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In how many ways can three men and three women be seated around a circular table (that seats six) assuming that women and men must alternate seats?

Short Answer

Expert verified
12

Step by step solution

01

Fix a Reference Point

In circular permutations, one position needs to be fixed to avoid counting rotations as different arrangements. Fix the position of one of the men.
02

Arrange the Remaining People

With one man fixed, there are two remaining men and three women to be arranged in the alternating seats pattern. Consider the seats to alternate: M-W-M-W-M-W, where M is a man and W is a woman.
03

Permute the Remaining Men

There are 2 remaining men to place in the M slots. The number of ways to arrange these two men is given by: \[ P_2 = 2! = 2 \]
04

Permute the Women

There are 3 women to place in the W slots. The number of ways to arrange these three women is given by: \[ P_3 = 3! = 6 \]
05

Combine the Arrangements

The total number of ways to arrange the men and women around the table is the product of the permutations of men and women: \[ 2 \times 6 = 12 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics that studies counting, arrangement, and combination of objects. In this problem, we use combinatorics to determine the number of ways to arrange three men and three women around a circular table. This involves considering different permutations and combinations while ensuring that men and women alternate in the seating arrangement. By breaking down the problem into simpler steps and using combinatorial principles, we can systematically count the valid seating arrangements.
Factorial
Understanding factorials is crucial in solving this problem. A factorial, denoted as \(!n\), represents the product of all positive integers up to \(!n\). For example: \(2! = 2 \times 1 = 2\) and \(3! = 3 \times 2 \times 1 = 6\).

In this exercise, the factorials help us count the permutations of men and women. By fixing one man to avoid redundancy from rotations, we consider the remaining people. The number of ways to arrange the remaining men is \(!2 = 2!\) and for the remaining women is \(!3 = 3!\). By multiplying these permutations, we get the total number of valid seating arrangements.
Alternating Arrangement
In this problem, we need an alternating arrangement where men and women sit in alternating seats. This ensures that no two men or two women are seated next to each other. To achieve this:
  • Fix one man in a seat to set a reference point.
  • Arrange the remaining men in the available man slots.
  • Arrange the women in the remaining slots.
Since the men and women need to alternate, the pattern will be M-W-M-W-M-W. By following these steps and combining the individual permutations of men and women, we arrive at the total number of ways to achieve this alternating seating arrangement around the circular table.

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