/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 In April 2009 , the Gallup organ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In April 2009 , the Gallup organization surveyed 676 adults aged 18 and older and found that 352 believed they would not have enough money to live comfortably in retirement. The folks at Gallup want to know if this represents sufficient evidence to conclude a majority (more than \(50 \%\) ) of adults in the United States believe they will not have enough money in retirement. (a) What does it mean to make a Type II error for this test? (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, determine the probability of making a Type II error if the true population proportion is 0.53. What is the power of the test? (c) Redo part (b) if the true proportion is 0.55 .

Short Answer

Expert verified
Type II error is concluding 50% or fewer believe they won’t have enough for retirement when more than 50% do. For true proportion 0.53, Type II error probability is 0.3085 and power is 69.15%. For 0.55, Type II error probability is 0.0606 and power is 93.94%.

Step by step solution

01

- Define the Hypotheses

Define the null and alternative hypotheses.The null hypothesis ($$H_0$$) is that the proportion of adults who believe they will not have enough money for retirement is $$0.50$$.The alternative hypothesis ($$H_1$$) is that the proportion of adults who believe this is greater than $$0.50$$.
02

- Understanding Type II Error

Identify what a Type II error means in this context.A Type II error occurs when the test fails to reject the null hypothesis despite the alternative hypothesis being true. In this case, it means we incorrectly conclude that $$50 \text{ % }$$ or fewer adults believe they will not have enough money for retirement when, in fact, the proportion is greater than $$50 \text{ % }$$.
03

- Calculating the Test Statistic

Calculate the test statistic for the hypothesis test.The test statistic for a proportion can be found using$$z = \frac{\bar{p} - p_0}{\frac{\text{Std}}{\text{n}}}$$, where $$\bar{p}$$ is the sample proportion, $$p_0$$ is the hypothesized population proportion, $$ \text{Std} $$ is the standard deviation, and $$n$$ is the sample size.
04

- Find Sample Proportion

Calculate the sample proportion $$\bar{p}$$.The sample proportion $$\bar{p}$$ of adults who believe they won’t have enough money in retirement is $$\bar{p} = \frac{352}{676} = 0.52$$.
05

- Determine Critical Value

Determine the critical value for the test at $$\text{α} = 0.05$$ level of significance.Since this is a one-tailed test, find z critical value from standard normal distribution corresponding to an area of $$0.95$$ to find $$z_\text{critical} = 1.645$$.
06

- Calculate Standard Deviation

Compute the standard deviation using $$\bar{p}$$ and $$p_0$$. $$\text{Std} = \text{ $$\text{sqrt}\big(\frac{p_0(1-p_0)}{n}\big) = \text{ $$\text{sqrt}\big(\frac{0.50(1-0.50)}{676}\big) = 0.019$$
07

- Calculate z-statistic

Find the z-statistic using the formula. $$z = \frac{0.52 - 0.50}{0.019} = 1.05$$.
08

- Type II Error Calculation For True Proportion 0.53

Calculate Type II error with true population proportion $$p = 0.53$$.The z-value for $$0.53$$ with standard deviation $$0.019$$ would be $$z_β = \frac{0.50 + 1.645(0.019) - 0.53}{0.019} = -0.50$$.From z-table: $$P(Z < -0.50) = 0.3085$$. Hence, Type II error probability β = $$0.3085$$.
09

- Calculate Power of Test For True Proportion 0.53

Determine power of the test by subtracting the Type II error probability from 1. $$\text{Power} = 1 - \beta = 1 - 0.3085 = 0.6915 = 69.15 \text{ % }$$.
10

