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Question: Impact of race on football card values. Refer to the Electronic Journal of Sociology (2007) study of the Impact of race on the value of professional football players鈥 鈥渞ookie鈥 cards, Exercise 12.72 (p. 756). Recall that the sample consisted of 148 rookie cards of NFL players who were inducted into the Football Hall of Fame (HOF). The researchers modelled the natural logarithm of card price (y) as a function of the following independent variables:

Race:x1=1ifblack,0ifwhiteCardavailability:x2=1ifhigh,0iflowCardvintage:x3=yearcardprintedFinalist:x4=naturallogarithmofnumberoftimesplayeronfinalHOFballotPosition-QB::x5=1ifquarterback,0ifnotPosition-RB:x7=1ifrunningback,0ifnotPosition-WR:x8=1ifwidereceiver,0ifnotPosition-TEx9=1iftightend,0ifnotPosition-DL:x10=1ifdefensivelineman,0ifnotPosition-LB:x11=1iflinebacker,0ifnotPosition-DB:x12=1ifdefensiveback,0ifnot

[Note: For position, offensive lineman is the base level.]

  1. The model E(y)=0+1x1+2x2+3x3+4x4+5x5+6x6+7x7+8x8+9x9+10x10+11x11+12x12 was fit to the data with the following results:R2=0.705,Ra2=0.681,F=26.9.Interpret the results, practically. Make an inference about the overall adequacy of the model.
  2. Refer to part a. Statistics for the race variable were reported as follows:^1=-0.147,s^1=-0.145,t=-1.014,p-value=0.312 .Use this information to make an inference about the impact of race on the value of professional football players鈥 rookie cards.
  3. Refer to part a. Statistics for the card vintage variable were reported as follows:^3=-0.074,s^3=0.007,t=-10.92,p-value=.000.Use this information to make an inference about the impact of card vintage on the value of professional football players鈥 rookie cards.
  4. Write a first-order model for E(y) as a function of card vintage x3and position x5-x12that allows for the relationship between price and vintage to vary depending on position.

Short Answer

Expert verified
  1. The value of R2 is 0.705 indicating that nearly 70% of variation in the data is explained by the model. The value of 68.1% for Ra2 indicates that the variables are explaining the model to a higher degree. At 95% significance level, it can be concluded thatthe model is not a good fit for the data.
  2. At95% significance level,1=0 . Hence it can be concluded with enough evidence that x1 is a significance variable.
  3. At 95% significance level, 3=0. Hence it can be concluded with enough evidence that x2 is a significance variable.
  4. The model is:
  5. Ey=0+1x3+2x5+3x6+4x7+5x8+6x9+7x10+8x11+9x12+10x3x5+11x3x6+12x3x7+13x3x8+14x3x9+15x3x10+16x3x11+17x3x12

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Step by step solution

01

Given Information

The model is given as-Ey=0+1x1+2x2+3x3+4x4+5x5+6x6+7x7+8x8+9x9+10x10+11x11+12x12

Where , R2=0.705andRa2=0.681 .

The statistics for the race variable are given as^1=-0.147,s^1=-0.145,t=-1.014,p-value=0.312 whereas the statistics for the card vintage variable are given as ^3=-0.074,s^3=0.007,t=-10.92,p-value=.000 .

02

Interpretation of results

The results got from the model were:R2=0.705,Ra2=0.681,F=26.9. .

Here, the value of R2 is 0.705 indicating that nearly 70% of variation in the data is explained by the model which is very good number. This denotes that the model is a good fit for the data.

Value of ,Ra2=0.681, which adjusts for the added variables and checks if the added variables is explaining the variation in the model or not. The value of 68.1% indicates that the variables are explaining the model to a higher degree.

F-test statistic value is 26.9, to check the overall adequacy of the model, we conduct the f-test.

H0:1=2=3=0

Ha :At least one of the parameters 1,2,3 is non zero.

H0:is rejected if F statistic >F0.025,147,147.

For =0.025,F0.025,147,147=1.311. Since , there is sufficient evidence to reject

Hence the model is not a good fit for the data.

03

 Step 3: Significance of  β1

b.

Here,

H0:1=0Ha:10

t-test statistic=^1s^1=-0.1470.145=-1.0137

Value of t0.025,147is 1.98

Ho: is rejected if t statistic>t0.05,24,24 .

For =0.025, since t<t0.025,147

Not sufficient evidence to reject at 95% confidence interval.

Therefore, 1=0. Hence it can be concluded with enough evidence that x1 is a significant variable.

04

Significance of  β2 

c.

H0:3=0Ha:30

Here,

t-teststatistic=^3s^3=-0.0740.007=-10.57

Value of t0.025,147 is 1.98

H0 is rejected if t statistic >t0.05,24,24. For =0.025, since t<t0.025,147

Not sufficient evidence to reject H0 at 95% confidence interval.

Therefore,3=0. Hence it can be concluded with enough evidence that x3 is a significant variable.

05

Model equation

d.

To write a first-order model for E(y) as a function of card vintage x3 and position x5-x12 that allows the relationship between price and vintage to vary depending on the position can be expressed by an interaction model.

The equation can be written as:

.Ey=0+1x3+2x5+3x6+4x7+5x8+6x9+7x10+8x11+9x12+10x3x5+11x3x6+12x3x7+13x3x8+14x3x9+15x3x10+16x3x11+17x3x12

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Most popular questions from this chapter

Question: Performance ratings of government agencies. The U.S. Office of Management and Budget (OMB) requires government agencies to produce annual performance and accounting reports (PARS) each year. A research team at George Mason University evaluated the quality of the PARS for 24 government agencies (The Public Manager, Summer 2008), where evaluation scores ranged from 12 (lowest) to 60 (highest). The accompanying file contains evaluation scores for all 24 agencies for two consecutive years. (See Exercise 2.131, p. 132.) Data for a random sample of five of these agencies are shown in the accompanying table. Suppose you want to conduct a paired difference test to determine whether the true mean evaluation score of government agencies in year 2 exceeds the true mean evaluation score in year 1.

Source: J. Ellig and H. Wray, 鈥淢easuring Performance Reporting Quality,鈥 The Public Manager, Vol. 37, No. 2, Summer 2008 (p. 66). Copyright 漏 2008 by Jerry Ellig. Used by permission of Jerry Ellig.

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