/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Sugary Beverages It has been rep... [FREE SOLUTION] | 91Ó°ÊÓ

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Sugary Beverages It has been reported that consumption of sodas and other sugar-sweetened beverages cause excessive weight gain. Researchers conducted a randomized study in which 224 overweight and obese adolescents who regularly consumed sugar-sweetened beverages were randomly assigned to experimental and control groups. The experimental groups received a one-year intervention designed to decrease consumption of sugar-sweetened beverages, with follow-up for an additional year without intervention. The response variable in the study was body mass index (BMI-the weight in kilograms divided by the square of the height in meters). Results of the study appear in the following table. Source: Cara B. Ebbeling, \(\mathrm{PhD}\) and associates, "A Randomized Trial of Sugar-Sweetened Beverages and Adolescent Body Weight" N Engl J Med 2012;367:1407-16. DOI: 10.1056/NEJMoal2Q3388 $$ \begin{array}{lll} & \text { Experimental } & \text { Control } \\ & \text { Group } & \text { Group } \\ & (n=110) & (n=114) \\ \hline \text { Start of Study } & \text { Mean BMI }=30.4 & \text { Mean BMI }=30.1 \\ & \text { Standard Deviation } & \text { Standard Deviation } \\ & \mathrm{BMI}=5.2 & \mathrm{BMI}=4.7 \\ \hline \text { After One Year } & \text { Mean Change in } & \text { Mean Change in } \\ & \mathrm{BMI}=0.06 & \mathrm{BMI}=0.63 \\ & \text { Standard Deviation } & \text { Standard Deviation } \\ & \text { Change in } & \text { Change in } \\ & \mathrm{BMI}=0.20 & \mathrm{BMI}=0.20 \\ \hline \text { After Two Years } & \text { Mean Change in } & \text { Mean Change in } \\ & \mathrm{BMI}=0.71 & \mathrm{BMI}=1.00 \\ & \text { Standard Deviation } & \text { Standard Deviation } \\ & \text { Change in } & \text { Change in } \\ & \mathrm{BMI}=0.28 & \mathrm{BMI}=0.28 \end{array} $$ (a) What type of experimental design is this? (b) What is the response variable? What is the explanatory variable? (c) One aspect of statistical studies is to verify that the subjects in the various treatment groups are similar. Does the sample evidence support the belief that the BMIs of the subjects in the experimental group is not different from the BMIs in the control group at the start of the study? Use an \(\alpha=0.05\) level of significance. (d) One goal of the research was to determine if the change in BMI for the experimental group was less than that for the control group after one year. Conduct the appropriate test to see if the evidence suggests this goal was met. Use an \(\alpha=0.05\) level of significance. What does this result suggest? (e) Does the sample evidence suggest the change in BMI is less for the experimental group than the control group after two years? Use an \(\alpha=0.05\) level of significance. What does this result suggest? (f) To what population do the results of this study apply?

Short Answer

Expert verified
The study is a randomized control trial, BMI is the response variable, the type of intervention is the explanatory variable. The initial BMIs do not significantly differ. After one year, the experimental group BMI change is significantly less. After two years, the changes are not significantly different.

Step by step solution

01

Identify Experimental Design

Determine the type of experimental design based on the description of the study. This is a randomized control trial where participants were randomly assigned to one of two groups to compare their outcomes over time.
02

Identify Variables

Determine the response variable and the explanatory variable. The response variable is the BMI (body mass index), which is being measured. The explanatory variable is the type of intervention, specifically whether participants were in the experimental group or control group.
03

Compare Baseline BMIs

Check if there is a significant difference in BMI between the experimental and control groups at the start using a two-sample t-test. This can be checked using the following formulas:
04

Compute t-Statistic

Using the formulas:
05

Test Statistic Calculation

To test if the mean change in BMI for the experimental group is significantly less than the control group after one year, use the following t-test:
06

One-Year Comparison Conclusion

Based on the p-value obtained from the previous step, determine if the evidence suggests that the change in BMI for the experimental group is less than that of the control group at the 0.05 level of significance.
07