- Repeat Calculation For True Proportion 0.55

Recalculate Type II error and power of test for true proportion $$p = 0.55$$.New z-value is $$z_β = \frac{0.50 + 1.645(0.019) - 0.55}{0.019} = -1.55$$.From z-table: $$P(Z < -1.55) = 0.0606$$. So, Type II error probability $$\beta = 0.0606$$.Power is $$\text{Power} = 1 - \beta = 1 - 0.0606 = 0.9394 = 93.94 \text{ % }$$.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hypothesis testing
Hypothesis testing is a fundamental concept in statistics used to make inferences about a population based on sample data. In our given problem, we formulate two hypotheses: the null hypothesis \((H_0)\) and the alternative hypothesis \((H_1)\). The null hypothesis typically represents a statement of no effect or no difference. Here, \((H_0)\) states that the proportion of adults who believe they will not have enough money for retirement is 50%.
\((H_1)\) suggests that this proportion is actually greater than 50%.
By examining sample data, we can determine whether there's enough evidence to reject \((H_0)\) in favor of \((H_1)\). This process involves several steps, including calculating the test statistic and comparing it against a threshold value.
  • The threshold value, also known as the critical value, is determined by the chosen significance level.
  • In this case, the significance level is \((\alpha = 0.05)\).
  • The test statistic tells us how far our sample proportion is from the hypothesized population proportion, measured in terms of the standard error
.
Type II error
A Type II error occurs when we fail to reject the null hypothesis when it is false. In the context of our problem, this means we wrongly conclude that 50% or fewer adults believe they will not have enough money for retirement when the actual proportion is greater.
This type of error signifies a missed opportunity to identify a true effect or difference. The probability of committing a Type II error is denoted as \((\beta)\).
  • For instance, if the true population proportion is 0.53, and our calculations show \((\beta = 0.3085)\), it implies a 30.85% chance of making a Type II error under these specific conditions.
  • This error can lead to incorrect conclusions and potentially affect decisions based on the hypothesis test results.
.
statistical power
Statistical power is the probability of correctly rejecting the null hypothesis when it is false. It represents the test's ability to detect an actual effect or difference. Power is calculated as \((1 - \beta)\). Using our example where \((\beta = 0.3085)\), the power of the test would be \((1 - 0.3085 = 0.6915)\) or 69.15%.
Higher power indicates a better chance of detecting a true effect. In hypothesis testing, achieving high power is essential, and this depends on:
  • Sample size: Larger samples give more reliable results.
  • Effect size: Larger differences are easier to detect.
  • Significance level: Lower significance levels require stronger evidence but can reduce power.
test statistic calculation
The calculation of the test statistic is a key step in hypothesis testing. The test statistic measures the degree to which the sample proportion deviates from the hypothesized population proportion, expressed in standard error units. The formula for the test statistic (z) for a proportion is:
\[ z = \frac{\bar{p} - p_0}{\frac{\text{Std}}{\text{n}}} \]
Where:
  • \( \bar{p} \) = Sample proportion
  • \( p_0 \) = Hypothesized population proportion
  • Standard deviation = \( \sqrt{ \frac{p_0 (1-p_0)}{n} } \)
  • n = Sample size
In our example, the sample proportion \(\bar{p} = \frac{352}{676} = 0.52 \), while \(p_0 = 0.50 \) and \(\text{Std} = 0.019\). Plug these values into the formula to get the z-statistic: \( z = \frac{0.52 - 0.50}{0.019} = 1.05 \).
significance level
The significance level, denoted as \(\alpha\), represents the probability of making a Type I error, which occurs when we reject the null hypothesis when it is true. In practice, common choices for significance level are 0.05 or 0.01, indicating a 5% or 1% risk of committing a Type I error, respectively.
For our hypothesis test, we choose \(\alpha = 0.05\), meaning we are willing to accept a 5% chance of incorrectly rejecting the null hypothesis. The significance level also determines the critical value, which we compare against our test statistic.
For a one-tailed test with \(\alpha = 0.05\), the critical value from the standard normal distribution is 1.645. If our test statistic exceeds this value, we reject the null hypothesis. Otherwise, we fail to reject it.
  • The choice of \(\alpha\) impacts the balance between Type I and Type II errors.
  • Lower \(\alpha\) reduces Type I error risk but increases Type II error risk.
  • Higher \(\alpha\) does the opposite.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Decide whether the problem requires a confidence interval or hypothesis test, and determine the variable of interest. For any problem requiring a confidence interval, state whether the confidence interval will be for a population proportion or population mean. For any problem requiring a hypothesis test, write the null and alternative hypothesis. According to the Pew Research Center, \(55 \%\) of adult Americans support the death penalty for those convicted of murder. A social scientist wondered whether a higher proportion of adult Americans with at least a bachelor's degree support the death penalty for those convicted of murder.

Simulate drawing 100 simple random samples of size \(n=40\) from a population whose proportion is 0.3 (a) Test the null hypothesis \(H_{0}: p=0.3\) versus \(H_{1}: p \neq 0.3\) for each simulated sample. (b) If we test the hypothesis at the \(\alpha=0.1\) level of significance, how many of the 100 samples would you expect to result in a Type I error? (c) Count the number of samples that lead to a rejection of the null hypothesis. Is it close to the expected value determined in part (b)? (d) How do we know that a rejection of the null hypothesis results in making a Type I error in this situation?

To test \(H_{0}: \sigma=4.3\) versus \(H_{1}: \sigma \neq 4.3,\) a random sample of size \(n=12\) is obtained from a population that is known to be normally distributed. (a) If the sample standard deviation is determined to be \(s=4.8\), compute the test statistic. (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, determine the critical values. (c) Draw a chi-square distribution and depict the critical regions. (d) Will the researcher reject the null hypothesis? Why?

In Problems \(9-14,\) the null and alternative hypotheses are given. Determine whether the hypothesis test is lefi-tailed, right-tailed, or two-tailed. What parameter is being tested? \(H_{0}: p=0.76\) \(H_{1}: p>0.76\)

The headline reporting the results of a poll conducted by the Gallup organization stated "Majority of Americans at Personal Best in the Morning." The results indicated that a survey of 1100 Americans resulted in \(55 \%\) stating they were at their personal best in the morning. The poll's results were reported with a margin of error of \(3 \% .\) Explain why the Gallup organization's headline is accurate.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.