/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q-8-56E Angioplasty鈥檚 benefits are cha... [FREE SOLUTION] | 91影视

91影视

Angioplasty鈥檚 benefits are challenged. Further, more than 1 million heart cases each time suffer an angioplasty. The benefits of an angioplasty were challenged in a study of cases (2007 Annual Conference of the American. College of Cardiology, New Orleans). All the cases had substantial blockage of the highways but were medically stable. All were treated with drugs similar to aspirin and beta-blockers. Still, half the cases were aimlessly assigned to get an angioplasty, and half were not. After five years, the experimenter planted 211 of the. Cases in the angioplasty group had posterior heart attacks compared with 202 cases in the drug-only group. Do you agree with the study鈥檚 conclusion? 鈥淭here was no significant difference in the rate of heart attacks for the two groups鈥? Support your answer with a 95-confidence interval.

Short Answer

Expert verified

There is insufficient evidence to indicate that () differs from 0 because the interval includes 0 as a possible value for().

Step by step solution

01

Find the value of P1 and P2

The two samples represent independent binomial trials. The arbitrary binomial variables are the figures and of the 1145 and 1142 cases in the angioplasty group and drug-only group, respectively.

The results are epitomized in the table over.

We now calculate the sample proportions and. Of the dropouts in the 1st and 2nd group Independently.

P1= == 0.1843

P2= == 0.1769

02

Difference between the drop rate of two group

A large sample 95% confidence interval for the difference (P1 - P2) between the drop rates of the two groups of exercisers is given by

(P1-P2)Za2(p1-p2)P1-P2)Za2P1q1n1+P2q2n2

Substituting the sample quantities yields

0.01843-0.17691.960.18430.81571145+0.17690.82311142

(0.1843 鈥 0.1769) 1.96

- 0.00740.03153

(- 0.02413, - 0.03893)

03

Confident intervals

The interval can be interpreted as follows:

With a confidence coefficient equal to 0.95, we estimate that the difference in the rate of the heart attacks between the cases in the angioplasty group and the cases in the medication-only group falls in the interval from -0.02431 to 0.03893.

In other words, we estimate (with 95% confidence) the rate of heart attack for the medication-only group to be anywhere from 2.413% less than to 3.893% more than the heart attack rate for the angioplasty group.

04

Final answer

There is insufficient evidence to indicate that () differs from 0 because the interval includes 0 as a possible value for().

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Bankruptcy effect on U.S. airfares. Both Delta Airlines and USAir filed for bankruptcy. A study of the impact of bankruptcy on the fares charged by U.S. airlines was published in Research in Applied Economics (Vol. 2, 2010). The researchers collected data on Orlando-bound airfares for three airlines鈥擲outhwest (a stable airline), Delta (just entering bankruptcy at the time), and USAir (emerging from bankruptcy). A large sample of nonrefundable ticket prices was obtained for each airline following USAir鈥檚 emergence from bankruptcy, and then a 95% confidence interval for the true mean airfare was obtained for each. The results for 7-day advance bookings are shown in the accompanying table.

a. What confidence coefficient was used to generate the confidence intervals?

b. Give a practical interpretation of each of the 95% confidence intervals. Use the phrase 鈥95% confident鈥 in your answer.

c. When you say you are 鈥95% confident,鈥 what do you mean?

d. If you want to reduce the width of each confidence interval, should you use a smaller or larger confidence coefficient?

4.134 Refer to Exercise 4.133. Find the following probabilities:

a.P(20x30)b.P(20<x30)c.P(x30)d.P(x45)e.(x40)f.(x<40)g.P(15x35)h.P(21.5x31.5)

Homework assistance for accounting students. How much assistance should accounting professors provide students for completing homework? Is too much assistance counterproductive? These were some of the questions of interest in a Journal of Accounting Education (Vol. 25, 2007) article. A total of 75 junior-level accounting majors who were enrolled in Intermediate Financial Accounting participated in an experiment. All students took a pretest on a topic not covered in class; then, each was given a homework problem to solve on the same topic. However, the students were randomly assigned different levels of assistance on the homework. Some (20 students) were given the completed solution, some (25 students) were given check figures at various steps of the solution, and the rest (30 students) were given no help. After finishing the homework, each student was given a posttest on the subject. One of the variables of interest to the researchers was the knowledge gain (or test score improvement), measured as the difference between the posttest and pretest scores. The sample means knowledge gains for the three groups of students are provided in the table.

