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Is honey a cough remedy?Refer to the Archives of Pediatrics and Adolescent Medicine(December 2007) study of honeyas a remedy for coughing, Exercise 2.31 (p. 86). The coughingimprovement scores (as determined by the children鈥檚 parents)for the patients in the over-the-counter cough medicinedosage (DM) group, honey dosage group, and control groupare reproduced in the accompanying table.

Honey Dosage

12, 11, 15, 11, 10, 13, 10, 4 ,15, 16, 9, 14, 10, 6, 10, 8, 11, 12, 12, 8, 12, 9, 11, 15, 10, 15, 9, 13, 8, 12, 10, 8, 9, 5, 12

DM Dosage

4, 6, 9, 4, 7, 7, 7, 9, 12 ,10, 11, 6, 3, 4, 9, 12, 7, 6, 8, 12, 12, 4, 12, 13, 7, 10

No Dosage
(Control)

13, 9, 4, 4, 10, 15, 9, 5, 8, 6, 1, 0, 8, 12, 8, 7, 7, 1, 6, 7, 7, 12, 7, 9, 7, 9, 5, 11, 9, 5, 6, 8, 8, 6, 7, 10, 9, 4, 8, 7, 3, 1, 4, 3

a.Find the standard deviation of the improvement scores for the honey dosage group.

b.Find the standard deviation of the improvement scores for the DM dosage group.

c.Find the standard deviation of the improvement scores for the control group.

d.Based on the results, parts a鈥揷, which group appears to have the most variability in coughing improvement scores? The least variability?

Short Answer

Expert verified

a. Standard Deviation = 2.85

b. Standard Deviation = 3.037

c. Standard Deviation = 2.976

d. Most Variable = DM dosage group

Least Variable = Honey dosage group

Step by step solution

01

Finding the standard deviation for honey dosage group

Mean=SumofallscoresNo.ofscores=12+11+15+11+10+13+10+4+15+16+9+14+10+6+10+8+11+12+12+8+12+9+11+15+10+15+9+13+8+12+10+8+9+5+1235=37535=10.71

x

(x-x)

(x-x)2

12

1.29

1.66

11

0.29

0.08

15

4.29

18.40

11

0.29

0.08

10

-0.71

0.50

13

2.29

5.24

10

-0.71

0.50

4

-6.71

45.02

15

4.29

18.40

16

5.29

27.98

9

-1.71

2.92

14

3.29

10.82

10

-0.71

0.50

6

-4.71

22.18

10

-0.71

0.50

8

-2.71

7.34

11

0.29

0.08

12

1.29

1.66

12

1.29

1.66

8

-2.71

7.34

12

1.29

1.66

9

-1.71

2.92

11

0.29

0.08

15

4.29

18.40

10

-0.71

0.50

15

4.29

18.40

9

-1.71

2.92

13

2.29

5.24

8

-2.71

7.34

12

1.29

1.66

10

-0.71

0.50

8

-2.71

7.34

9

-1.71

2.92

5

-5.71

32.60

12

1.29

1.66

Sum

0

277.14

Variance=(x-x)2n-1=277.1435-1=277.1434=8.15StandardDeviation=Variance=8.15=2.85

Therefore, Standard deviation for honey dosage group is 2.85.

02

Calculating the standard deviation for DM dosage group

Mean=SumofallscoresNo.ofscores=4+6+9+4+7+7+7+9+12+10+11+6+3+4+9+12+7+6+8+12+12+4+12+13+7+1026=21126=8.115

x

(x-x)

(x-x)2

4

-4.115

16.93

6

-2.115

4.47

9

0.885

0.78

4

-4.115

16.93

7

-1.115

1.24

7

-1.115

1.24

7

-1.115

1.24

9

0.885

0.78

12

3.885

15.09

10

1.885

3.55

11

2.885

8.32

6

-2.115

4.47

3

-5.115

26.16

4

-4.115

16.93

9

0.885

0.78

12

3.885

15.09

7

-1.115

1.24

6

-2.115

4.47

8

-0.115

0.01

12

3.885

15.09

12

3.885

15.09

4

-4.115

16.93

12

3.885

15.09

13

4.885

23.86

7

-1.115

1.24

10

1.885

3.55

Sum

0

230.65

Variance=(x-x)2n-1=230.6526-1=230.6525=9.226StandardDeviation=Variance=9.226=3.037

Therefore, Standard deviation for DM dosage group is 3.03.

