/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Suppose that a local area networ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that a local area network requires eight letters for user names. Lower- and uppercase letters are considered the same. How many user names are possible for the local area network?

Short Answer

Expert verified
208,827,064,576 possible user names.

Step by step solution

01

Determine the number of available symbols

Since lowercase and uppercase letters are considered the same, each letter of the alphabet can represent one of 26 possible characters (a to z).
02

Number of positions for the username

The username consists of eight positions.
03

Calculate the number of possible user names

Each position in the username can be filled by any of the 26 letters. Therefore, the total number of combinations can be calculated using the formula: 26^8, which represents 26 choices for each of the 8 positions.
04

Compute the result

Calculate the value of 26^8: 26^8 = 208,827,064,576.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

username combinations
Understanding how to form unique usernames is vital in fields like computer science and information security. In our exercise, a username must be composed of eight letters.

If you consider the English alphabet, there are 26 letters from 'a' to 'z'. Because lower- and uppercase letters are treated the same (e.g., 'A' and 'a' are identical), each position in the username can be one of 26 possible characters. This simplifies our problem since we don't have to worry about differentiating between upper- and lowercase.

So to create a username, you simply choose one letter for each of the eight positions. This is where the concept of combinations comes into play, and we use combinatorial analysis to further explore this calculation.
combinatorial analysis
Combinatorial analysis helps us figure out how many possible combinations there are when selecting items from a larger pool. In our case, it's the number of different eight-letter usernames possible.

Each of the eight positions in a username can be any one of 26 letters. This is a case of permutations with repetition since each position can have any letter independent of the other positions.

The number of possible combinations can be calculated using the formula for permutations with repetition: \[\begin{equation} 26^8 \text{ (where 26 is the number of letters, and 8 is the number of positions).} \ \textrm{Therefore,} \ 26^8 = 208,827,064,576. \ \text{This means there are 208,827,064,576 different possible usernames.}\end{equation}\]
probability calculations
Now, let's tie this into probability. Probability helps us understand the likelihood of certain outcomes, like generating a specific username among all possible combinations. If you randomly generate one username out of 208,827,064,576 possible options, the probability of getting a particular username is: \[\begin{equation}\frac{1}{26^8} = \frac{1}{208,827,064,576} \end{equation}\]

This number is quite small, which shows the uniqueness and vastness of potential usernames. Probability helps underline the security aspect of choosing usernames, showing how unlikely it is to guess a particular username by chance.
statistical problem solving
Statistical problem solving involves breaking down a problem into manageable parts, much like we did in this exercise. By understanding the core principles of combinatorics and probability, we tackled the username problem step by step.

First, we identified the number of possible characters (26 for each position). Then, we used combinatorial analysis to determine the total number of possible usernames ( \[\begin{equation} 26^8 \end{equation}\]). Finally, we applied probability calculations to understand how likely it is to generate a specific username.

Approaching problems systematically like this makes complex statistical challenges easier to grasp and solve.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Outside a home there is a keypad that will open the garage if the correct four-digit code is entered. (a) How many codes are possible? (b) What is the probability of entering the correct code on the first try, assuming that the owner doesn’t remember the code?

Fingerprints are now widely accepted as a form of identification. In fact, many computers today use fingerprint identification to link the owner to the computer. In \(1892,\) Sir Francis Galton explored the use of fingerprints to uniquely identify an individual. A fingerprint consists of ridgelines. Based on empirical evidence, Galton estimated the probability that a square consisting of six ridgelines that covered a fingerprint could be filled in accurately by an experienced fingerprint analyst as \(\frac{1}{2}\). (a) Assuming that a full fingerprint consists of 24 of these squares, what is the probability that all 24 squares could be filled in correctly, assuming that success or failure in filling in one square is independent of success or failure in filling in any other square within the region? (This value represents the probability that two individuals would share the same ridgeline features within the 24 -square region.) (b) Galton further estimated that the likelihood of determining the fingerprint type (e.g., arch, left loop, whorl, etc.) as \(\left(\frac{1}{2}\right)^{4}\) and the likelihood of the occurrence of the correct number of ridges entering and exiting each of the 24 regions as \(\left(\frac{1}{2}\right)^{8}\). Assuming that all three probabilities are independent, compute Galton's estimate of the probability that a particular fingerprint configuration would occur in nature (that is, the probability that a fingerprint match occurs by chance).

A flush in the card game of poker occurs if a player gets five cards that are all the same suit (clubs, diamonds, hearts, or spades). Answer the following questions to obtain the probability of being dealt a flush in five cards. (a) We initially concentrate on one suit, say clubs. There are 13 clubs in a deck. Compute \(P(\) five clubs \()=P(\) first card is clubs and second card is clubs and third card is clubs and fourth card is clubs and fifth card is clubs). (b) A flush can occur if we get five clubs or five diamonds or five hearts or five spades. Compute \(P\) (five clubs or five diamonds or five hearts or five spades). Note that the events are mutually exclusive.

How many different simple random samples of size 5 can be obtained from a population whose size is 50?

A family has six children. If this family has exactly two boys, how many different birth and gender orders are possible?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.