of an individual smoking can offer valuable health and behavioral insights. In this exercise, we're given the probability that a person smokes, 0.203 or 20.3%. This means that out of every 100 individuals, roughly 20 to 21 individuals are expected to be smokers.

If we were to visualize this probability, think of it like drawing 20 smokers out of a pool of 100 people at random. It’s a relatively straightforward concept but foundational to understanding more complex probabilities.

When dealing with probability, always remember:
  • Probability is a measure of how likely an event is to occur.
  • The probability value ranges between 0 and 1, where 0 indicates impossibility and 1 indicates certainty.
  • A probability of 0.203 means there is a 20.3% chance of the event occurring.
This provides a basis for calculating joint probabilities, like finding the probability of being both a female and a smoker in the exercise.
unusual events criterion
In statistics, an event is considered unusual if its probability is less than 0.05 (or 5%). This criterion helps us identify occurrences that are rare or exceptional.

For example, if an event happens less than 5 times out of 100, it’s deemed unusual. This helps in making decisions and drawing conclusions based on how common or rare an event is.

In our exercise, we calculated the joint probability of a resident being female and a smoker to be approximately 0.090335 (or 9.03%).

Since 0.090335 is greater than 0.05, this event is not considered unusual. It suggests that encountering a female smoker in the population is relatively common and not a rare occurrence.

The unusual events criterion is a handy tool to quickly judge the commonality of an occurrence without needing complex analysis. This criterion answers questions like:
  • Is it rare to find someone with these characteristics?
  • Should this finding be surprising?
By comparing the event probability with the 0.05 threshold, we can easily determine whether an event is unusual or not.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that you roll a pair of dice 1000 times and get seven 350 times. Based on these results, what is the probability that the next roll results in seven?

The following data represent the number of live multiple-delivery births (three or more babies) in 2012 for women 15 to 54 years old. $$ \begin{array}{lc} \text { Age } & \text { Number of Multiple Births } \\ \hline 15-19 & 44 \\ \hline 20-24 & 404 \\ \hline 25-29 & 1204 \\ \hline 30-34 & 1872 \\ \hline 35-39 & 1000 \\ \hline 40-44 & 332 \\ \hline 45-54 & 63 \end{array} $$ (a) Construct a probability model for number of multiple births. (b) In the sample space of all multiple births, are multiple births for 15 - to 19 -year-old mothers unusual? (c) In the sample space of all multiple births, are multiple births for 40 - to 44 -year-old mothers unusual?

Suppose that a satellite defense system is established in which four satellites acting independently have a 0.9 probability of detecting an incoming ballistic missile. What is the probability that at least one of the four satellites detects an incoming ballistic missile? Would you feel safe with such a system?

Todd is putting together an exercise routine and feels that the sequence of exercises can affect his overall performance. He has 12 exercises to select from, but only has enough time to do \(9 .\) How many different exercise routines could he put together?

Four members from a 50-person committee are to be selected randomly to serve as chairperson, vice-chairperson, secretary, and treasurer. The first person selected is the chairperson; the second, the vice-chairperson; the third, the secretary; and the fourth, the treasurer. How many different leadership structures are possible?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.