03

Finding the standard deviation for honey dosage group

Mean=SumofallscoresNo.ofscores=5+8+6+1+0+8+12+8+7+7+1+6+7+7+12+7+9+5+6+8+8+6+7+10+9+4+8+7+3+1+4+8+7+3+1+4+337=22337=6.027

x

(x-x)

(x-x)2

5

-1.027

1.05

8

1.973

3.89

6

-0.027

0.0007

1

-5.027

25.27

0

-6.027

36.32

8

1.973

3.89

12

5.973

35.67

8

1.973

3.89

7

0.973

0.94

7

0.973

0.94

1

-5.027

25.27

6

-0.027

0.0007

7

0.973

0.94

7

0.973

0.94

12

5.973

35.67

7

0.973

0.94

9

2.973

8.83

5

-1.027

1.05

6

-0.027

0.0007

8

1.973

3.89

8

1.973

3.89

6

-0.027

0.0007

7

0.973

0.94

10

3.973

15.78

9

2.973

8.83

4

-2.027

4.11

8

1.973

3.89

7

0.973

0.94

3

-3.027

9.16

1

-5.027

25.27

4

-2.027

4.11

8

1.973

3.89

7

0.973

0.94

3

-3.027

9.16

1

-5.027

25.27

4

-2.027

4.11

3

-3.027

9.16

Sum

0

318.973

Variance=(x-x)2n-1=318.97337-1=318.97336=8.86StandardDeviation=Variance=8.86=2.976

Therefore, Standard deviation for control group is 2.976.

04

Identifying the least and the most variable group

The most variable group is the DM dosage group as it has the highest standard deviation out of the 3.

The least variable group is the honey dosage group with the lowest standard deviation value.

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Most popular questions from this chapter

Explain why we generally prefer the standard deviation to the range as a measure of variability for quantitative data.

Calculate the range, variance, and standard deviation for the following samples:

a.4, 2, 1, 0, 1

b.1, 6, 2, 2, 3, 0, 3

c.8, -2, 1, 3, 5, 4, 4, 1, 3, 3

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Complete the following table on customer statistics.

Age of customer

Frequency

Relative Frequency

15 or younger

36

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16 to 25

96

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25 to 35

48

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36 to 50

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Total

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1.00

Is honey a cough remedy?Refer to the Archives of Pediatrics and Adolescent Medicine(Dec. 2007) studyof honey as a remedy for coughing, Exercise 2.31 (p. 86). Recall that the 105 ill children in the sample wererandomly divided into three groups: those who receiveda dosage of over-the-counter cough medicine (DM),those who received a dosage of honey (H), and thosewho received no dosage (control group). The coughingimprovement scores (as determined by the children鈥檚parents) for the patients are reproduced in the nexttable.

Honey Dosage

12, 11, 15, 11, 10, 13, 10, 4 ,15, 16, 9, 14, 10, 6, 10, 8, 11, 12, 12, 8, 12, 9, 11, 15, 10, 15, 9, 13, 8, 12, 10, 8, 9, 5, 12

DM Dosage

4, 6, 9, 4, 7, 7, 7, 9, 12 ,10, 11, 6, 3, 4, 9, 12, 7, 6, 8, 12, 12, 4, 12, 13, 7, 10

No Dosage
(Control)

13, 9, 4, 4, 10, 15, 9, 5, 8, 6, 1, 0, 8, 12, 8, 7, 7, 1, 6, 7, 7, 12, 7, 9, 7, 9, 5, 11, 9, 5, 6, 8, 8, 6, 7, 10, 9, 4, 8, 7, 3, 1, 4, 3

a) Find the median improvement score for the honey dosage group.

b) Find the median improvement score for the DM dosage group.

c) Find the median improvement score for the control group.

d) Based on the results, parts a鈥揷, what conclusions can pediatric researchers draw? (We show how to support these conclusions with a measure of reliability in subsequent chapters.)

Crash tests on new cars.The National Highway Traffic Safety Administration (NHTSA) crash-tests new car models to determine how well they protect the driver and front-seat passenger in a head-on collision. The NHTSA has developed a 鈥渟tar鈥 scoring system for the frontal crash test, with results ranging from one star (*) to five stars (). The more stars in the rating, the better the level of crash protection in a head-on collision. The NHTSA crashtest results for 98 cars (in a recent model year) are stored in the accompanying data file.

a. The driver-side star ratings for the 98 cars are summarized in the Minitab printout shown below. Use the information in the printout to form a pie chart. Interpret the graph.

Tally for Discrete Variables: DRIVSTAR

DRIVSTAR

Count

Percent

2

3

4

5

N =

4

17

59

18

98

4.08

17.35

60.20

18.37


b. One quantitative variable recorded by the NHTSA is the driver鈥檚 severity of head injury (measured on a scale from 0 to 1,500). The mean and standard deviation for the 98 driver head-injury ratings are displayed in the Minitab printout below. Give a practical interpretation of the mean.
Descriptive Statistics: DRIVHEAD

Variable

N

Mean

StDev

Minimum

Q1

Median

Q3

Maximum

DRIVHEAD

98

603.7

185.4

216.0

475.0

605.0

724.3

1240.0

C. Use the mean and standard deviation to make a statement about where most of the head-injury ratings fall.

d..Find the z-score for a driver head-injury rating of 408. Interpret the result.

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