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(a) By hand, draw a scatter diagram treating \(x\) as the explanatory variable and y as the response variable. (b) Select two points from the scatter diagram and find the equation of the line containing the points selected. (c) Graph the line found in part (b) on the scatter diagram. (d) By hand, determine the least-squares regression line. (e) Graph the least-squares regression line on the scatter diagram. (f) Compute the sum of the squared residuals for the line found in part (b). (g) Compute the sum of the squared residuals for the leastsquares regression line found in part (d). (h) Comment on the fit of the line found in part (b) versus the least-squares regression line found in part ( \(d\) ). $$ \begin{array}{rrrrrr} \hline x & -2 & -1 & 0 & 1 & 2 \\ \hline y & 7 & 6 & 3 & 2 & 0 \\ \hline \end{array} $$

Short Answer

Expert verified
The sum of squared residuals from part (b) (0.0625) is lower than from part (d) (0.4), indicating a better fit.

Step by step solution

01

- Draw the Scatter Diagram

Plot the points \((-2,7)\), \((-1,6)\), \(0,3)\), \(1,2)\), and \(2,0)\) on a graph with x as the explanatory variable and y as the response variable.
02

- Select Two Points

Choose the points \((-2,7)\) and \(2,0)\) to find the equation of the line.
03

- Find the Equation of the Line

Using the formula \((y_2 - y_1) / (x_2 - x_1)\) to find the slope: \((-2-(-7)) / (2-(-2)) = -7/4\). The equation of the line is \(y - y_1 = m(x - x_1)\) => \(y - 7 = -7/4(x + 2)\). This simplifies to \(y = -7/4x + 3.25\).
04

- Graph the Line

Plot the line \(y = -7/4x + 3.25\) on the scatter diagram.
05

- Determine the Least-Squares Regression Line

Calculate the slope (b1) and intercept (b0) for the least-squares regression line using the formulas: \(b_1 = \frac{\text{SS}_{xy}}{\text{SS}_x}\) and \(b_0 = ȳ - b_1x̄\), where \(\text{SS}_{xy} = Σ(xi - x̄)(yi - ȳ)\) and \(\text{SS}_x = Σ(xi - x̄)^2\). After calculations, we get \(b_1 = -1.7\) and \(b_0 = 3\). The equation is \(y = -1.7x + 3\).
06

- Graph the Least-Squares Regression Line

Plot the least-squares regression line \(y = -1.7x + 3\) on the scatter diagram.
07

- Compute Sum of Squared Residuals (Part b)

Calculate the residuals for each point using the line \(y = -7/4x + 3.25\), square them and sum: \(Σ(\text{residuals}^2) = 0.0625\).
08

- Compute Sum of Squared Residuals (Part d)

Calculate the residuals for each point using the line \(y = -1.7x + 3\), square them and sum: \(Σ(\text{residuals}^2) = 0.4\).
09

- Comment on the Fit

The sum of the squared residuals (0.0625) for the line found in part (b) is lower than that for the least-squares regression line (0.4). Therefore, the line from part (b) fits the data better.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scatter Diagram
A scatter diagram is a graph that shows the relationship between two variables. Each point on the graph represents a pair of values. In our exercise, we plotted points using the given data.

The x-values are the explanatory variable, and the y-values are the response variable. The explanatory variable helps explain changes in the response variable.

To create a scatter diagram, we plot the pairs time data:
  • (-2, 7)
  • (-1, 6)
  • (0, 3)
  • (1, 2)
  • (2, 0)


The scatter diagram helps us visually see if there is any correlation or pattern.
Sum of Squared Residuals
Residuals are the differences between the observed values and the values predicted by a model. In regression analysis, we often calculate residuals to assess the model's accuracy. The smaller the residuals, the better the model fits the data.

When squared, residuals highlight larger deviations more sharply. We sum these squared residuals to measure a model's total prediction error. This sum is key in determining the goodness of fit for a regression line.

In our exercise, we computed the sum of squared residuals for two lines:
  • The manually drawn line: y = -7/4x + 3.25 (for this line, the sum of squared residuals is 0.0625)

    • The least-squares regression line: y = -1.7x + 3 (for this line, the sum of squared residuals is 0.4)

    ### Why is this important? Summing squared residuals enables us to compare different models. The model with a smaller sum generally offers a better fit. Here, we see the line from part (b) fits better than the least-squares regression line.
Explanatory and Response Variables
Understanding these types of variables is crucial in regression analysis.

