91影视

$$\begin{gathered} H_0:{尾}_1={尾}_2={尾}_3={尾}_4=0 \\ {H}_a:Atleastoneoftheparameters{尾}_1,{尾}_2,{尾}_3,and{尾}_{4}isnonzero \end{gathered}$$

Here, F test statistic =$\frac{\mathrm{SSE}}{\mathrm{n}-(\mathrm{k}+1)}=\frac{0.41}{25-5}=0.0205$

Value of F_0.05,25,25 is 1.964

${\mathrm{H}}_0\mathrm{is}\mathrm{rejected}\mathrm{if}\mathrm{F}\mathrm{statistic}>{\mathrm{F}}_{0.05,28,28}.\mathrm{For}\mathrm{伪}=0.05,\mathrm{since}\mathrm{F}<{\mathrm{F}}_{0.05,28,28}$role="math" localid="1652120400407" $\mathrm{Not}\mathrm{sufficient}\mathrm{evidence}\mathrm{to}\mathrm{rejec}{\mathrm{H}}_{\mathrm{o}}\mathrm{at}95\mathrm{\%}\mathrm{confidence}\mathrm{interval}.$

$\mathrm{Therefore},{\mathrm{尾}}_1={\mathrm{尾}}_2={\mathrm{尾}}_3={\mathrm{尾}}_4=0.$

$$\begin{gathered} {\mathrm{H}}_0:{\mathrm{尾}}_1=0 \\ {\mathrm{H}}_{\mathrm{a}}:{\mathrm{尾}}_1<0 \end{gathered}$$

Here, t-test statistic =$\frac{\widehat{{尾}_1}}{2\widehat{{尾}_1}}=\frac{-2.43}{1.21}=-2.008$

Value oft_0.05,25 is 1.708

$$\begin{gathered} {\text{H}}_{0}isrejectedift\mathrm{statistic}>t_{0.05,25}.\mathrm{For}\mathrm{伪}=0.05,\mathrm{since}t<t_{0.05,25.} \\ Notsufficientevidencetoreject{H}_{o}at95\%confidenceinterval. \\ Therefore,{尾}_1=0 \end{gathered}$$

$$\begin{gathered} H_0:{尾}_2=0 \\ {H}_a:{尾}_2>0 \end{gathered}$$

Here, t-test statistic =$\frac{\widehat{{尾}_2}}{2\widehat{{尾}_2}}=\frac{0.05}{0.16}=0.3125$

Value oft_0.05,25 is 1.708

$$\begin{gathered} {\mathrm{H}}_0\mathrm{is}\mathrm{rejected}\mathrm{if}t\mathrm{statistic}>t_{0.05,25}.\mathrm{For}\mathrm{伪}=0.05,\mathrm{since}t<t_{0.05,31}. \\ \mathrm{Not}\mathrm{sufficient}\mathrm{evidence}\mathrm{to}\mathrm{reject}{\mathrm{H}}_{\mathrm{o}}\mathrm{at}95\mathrm{\%}\mathrm{confidence}\mathrm{interval}. \\ \mathrm{Therefore},{\mathrm{尾}}_2=0. \end{gathered}$$

$$\begin{gathered} H_0:{尾}_3=0 \\ {H}_a:{尾}_3鈮�0 \end{gathered}$$

Here, t-test statistic = $\frac{\widehat{{尾}_3}}{s{\widehat{尾}}_3}=\frac{0.62}{0.26}=2.38461$

Value oft_0.025,25 is 2.060

$$\begin{gathered} H_{0}isrejectediftstatistic>t_{0.05,24,24}.For伪=0.05,sincet>t_{0.05,31}. \\ \mathrm{Sufficient}\mathrm{evidence}\mathrm{to}\mathrm{reject}{\mathrm{H}}_{\mathrm{o}}\mathrm{at}95\mathrm{\%}\mathrm{confidence}\mathrm{interval}. \\ \mathrm{Therefore},{\mathrm{尾}}_3鈮�0. \end{gathered}$$