a. The researchers theorized that as the level of homework assistance increased, the test score improvement from pretest to post test would decrease. Do the sample means reported in the table support this theory?

b. What is the problem with using only the sample means to make inferences about the population mean knowledge gains for the three groups of students?

c. The researchers conducted a statistical test of the Hypothesis to compare the mean knowledge gain of students in the "no solutions" group with the mean knowledge gain of students in the "check figures" group. Based on the theory, part a sets up the null and alternative hypotheses for the test.

d. The observed significance level of the t-test of the partc was reported as8248 Using =.05, interpret this result.

e. The researchers conducted a statistical test of the hypothesis to compare the mean knowledge gain of students in the "completed solutions" group with the mean knowledge gain of students in the "check figures" group. Based on the theory, part a sets up the null and alternative hypotheses for the test.

f. The observed significance level of the role="math" localid="1652694732458" t-test of part e was reported as 1849. Using =.05, interpret this result.

g. The researchers conducted a statistical test of the Hypothesis to compare the mean knowledge gain of students in the "no solutions" group with the mean knowledge gain of students in the "completed solutions" group. Based on the theory, part a sets up the null and alternative hypotheses for the test.

h. The observed significance level of the t-test of the part wasg reported as2726. Using role="math" localid="1652694677616" =.05, interpret this result.

Question: Summer weight-loss camp. Camp Jump Start is an 8-week summer camp for overweight and obese adolescents. Counselors develop a weight-management program for each camper that centers on nutrition education and physical activity. To justify the cost of the camp, counselors must provide empirical evidence that the weight-management program is effective. In a study published in Paediatrics (April 2010), the body mass index (BMI) was measured for each of 76 campers both at the start and end of camp. Summary statistics on BMI measurements are shown in the table.

Source: Based on J. Huelsing, N. Kanafani, J. Mao, and N. H. White, "Camp Jump Start: Effects of a Residential Summer Weight-Loss Camp for Older Children and Adolescents," Pediatrics, Vol. 125, No. 4, April 2010 (Table 3).

a. Give the null and alternative hypotheses for determining whether the mean BMI at the end of camp is less than the mean BMI at the start of camp.

b. How should the data be analyzed, as an independent samples test or as a paired difference test? Explain.

c. Calculate the test statistic using the formula for an independent samples test. (Note: This is not how the test should be conducted.)

d. Calculate the test statistic using the formula for a paired difference test.

e. Compare the test statistics, parts c and d. Which test statistic provides more evidence in support of the alternative hypothesis?

f. The p-value of the test, part d, was reported as p 6 .0001. Interpret this result, assuming a = .01.

g. Do the differences in BMI values need to be normally distributed in order for the inference, part f, to be valid? Explain.

h. Find a 99% confidence interval for the true mean change in BMI for Camp Jump Start campers. Interpret the result.

Vulnerability of counting party Web spots. When you subscribe to your Facebook account, you're granted access to further. Then 1 million counting parties (RP) Web spots. Vulnerabilities in this sign-on system may permit a bushwhacker to gain unauthorized access to your profile, allowing the bushwhacker to impersonate you on the RP Web point. Computer and systems Masterminds delved into the vulnerability of counting party Web spots and presented their results at the Proceedings of the 5th AMC Factory on Computers & Communication Security (October 2012). RP Web spots were distributed as Gar莽on- inflow or customer- inflow Web spots. Of the 40 gar莽on- inflow spots studied, 20 were planted to be vulnerable to impersonation attacks. Of the 54 customer-inflow spots examined, 41 were. Plant to be vulnerable to impersonation attacks. Give your opinion on whether a customer- inflow Web point is more likely to be vulnerable to an impersonation attack than a gar莽on- inflow Website. However, how much more likely? If so.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.