Two-Year Comparison

Conduct a similar t-test to evaluate the change in BMI after two years.
08

Identify Population Applicability

Identify who the results of this study apply to, based on the initial population and sampling method used in the study.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

experimental design
This study uses a **randomized controlled trial** (RCT). Here, researchers randomly assigned 224 overweight adolescents to experimental and control groups. Random assignment helps prevent bias, ensuring that any differences in outcomes between groups are due to the intervention rather than pre-existing differences. The experimental group received an intervention to reduce sugary beverage intake, while the control group received no such intervention.
response variable
In this study, the response variable is **Body Mass Index (BMI)**. BMI is calculated by dividing a person's weight in kilograms by their height in meters squared \( \text{BMI} = \frac{\text{weight (kg)}}{\text{height (m)}^2} \). It is measured at different points to assess the impact of the intervention. Changes in BMI indicate whether there is a weight gain or loss.
explanatory variable
The explanatory variable is the type of intervention received. Specifically, whether participants are in the **experimental group** (who received the intervention to reduce sugary beverage consumption) or in the **control group** (who did not receive any intervention). This variable explains the change in BMI observed.
t-test
The **t-test** helps determine if there are significant differences between the experimental and control groups. For example, to check if there's a difference in BMI at the start, we use a two-sample t-test: \text{t} = \frac{\bar{X1} - \bar{X2}}{s_p\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}} \. Here, \( \bar{X1} \) and \( \bar{X2} \) are the sample means of the two groups, \( n_1 \) and \( n_2 \) are the sample sizes, and \( s_p \) is the pooled standard deviation.
BMI comparison
To compare BMI changes, we look at means and standard deviations over time. Initially, the experimental group had a mean BMI of 30.4, while the control group had 30.1. After one year, changes in BMI were 0.06 (experimental) and 0.63 (control). Finally, after two years, BMI changes were 0.71 (experimental) and 1.00 (control). These comparisons help assess the effectiveness of the intervention.
statistical significance
Statistical significance tells us if the results are likely due to the intervention rather than random chance. We use an **alpha level (\( \alpha \)) of 0.05**. If the p-value from the t-test is less than 0.05, the result is considered statistically significant. For example, after one year, if the p-value is low, we conclude that the intervention had a significant effect on reducing BMI compared to the control group.

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Most popular questions from this chapter

\( \begin{array}{ccccccccc} \text { Observation } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} & \mathbf{6} & \mathbf{7} & \mathbf{8} \\ \hline X_{i} & 19.4 & 18.3 & 22.1 & 20.7 & 19.2 & 11.8 & 20.1 & 18.6 \\ \hline Y_{i} & 19.8 & 16.8 & 21.1 & 22.0 & 21.5 & 18.7 & 15.0 & 23.9 \end{array} \) (a) Determine \(d_{i}=X_{i}-Y_{i}\) for each pair of data. (b) Compute \(\bar{d}\) and \(s_{d}\) (c) Test if \(\mu_{d} \neq 0\) at the \(\alpha=0.01\) level of significance. (d) Compute a \(99 \%\) confidence interval about the population mean difference \(\mu_{d}\).

College Skills The Collegiate Learning Assessment Plus (CLA+) is an exam that is meant to assess the intellectual gains made between one's freshman and senior year of college. The exam, graded on a scale of 400 to 1600 , assesses critical thinking, analytical reasoning, document literacy, writing, and communication. The exam was administered to 135 freshman in Fall 2012 at California State University Long Beach (CSULB). The mean score on the exam was 1191 with a standard deviation of 187 . The exam was also administered to graduating seniors of CSULB in Spring 2013. The mean score was 1252 with a standard deviation of \(182 .\) Explain the type of analysis that could be applied to these data to assess whether CLA+ scores increase while at CSULB. Explain the shortcomings in the data available and provide a better data collection technique.

In Problems 9–12, conduct each test at the a = 0.05 level of significance by determining (a) the null and alternative hypotheses, (b) the test statistic, (c) the critical value, and (d) the P-value. Assume that the samples were obtained independently using simple random sampling. Test whether \(p_{1}>p_{2}\). Sample data: \(x_{1}=368, n_{1}=541\), \(x_{2}=351, n_{2}=593\)

Perform the appropriate hypothesis test. If \(n_{1}=61, s_{1}=18.3, n_{2}=57,\) and \(s_{2}=13.5,\) test whether the population standard deviations differ at the \(\alpha=0.05\) level of significance.

In Problems 13-16, construct a confidence interval for \(p_{1}-p_{2}\) at the given level of confidence. \(x_{1}=368, n_{1}=541, x_{2}=421, n_{2}=593,90 \%\) confidence

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