91影视

Range = 4 鈥� 0 = 4

$\begin{array}{c}\text{Mean}\left(\stackrel{-}{蠂}\right)\text{=}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{N}}\\ \text{=}\frac{\text{4+2+1+0+1}}{\text{5}}\\ \text{=}\frac{\text{8}}{\text{5}}\\ \text{=1.6}\\ 蠂\text{=1.6}\end{array}$

$\begin{array}{c}\text{Mean}\left(\stackrel{-}{蠂}\right)\text{=}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{N}}\\ \text{=}\frac{\text{4+2+1+0+1}}{\text{5}}\\ \text{=}\frac{\text{8}}{\text{5}}\\ \text{=1.6}\end{array}$

$\stackrel{-}{蠂}\text{=1.6}$

$\begin{array}{c}\text{Variance=}\frac{{\displaystyle 鈭�\text{(蠂}鈭�\stackrel{-}{蠂}{\text{)}}^{\text{2}}}}{\text{N}鈭�\text{1}}\\ \text{=}\frac{\text{9.2}}{\text{5}鈭�\text{1}}\\ \text{=}\frac{\text{9.2}}{\text{4}}\\ \text{=2.3}\end{array}$

Therefore, the variance is 2.3

$\begin{array}{c}\text{Standarddeviation=}\sqrt{\text{Variance}}\\ \text{=}\sqrt{\text{2.3}}\\ \text{=1.52}\end{array}$

Therefore, the standard deviation is 1.52.

Range = 6 鈥� 0 = 6

localid="1651305337400" $\begin{array}{c}\text{Mean}\left(\stackrel{-}{蠂}\right)\text{=}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{N}}\\ =\frac{1+6+2+2+3+0+3}{7}\\ =\frac{17}{7}\\ =2.43\end{array}$

localid="1651305447844" $\stackrel{-}{蠂}\text{=2.43}$

localid="1651305675002" $\begin{array}{c}\text{Variance=}\frac{{\displaystyle 鈭�\text{(蠂}鈭�\stackrel{-}{蠂}{\text{)}}^{\text{2}}}}{\text{N}鈭�\text{1}}\\ \text{=}\frac{\text{21.7143}}{\text{7}鈭�\text{1}}\\ \text{=}\frac{\text{21.7143}}{\text{6}}\\ \text{=3.619}\end{array}$

Therefore, the variance is 3.619.

$\begin{array}{c}\text{Standarddeviation=}\sqrt{\text{Variance}}\\ \text{=}\sqrt{\text{3.619}}\\ \text{=1.90}\end{array}$

Therefore, the standard deviation is 1.90.

Range = 8 鈥� (-2) = 10

$\begin{array}{c}\text{Mean}\left(\stackrel{-}{蠂}\right)\text{=}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{N}}\\ \text{=}\frac{\text{8+}(鈭�\text{2})\text{+1+3+5+4+4+1+3+3}}{\text{10}}\\ \text{=}\frac{\text{30}}{\text{10}}\\ \text{=3}\end{array}$

$\stackrel{-}{蠂}=3$

$\begin{array}{c}\text{Variance=}\frac{{\displaystyle 鈭�{\text{(蠂}鈭�\stackrel{-}{蠂})}^{\text{2}}}}{\text{N}鈭�\text{1}}\\ \text{=}\frac{\text{64}}{\text{10}鈭�\text{1}}\\ \text{=}\frac{\text{64}}{\text{9}}\\ \text{=7.11}\end{array}$

Therefore, the variance is 7.11.

$\begin{array}{c}\text{Standarddeviation=}\sqrt{\text{Variance}}\\ \text{=}\sqrt{\text{7.11}}\\ \text{=2.66}\end{array}$

Therefore, the standard deviation is 2.66.

Range = 2 鈥� (-3) = 5

$$\begin{gathered} \text{Mean}\left(\stackrel{-}{蠂}\right)\text{=}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{N}} \\ \text{=}\frac{\text{0+2+0+0+}(鈭�\text{1})\text{+1+}(鈭�\text{2})\text{+1+0+}(鈭�\text{1})\text{+1+}(鈭�\text{1})\text{+0+}(鈭�\text{3})\text{+}(鈭�\text{2})\text{+}(鈭�\text{1})\text{+0+1}}{\text{18}} \\ \text{=}\frac{鈭�\text{5}}{\text{18}} \\ \text{=}鈭�\text{0.27} \end{gathered}$$

$\stackrel{-}{蠂}=鈭�\text{0.27}$

$$\begin{gathered} \text{Variance=}\frac{{\displaystyle 鈭�\text{(蠂}鈭�\stackrel{-}{蠂}{\text{)}}^{\text{2}}}}{\text{N}鈭�\text{1}} \\ \text{=}\frac{\text{8.4432}}{\text{18}鈭�\text{1}} \\ \begin{array}{c}=\frac{\text{8.4432}}{\text{17}}\\ \text{=0.4966}\end{array} \end{gathered}$$

Therefore, the variance is 0.4966.

$\begin{array}{c}\text{Standarddeviation=}\sqrt{\text{Variance}}\\ \text{=}\sqrt{\text{0.4966}}\\ \text{=0.70}\end{array}$

Therefore, the standard deviation is 0.70.