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True or False: The shape of the chi-square distribution depends on the degrees of freedom.

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Step by step solution

01

Understand the Chi-Square Distribution

The chi-square distribution is a continuous probability distribution that is widely used in statistical testing, especially for tests of independence and goodness of fit. It is defined for values greater than or equal to zero.
02

Define Degrees of Freedom

Degrees of freedom, often denoted as 'df', refer to the number of independent values or quantities that can vary in the analysis without breaking any constraints. In the context of a chi-square distribution, degrees of freedom typically correspond to the number of categories minus one.
03

Explain the Impact of Degrees of Freedom

The shape of the chi-square distribution varies depending on the degrees of freedom. With low degrees of freedom, the distribution is highly skewed to the right. As the degrees of freedom increase, the distribution becomes more symmetrical.
04

Determine the Statement's Validity

Given that the shape of the chi-square distribution changes with different degrees of freedom, this shows a clear dependency on the degrees of freedom.
05

Conclusion

Since the shape of the chi-square distribution does depend on the degrees of freedom, the statement given in the exercise is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of freedom (often abbreviated as df) are a key concept in statistics, referring to the number of independent values that can vary in an analysis without violating any constraints. Imagine you have a set of numbers, and the total sum of these numbers is fixed. Knowing all but one of these numbers means the last number isn't free to change if the total must be maintained. That last number would be an example of a degree of freedom.
In chi-square distribution, degrees of freedom are calculated typically as the number of categories minus one (df = k - 1). For instance, if you have 5 categories, the degrees of freedom would be 4. The calculation of degrees of freedom is crucial for determining the shape and behavior of the chi-square distribution.
A key takeaway is that the degrees of freedom impact the distribution's shape:
  • With low degrees of freedom, the chi-square distribution tends to be skewed to the right.
  • As degrees of freedom increase, it becomes more symmetrical and approaches a normal distribution.
Statistical Testing
Statistical testing involves using statistical methods to make inferences about a population based on sample data. The chi-square test is a popular method in this context, often used to test hypotheses about categorical data.
Two common types of chi-square tests are:
  • Chi-Square Test of Independence: This test helps to determine if there is a significant association between two categorical variables.
  • Chi-Square Goodness of Fit Test: This test checks how well the observed data fit an expected distribution.
Here's how it works in practice:
  • Start with a null hypothesis that states there is no association or fit.
  • Collect and organize your data in a contingency table.
  • Calculate the expected frequencies based on the hypothesis.
  • Compute the chi-square statistic using the formula: \[\text{chi-square} = \frac{ (O - E)^2 }{E} \] where \[\text{O}\] is the observed frequency and \[\text{E}\] is the expected frequency.
  • Compare the computed chi-square value against a critical value from the chi-square distribution table based on degrees of freedom and the chosen significance level (usually 0.05).
  • If the calculated chi-square is greater than the critical value, reject the null hypothesis.
Statistical testing using chi-square can provide insights into relationships in your data and the fit of your observations with an expected model.
Goodness of Fit
The Goodness of Fit test is a critical application of the chi-square distribution. This test assesses how well observed data match an expected distribution. For instance, you might use this test to determine if a die is fair by comparing the observed frequencies of rolled outcomes to the expected frequencies if the die were fair (which would be equal for all outcomes).
Here are the steps to perform a Goodness of Fit test:
  • Formulate the null hypothesis (H0), stating that there is no difference between observed and expected frequencies.
  • Calculate the expected frequencies based on either theoretical distribution or empirical data.
  • Use the chi-square statistic formula: \[\text{chi-square} = \frac{ (O - E)^2 }{E} \] to quantify the deviation of observed frequencies (O) from expected frequencies (E).
  • Determine the degrees of freedom as the number of categories minus one (df = k - 1).
  • Compare your chi-square statistic to the chi-square distribution table's critical value for your df and chosen significance level.
If your chi-square statistic exceeds the critical value, you reject the null hypothesis, indicating a poor fit between observed and expected data. Otherwise, you do not reject the null hypothesis, suggesting a good fit.
This test is vital in various fields, including genetics, quality control, and market research, helping analysts understand data distributions and their alignment with expected patterns.

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Most popular questions from this chapter

The National Highway Traffic Safety Administration publishes reports about motorcycle fatalities and helmet use. The distribution shows the proportion of fatalities by location of injury for motorcycle accidents. $$ \begin{array}{lccccc} \hline \begin{array}{l} \text { Location } \\ \text { of injury } \end{array} & \begin{array}{l} \text { Multiple } \\ \text { Locations } \end{array} & \text { Head } & \text { Neck } & \text { Thorax } & \begin{array}{l} \text { Abdomen/ } \\ \text { Lumbar/Spine } \end{array} \\ \hline \text { Proportion } & 0.57 & 0.31 & 0.03 & 0.06 & 0.03 \\ \hline \end{array} $$ The following data show the location of injury and number of fatalities for 2068 riders not wearing a helmet. $$ \begin{array}{lccccc} \hline \begin{array}{c} \text { Location } \\ \text { of injury } \end{array} & \begin{array}{l} \text { Multiple } \\ \text { Locations } \end{array} & \text { Head } & \text { Neck } & \text { Thorax } & \begin{array}{l} \text { Abdomen/ } \\ \text { Lumbar/Spine } \end{array} \\ \hline \text { Number } & 1036 & 864 & 38 & 83 & 47 \\ \hline \end{array} $$ (a) Does the distribution of fatal injuries for riders not wearing a helmet follow the distribution for all riders? Use the \(\alpha=0.05\) level of significance. (b) Compare the observed and expected counts for each category. What does this information tell you?