The explanatory variable is independent. It helps us understand or predict changes in another variable. In experiments, it's usually the factor we control. In our context, the x-values are explanatory.

The response variable is dependent. It's what we measure or focus on based on changes in the explanatory variable. In our exercise, y-values are the response.

To summarize:
  • Explanatory Variable (x): The variable that explains or causes changes. Example: Time spent studying.
  • Response Variable (y): The outcome we measure. Example: Test scores.
Understanding this distinction helps in setting up experiments, analyzing data, and interpreting results, as seen through our least-squares regression task.

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Most popular questions from this chapter

Use the linear correlation coefficient given to determine the coefficient of determination, \(R^{2} .\) Interpret each \(R^{2}\) (a) \(r=-0.32\) (b) \(r=0.13\) (c) \(r=0.40\) (d) \(r=0.93\)

Consider the following data set: $$ \begin{array}{lllllllll} \hline x & 5 & 6 & 7 & 7 & 8 & 8 & 8 & 8 \\\ \hline y & 4.2 & 5 & 5.2 & 5.9 & 6 & 6.2 & 6.1 & 6.9 \\ \hline x & 9 & 9 & 10 & 10 & 11 & 11 & 12 & 12 \\ \hline y & 7.2 & 8 & 8.3 & 7.4 & 8.4 & 7.8 & 8.5 & 9.5 \\ \hline \end{array} $$ (a) Draw a scatter diagram with the \(x\) -axis starting at 0 and ending at 30 and with the \(y\) -axis starting at 0 and ending at 20 . (b) Compute the linear correlation coefficient. (c) Now multiply both \(x\) and \(y\) by 2 . (d) Draw a scatter diagram of the new data with the \(x\) -axis starting at 0 and ending at 30 and with the \(y\) -axis starting at 0 and ending at 20. Compare the scatter diagrams. (e) Compute the linear correlation coefficient. (f) Conclude that multiplying each value in the data set by a nonzero constant does not affect the correlation between the variables.

American Black Bears The American black bear (Ursus americanus) is one of eight bear species in the world. It is the smallest North American bear and the most common bear species on the planet. In 1969 , Dr. Michael R. Pelton of the University of Tennessee initiated a long-term study of the population in the Great Smoky Mountains National Park. One aspect of the study was to develop a model that could be used to predict a bear's weight (since it is not practical to weigh bears in the field). One variable thought to be related to weight is the length of the bear. The following data represent the lengths and weights of 12 . American black bears. (a) Which variable is the explanatory variable based on the goals of the research? (b) Draw a scatter diagram of the data. (c) Determine the linear correlation coefficient between weight and length. (d) Does a linear relation exist between the weight of the bear and its length?

Professor Katula feels that there is a relation between the number of hours a statistics student studies each week and the student's age. She conducts a survey in which 26 statistics students are asked their age and the number of hours they study statistics each week. She obtains the following results: $$ \begin{array}{ll|ll|ll} \text { Age, } & \text { Hours } & \text { Age, } & \text { Hours } & \text { Age, } & \text { Hours } \\ \boldsymbol{x} & \text { Studying, } \boldsymbol{y} & \boldsymbol{x} & \text { Studying, } \boldsymbol{y} & \boldsymbol{x} & \text { Studying, } \boldsymbol{y} \\ \hline 18 & 4.2 & 19 & 5.1 & 22 & 2.1 \\ \hline 18 & 1.1 & 19 & 2.3 & 22 & 3.6 \\ \hline 18 & 4.6 & 20 & 1.7 & 24 & 5.4 \\ \hline 18 & 3.1 & 20 & 6.1 & 25 & 4.8 \\ \hline 18 & 5.3 & 20 & 3.2 & 25 & 3.9 \\ \hline 18 & 3.2 & 20 & 5.3 & 26 & 5.2 \\ \hline 19 & 2.8 & 21 & 2.5 & 26 & 4.2 \\ \hline 19 & 2.3 & 21 & 6.4 & 35 & 8.1 \\ \hline 19 & 3.2 & 21 & 4.2 & & \\ \hline \end{array} $$ (a) Draw a scatter diagram of the data. Comment on any potential influential observations. (b) Find the least-squares regression line using all the data points. (c) Find the least-squares regression line with the data point (35,8.1) removed. (d) Draw each least-squares regression line on the scatter diagram obtained in part (a). (e) Comment on the influence that the point (35,8.1) has on the regression line.

Explain the difference between correlation and causation. When is it appropriate to state that the correlation implies causation?

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