A researcher wanted to determine whether pedestrian deaths were uniformly distributed over the days of the week. She randomly selected 300 pedestrian deaths, recorded the day of the week on which the death occurred, and obtained the following results (the data are based on information obtained from the Insurance Institute for Highway Safety) $$ \begin{array}{lc|lc} \begin{array}{l} \text { Day of } \\ \text { the Week } \end{array} & \text { Frequency } & \begin{array}{l} \text { Day of } \\ \text { the Week } \end{array} & \text { Frequency } \\ \hline \text { Sunday } & 39 & \text { Thursday } & 41 \\ \hline \text { Monday } & 40 & \text { Friday } & 49 \\ \hline \text { Tuesday } & 30 & \text { Saturday } & 61 \\ \hline \text { Wednesday } & 40 & & \\ \hline \end{array} $$ Test the belief that the day of the week on which a fatality happens involving a pedestrian occurs with equal frequency at the \(\alpha=0.05\) level of significance.

Social Well-Being and Obesity The Gallup Organization conducted a survey in 2014 asking individuals questions pertaining to social well-being such as strength of relationship with spouse, partner, or closest friend, making time for trips or vacations, and having someone who encourages them to be healthy. Social well-being scores were determined based on answers to these questions and used to categorize individuals as thriving, struggling, or suffering in their social wellbeing. In addition, body mass index (BMI) was determined based on height and weight of the individual. This allowed for classification as obese, overweight, normal weight, or underweight. The data in the following contingency table are based on the results of this survey. $$ \begin{array}{lccc} & \text { Thriving } & \text { Struggling } & \text { Suffering } \\ \hline \text { Obese } & 202 & 250 & 102 \\ \hline \text { Overweight } & 294 & 302 & 110 \\ \hline \text { Normal Weight } & 300 & 295 & 103 \\ \hline \text { Underweight } & 17 & 17 & 8 \\ \hline \end{array} $$ (a) Researchers wanted to determine whether the sample data suggest there is an association between weight classification and social well-being. Explain why this data should be analyzed using a chi-square test for independence. (b) Do the sample data suggest that weight classification and social well- being are related? (c) Draw a conditional bar graph of the data by weight classification. (d) Write some general conclusions based on the results from parts (b) and (c).

Our number system consists of the digits \(0,1,2,3,4,5,6,7,8,\) and \(9 .\) The first significant digit in any number must be \(1,2,3,4,5,6,7,8,\) or 9 because we do not write numbers such as 12 as \(012 .\) Although we may think that each first digit appears with equal frequency so that each digit has a \(\frac{1}{9}\) probability of being the first significant digit, this is not true. In 1881 , Simon Newcomb discovered that first digits do not occur with equal frequency. This same result was discovered again in 1938 by physicist Frank Benford. After studying much data, he was able to assign probabilities of occurrence to the first digit in a number as shown. $$ \begin{array}{lccccc} \text { Digit } & 1 & 2 & 3 & 4 & 5 \\ \hline \text { Probability } & 0.301 & 0.176 & 0.125 & 0.097 & 0.079 \\ \hline \text { Digit } & 6 & 7 & 8 & 9 & \\ \hline \text { Probability } & 0.067 & 0.058 & 0.051 & 0.046 & \\ \hline \end{array} $$ The probability distribution is now known as Benford's Law and plays a major role in identifying fraudulent data on tax returns and accounting books. For example, the following distribution represents the first digits in 200 allegedly fraudulent checks written to a bogus company by an employee attempting to embezzle funds from his employer. $$ \begin{array}{lrrrrrrrrr} \hline \text { First digit } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \text { Frequency } & 36 & 32 & 28 & 26 & 23 & 17 & 15 & 16 & 7 \\ \hline \end{array} $$ (a) Because these data are meant to prove that someone is guilty of fraud, what would be an appropriate level of significance when performing a goodness- of-fit test? (b) Using the level of significance chosen in part (a), test whether the first digits in the allegedly fraudulent checks obey Benford's Law. (c) Based on the results of part (b), do you think that the employee is guilty of embezzlement?

Determine the expected counts for each outcome. $$ \begin{array}{lllll} \hline \boldsymbol{n}=\mathbf{5 0 0} & & & & \\ \hline p_{i} & 0.2 & 0.1 & 0.45 & 0.25 \\ \hline \text { Expected counts } & & & & \\ \hline \end{array} $$

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